Download A weightlifter lifts a set of weights a vertical distance of 2.00 m. If a

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A weightlifter lifts a set of weights a vertical distance of 2.00 m. If a constant net
force of 350 N is exerted on the weights, what is the net work done on the weights?
Solution:
d = 2.00m − vertical distance;
F = 250N − net force;
The work done by a constant force of magnitude F on a point that moves a
displacement d in the direction of the force is the product
W = F ∙ d = 2m ∙ 250N = 500J
Answer: net work done on the weights is 500J.
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