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Subject: MDM4UI Topic: The Normal Distribution (1) Unit: 6.5 Homework: Page 176 1, 3b, 6, 9a Objective: To look at the most famous distribution curve. Notes: Normal distributions are symmetrical and approach zero at the extremes Of the data, 68% is within one standard deviation of the mean, 95% is within two standard deviations of the mean, and 99.7% is within three standard deviations of the mean. The mean, median, and mode are all equal and fall on the line of symmetry of the distribution The area under any normal curve is 1. The percent of the data that lies between two values in a normal distribution is equivalent to the area under the normal curve between these values. The notation used to describe a normal distribution, of the variable X, is X ∼ N ( x , σ 2 ) . Examples: Giselle is 168cm tall. In her high school, boys’ heights are normally distributed with a mean of 174cm and a standard deviation of 6cm. What is the probability that the first boy Giselle meets at school tomorrow will be taller than she is? Solution: We need to find the probability that the height of the first boy falls into a certain range. The normal distribution is a continuous curve, so the probability is the area under the appropriate part of the probability-distribution curve. Giselle’s Height 6 168 174 The shaded red colour represents the P(168<Boys height) We need to find P(168< boy’s height). For this distribution, 168 = µ − σ . So, you can use the fact that, for any normally distributed random variable X, P ( µ − σ < X < µ + σ ) 68% Since 168 is exactly one standard deviation (6) form 174, the are under curve between 168 and 174 is 34%. The are under curve from 174 to infinity is 50&. Therefore the red area is 84%. The probability is 84%.