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Quadratic factorisation - Two algorithms Type 1 x2 + bx + c Example 1 x2 + 5x + 6 Find a pair of numbers with product (+6) and sum (+5) (+3) and (+2) x2 + 5x + 6 (x + 3)(x + 2) Example 2 x2 - x - 2 Find a pair of numbers with product (-2) and sum (-1) (-2) and (+1) x2 - x - 2 (x - 2)(x + 1) Example 3 x2 - 7x + 12 Find a pair of numbers with product (+12) and sum (-7) (-3) and (-4) x2 - 7x + 12 (x - 3)(x - 4) Example 4 x2 - 4 Find a pair of numbers with product (-4) and sum (0) (-2) and (+2) x2 - 4 (x - 2)(x + 2) Try these 1. x2 + 7x + 12 2. x2 + x - 2 3. x2 - 9x + 20 4. x2 - 9 5. x2 - 25 6. x2 - 2x - 8 7. x2 + 7x + 10 8. x2 - 8x + 15 © www.teachitmaths.co.uk 2016 25751 Page 1 of 4 Quadratic factorisation - Two algorithms Type 2 ax2 + bx + c Example 1 6x2 + 5x – 6 • Multiply a by c 6 x (-6) = -36 • Find a pair of numbers with product (-36) and sum b, +5 9 and (-4) • Write as 9x and -4x • Replace 5x by 9x and -4x, in either order • Factorise the red pair and the blue pair • Factorise by the bracket 6x2 + 9x - 4x – 6 3x(2x + 3) – 2(2x + 3) 6x2 + 5x – 6 = (2x + 3)(3x – 2) If in the other order at step 4…. 6x2 - 4x + 9x – 6 2x(3x - 2) + 3(3x - 2) 6x2 + 5x – 6 = 3x – 2) (2x + 3) Example 2 12x2 + x – 1 • 12 x (-1) = (-12) • product (-12) and sum 1 4 and -3 4x and -3x • 12x + 4x – 3x – 1 2 • 4x(3x + 1) -1(3x + 1) • 12x2 + x – 1 = (3x + 1)(4x – 1) Example 3 4x2 + 7x + 3 • 4 x 3 = 12 • product 12 and sum 7 3 and 4 3x and 4x • 4x + 3x + 4x + 3 2 • x(4x + 3) + 1(4x + 3) • 4x2 + 7x + 3 = (4x + 3)(x + 1) © www.teachitmaths.co.uk 2016 25751 Page 2 of 4 Quadratic factorisation - Two algorithms Example 4 4x2 – 9 • 4 x (-9) = (-36) • product (-36) and sum 0 6 and -6 6x and -6x • 4x2 + 6x – 6x – 9 • 2x(2x + 3) -3(2x + 3) • 4x2 – 9 = (2x + 3)(2x – 3) Short cut: a2 - b2 = (a - b)(a + b). 4x2 – 9 a = 2, b = 3 (2x + 3)(2x – 3) Try these 1. 6x2 + 7x + 2 2. 2x2 + x - 3 3. 3x2 - 5x - 2 4. 9x2 - 4 5. 10x2 + x - 2 6. 3x2 + 10x + 3 © www.teachitmaths.co.uk 2016 25751 Page 3 of 4 Quadratic factorisation - Two algorithms Solutions Type 1 1. x2 + 7x + 12 = (x + 4)(x + 3) 2. x2 + x - 2 = (x - 1)(x + 2) 3. x2 - 9x + 20 = (x - 4)(x - 5) 4. x2 - 9 = (x - 3)(x + 3) 5. x2 - 25 = (x - 5)(x + 5) 6. x2 - 2x - 8 = (x - 4)(x + 2) 7. x2 + 7x + 10 = (x + 2)(x + 5) 8. x2 - 8x + 15 = (x - 3)(x - 5) Type 2 1. 6x2 + 7x + 2 = (2x + 1)(3x + 2) 2. 2x2 + x - 3 = (x - 1)(2x + 3) 3. 3x2 - 5x - 2 = (3x + 1)(x - 2) 4. 9x2 - 4 = (3x - 2)(3x + 2) 5. 10x2 + x - 2 = (5x - 2)(2x + 1) 6. 3x2 + 10x + 3 = (3x + 1)(x + 3) © www.teachitmaths.co.uk 2016 25751 Page 4 of 4