Download Ch. 6 Calculation Worksheet: F =ma 1. A mass = 200

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Ch. 6 Calculation Worksheet: F =ma
1.
A mass = 200 kg is accelerated at 3.5 m/s2. Calculate the force required.
Given
m = 200 kg a = 3.5 m/s2
Find
F
Equation
F = ma
Solve
F = 200 kg x 3.5 m/s2 = 700 N‐ 2.
Two boys push a cart accelerating at a rate of 2 m/s2. If the boys exert a force = 450 N, what was the mass of the cart?
Given
F = 450 N a = 2 m/s2
Find
m
Equation m = F/a
Solve
m = 450 N ÷ 2 m/s2 = 225 kg‐ 3.
A 375 N force is exerted on a 125 kg mass. Calculate acceleration. Given
F = 375 N m = 125 kg
Find
a
Equation a = F/m
Solve
a = 375 N ÷ 125 kg = 3 m/s2 ‐ 4.
An applied force = 400 N is exerted on a rolling cart that has a mass = 125 kg. If the frictional force = 50 N, at what rate did the car accelerate?
Given
Fapplied = 400 N Ffrictional = 50 N m = 125 kg
Find
a
Equation
a = Fapplied ‐ Ffrictional /m
Solve
a = (400 N ‐ 50 N ) ÷ 125 kg = 2.8 m/s2 ‐ 5.
A 40 kg mass is accelerated from rest to reach a final velocity = 100 m/s. It accelerates for a time = 25 s. Calculate the force required.
Given
v initial = 0 m/s v final = 100 m/s t= 25 s m = 40 kg
Find
F
Equation
F = m (Vf ‐ Vi) t
Solve
F = 40 kg (100 m/s ‐ 0 m/s ) = 160 N ‐ 25 s
6.
A 650 N force is exerted on a 40 kg mass. Calculate the acceleration.
Given
v i = 0 m/s v f = 100 m/s t= 25 s m = 40 kg
Find
a
Equation
F = m (Vf ‐ Vi) Solve
F = 40 kg (100 m/s ‐ 0 m/s ) = 160 N ‐ 25 s
7.
An applied force on a box causes it to accelerate at a rate of 4 m/s2. If the applied force is doubled but the mass of the mass is reduced to half of its original mass, what is the new rate of acceleration?
Given
a = 4 m/s2 Find
a where F is doubled and m is reduced to half the original
Equation
a = F/m
Solve
(1)
Develop an equation in which a = 4 m/s2.
(2)
4 m/s2 = 8 N ÷ 2 kg (3) double the force and reduce mass to half the original mass
(4) a = 16 N ÷ 1 kg a = 16 m/s2
8.
A 375 N FORCE is exerted from the RIGHT and a 900 N force is exerted on the LEFT on an object with a MASS = 125 kg. Calculate ACCELERATION.
Given
F1 = 375 N F2 = 900 N m = 125 kg
Find
a
Equation
a = (F2 ‐ F1) m
Solve
a = (900 N ‐ 375 N) 125 kg F = 65625 N‐
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