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Name ________________________________ Date ____________________ CC Algebra II Algebra II Review Factoring & Solving Quadratics Methods to Factor Quadratic Equations Factoring Trinomials Quadratic Formula x2 + (a + b)x + (ab) ο (x + a)(x + b) Compare to ax2 + bx + c and substitute Completing The Square π 2 π 2 ax2 + bx + (2) = c + (2) Now I can factor the trinomial as explained in the first column, or using the difference of two squares. What multiplies to the third term and adds to the middle term? I.) Match the following quadratics with their roots: _____ x2 + 10x + 11 a. x = -11, 1 _____ x2 + 10x β 11 b. x = 3, 7 _____ x2 β 10x + 11 c. x = β5 ± β14 _____ x2 β 10x β 11 d. x = 5 ± β14 _____ (x - 5)2 = 4 e. x = 11, -1 II. Solve by Factoring 1.) x2 β 64 = 0 2.) x2 β 6x β 16 = 0 3.) x2 + 3x = 40 4.) 2 x 2 ο« 3x ο« 1 ο½ 0 5.) x² β 100 = 0 6.) x² + 6x = 0 III. Solve by using the quadratic formula: 7.) x² + 3x + 2 = 0 8.) 4x² β 8x = 1 9.) x² + 8x = 0 IV. Solve each equation any way you want. Show your work. 10.) x2 + 11x + 18 = 0 11.) x2 + 2x + 1 = 15 12.) 7x2 β 9x +1 = 0 13.) (x + 2)² = 36 14.) 3π₯2β9π₯ = β6 16.) (π₯2 β 2π₯ β 4)(3π₯2 + 8π₯ β 3) = 0. VI. REASONING: 18.) Explain why x² = -81 DOES NOT have a solution. 15.) x² β 6x + 2 = 0 17.) (2π₯2 β5π₯+2)(3π₯2 β4π₯+1) = 0 19.) Which method canβt you use to solve this problem? x² β 47 = 0 Circle one: Factoring Square Roots Quadratic Formula Explain why: 20.) Which method canβt you use to solve this problem? x² + 7x = 0 Circle one: Quadratic Formula Factoring Square Roots Explain why: 21.) Which method can you use to solve all quadratic equations? Circle one: Factoring Square Roots Quadratic Formula Explain why: 22.) What are the two mistakes in setting up the quadratic formula: Solve: 2x² β x β 6 = 0 ο 1 ο± (ο1) 2 ο 4(2)(6) xο½ 2(2) 23.) Solve this quadratic equation ALL three ways. Make sure you get the same answers! π₯ 2 β 8π₯ = 9 FACTORING COMPLETING THE SQUARE QUADRATIC FORMULA 24.) Use any method youβd like to solve. Remember, not all quadratics can be factored! π₯ 2 + 4π₯ β 8 = 0 π₯ 2 + 8π₯ + 16 = 0