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19. Derivative of sine and cosine Derivative of sine and cosine Two trigonometric limits 19.1. Two trigonometric limits Statement Examples The rules for finding the derivative of the functions sin x and cos x depend on two limits (that are used elsewhere in calculus as well): Two trigonometric limits. (a) lim θ→0 sin θ = 1, θ cos θ − 1 (b) lim = 0. θ→0 θ The verification we give of the first formula is based on the pictured wedge of the unit circle: Table of Contents JJ II J I Page 1 of 7 Back Print Version Home Page Derivative of sine and cosine Two trigonometric limits Statement Examples The segment tagged with sin θ has this length by the definition of sin θ as the y-coordinate of the point P on the unit circle corresponding to the angle θ. The line segment tagged with tan θ has this length since looking at the large triangle, we have tan θ = o/a = o. The arc tagged with θ has this length by the definition of radian measure of an angle. The diagram reveals the inequalities sin θ < θ < tan θ. The first inequality implies (sin θ)/θ < 1; the second says θ < (sin θ)/(cos θ), implying that cos θ < (sin θ)/θ. Therefore, sin θ < 1. cos θ < θ As θ goes to 0, both ends go to 1 forcing the middle expression to go to 1 as well (by the squeeze theorem). This establishes (a). Table of Contents JJ II J I Page 2 of 7 Back Print Version Home Page For the second formula, we use a method that is similar to our rationalization method, as well as the main trigonometric identity, and finally the first formula: cos θ − 1 cos θ − 1 cos θ + 1 = lim · θ→0 θ→0 θ θ cos θ + 1 cos2 θ − 1 = lim θ→0 θ(cos θ + 1) lim − sin2 θ θ→0 θ(cos θ + 1) sin θ sin θ = − lim · θ→0 θ cos θ + 1 sin θ sin θ · lim = − lim θ→0 θ θ→0 cos θ + 1 = −1 · 0 = 0. Derivative of sine and cosine Two trigonometric limits Statement Examples = lim Table of Contents JJ II J I This completes the verification of the two trigonometric limit formulas. 19.2. Statement Page 3 of 7 Derivative of sine and cosine. d (a) [sin x] = cos x, dx d (b) [cos x] = − sin x. dx Back Print Version Home Page We verify only the first of these derivative formulas. With f (x) = sin x, the formula says f 0 (x) = cos x: f (x + h) − f (x) h→0 h sin(x + h) − sin x = lim h→0 h (sin x cos h + cos x sin h) − sin x = lim h→0 h cos h − 1 sin h = lim sin x · + cos x · h→0 h h cos h − 1 sin h = sin x · lim + cos x · lim h→0 h→0 h h = sin x · 0 + cos x · 1 Derivative of sine and cosine Two trigonometric limits Statement f 0 (x) = lim Examples ((4) of 4.3) Table of Contents ((b) and (a)) = cos x. The formula says that f (x) = sin x has general slope function f 0 (x) = cos x, so the height of the graph of the cosine function at x should be the slope of the graph of the sine function at x. The following figures show this relationship for x a multiple of π/2. JJ II J I Page 4 of 7 Back Print Version Home Page Derivative of sine and cosine Two trigonometric limits Statement Examples Table of Contents 19.3. Examples 19.3.1 Solution Example JJ II J I Page 5 of 7 Find the derivative of f (x) = 3 cos x + 5 sin x. Back We use the rules of this section after first applying the sum rule and the constant Print Version Home Page Derivative of sine and cosine multiple rule: d [3 cos x + 5 sin x] dx d d = 3 [cos x] + 5 [sin x] dx dx = 3(− sin x) + 5(cos x) Two trigonometric limits f 0 (x) = Statement Examples = −3 sin x + 5 cos x. 19.3.2 Example line has slope 1/2. Find all points on the graph of f (x) = sin x at which the tangent Table of Contents 0 Solution The general slope function for this function is its derivative, which is f (x) = cos x. We get the x-coordinates of the desired points by solving f 0 (x) = 1/2, that is, cos x = 1/2. Picturing the unit circle and using the 30-60-90 triangle we find that x = π/3 (60◦ ) in the first quadrant yields a cosine of 1/2, as does x = −π/3 in the fourth quadrant. A multiple of 2π added to these angles produces the same cosine. JJ II J I Therefore, the x-coordinates of the desired points are Page 6 of 7 π/3 + 2πn, −π/3 + 2πn (n any integer). √ The y-coordinate corresponding to x = π/3 is f (π/3) = sin(π/3) = 3/2 and this is also the y-coordinate corresponding to x =√π/3 + 2πn for any n. Similarly, the y-coordinate corresponding to x = −π/3 + 2πn is − 3/2. The desired points are √ √ (π/3 + 2πn, 3/2), (−π/3 + 2πn, − 3/2) (n any integer). Back Print Version Home Page Derivative of sine and cosine 19 – Exercises Two trigonometric limits Statement 19 – 1 Find all points on the graph of f (x) = cos x at which the tangent line has slope √ Examples 3/2. Table of Contents JJ II J I Page 7 of 7 Back Print Version Home Page