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Transcript
Combustion Chemistry
Hai Wang
University of Southern California
2013 Tsinghua-Princeton Summer School On Combustion
Course Length: 3 hrs/day
July 7 – 12, 2013
Copyright © 2013 by Hai Wang
1
This material is not to be sold, reproduced or distributed without prior written permission of the owner, Hai Wang.
Background 1
http://en.wikipedia.org/wiki/File:Bunsen_burner_flame_types_.jpg
2
Background 2
• Combustion usually involves the oxidation of a
(hydrocarbon CmHn) fuel to form oxidation
products. Heat is released in the process.
• For complete combustion, the global reaction
in air can be expressed as, e.g.,
– CmHn + (m+n/4) O2 + (79/21)x(m+n/4) N2 
mCO2 + (n/2) H2O + (79/21)x(m+n/4) N2 + Q
• The above equation is balanced on a molar
basis (per mole of the fuel).
3
Background 3
• Actual reaction proceeds through a series of
simultaneous elementary reactions resulting
from collision of two species.
• Some of these species are molecules while
others are unstable free-radicals.
4
Background 4
• Combustion chemistry involves a study
of elementary reaction processes
–Individually: fundamental reaction kinetics
–collectively: reaction mechanisms and
models
5
Background 5
• The end goal is to be able to predict
– Local heat release rate
– Ignition
– Flame propagation and extinction
– Coupled chemistry and fluid mechanics in flames
– Pollutant (e.g., unburned HC, NOx and soot)
formation
– ……
6
Background 4
• The lecture series
– Reviews the basic principles of thermodynamics and
statistical mechanics
– Discusses the nature of chain reaction mechanisms
– Present simple theories of elementary chemical
reactions
– Explore the application of combustion chemistry in
combustion studies
– Present several special topics in combustion chemistry
research
7
Background 5
• This series of lecture is linked to those given in
the prior years
– 2012 Michael Pilling
• But it emphasizes the very fundamental
knowledge and application of the knowledge
in your work
8
Thermodynamics
James Watt
Sati Carnot
James Prescott Joule
Rudolf J. E. Clausius
William Thomson Kelvin J Willard Gibbs
Hermann von Helmholtz
9
Thermodynamics
• Describes the driving force of a
chemical process.
• Determines the ideal end state of a
reaction process.
• The very foundation of chemical
kinetics/combustion chemistry.
10
The First Law 1
• Energy is conserved:
Q − W = U
For a working fluid in a closed system, the heat (Q) it
receives from the surrounding minus the work (W) it
performs on the surrounding is equal to the change in
its internal energy.
• Q > 0 – receive heat from the surrounding
(endothermic)
Q < 0 – give off heat to the surrounding (exothermic).
11
The First Law 2
• The energy in the three forms may be
transformed from one to another without
limits – we know something is wrong here.
• Measured by J, kJ, cal or kcal.
• Internal energy is the total energy of
molecules in the working fluid – a sum of
kinetic and potential energies.
12
The First Law 3
• If only boundary work is done (e.g., gas expansion)
under a constant pressure p,
the first law may be re-written as
where V is the volume, and the subscripts “1” and
“2” represent the starting and ending states.
• We define enthalpy as
13
Extensive versus Intensive Properties
• Extensive: U, H, Q and W (J); V (cm3)
• Intensive: u, h, q, w (J/mol or cal/mol)
v, p, T (cm3/mol)
• Thermodynamic properties are state functions
• A state is usually defined by two independent
intensive variables – e.g., (p, T), (p, v), (h, T)
etc.
• Equation of state – ideal gas
where Ru is the universal gas constant (8.314
J/mol-K)
14
Two More Intensive Properties
• Specific heats:
– Constant volume:
– Constant pressure:
• For an ideal gas, h = h(T), u = u(T) etc
15
Second Law and Entropy
• The Kelvin-Planck statement:
It is impossible to construct a device that will operate in
a cycle and produce no effect other than the raising of a
weight and the exchange of heat with a single reservoir.
• Entropy
where (Q)int rev is the heat a working fluid receives
during an infinitesimal, reversible process.
16
Entropy
• A measure of molecular randomness
• Ssolid < Sliquid < Sgas
• For closed system, a spontaneous process
(from 1 to 2) must have S2 – S1 ≥ 0
• That is, randomness always increase (a desk
never cleans itself, cloths never fold
themselves etc).
• S increases as T , but decreases with p
• The third law: S = 0 at 0 K.
17
S(T,P)
• Apply the first law to a reversible constant T,P
(piston) process
Ideal gas law
S(T,P)
Standard-state entropy (1 atm)
Po is the standard pressure of 1 atm
19
Three forms of enthalpy
•
•
•
•
Sensible – heating/cooling
Latent – melting, evaporation/condensation
Reaction – due to chemical composition change
Enthalpy of formation
– the heat released from producing 1 mole of a substance
from its elements at a constant temperature T
– the enthalpy of formation is zero for the reference
elements: graphite C(S), hydrogen H2, oxygen (O2),
nitrogen (N2), and chlorine (Cl2).
– C(S) + O2  CO2 + Q (= 393.522 kJ @298 K),
hf,298K = 393.522 kJ/mol of CO2
20
Enthalpy of formation
21
Enthalpy of formation varies with T
Generalize to
22
Total Enthalpy
23
Enthalpy of Reaction/Combustion
• Standard enthalpy of combustion
– Heat released from complete combustion of 1
mole of a fuel
24
Enthalpy of Reaction/Combustion
For a generalized combustion reaction
The heat of combustion is
For a generalized chemical reaction
The heat (enthalpy) of reaction is
DH r ,T
ìï
üï
= DH r ,298 + í å n i ' éëh (T ) - h (298)ùû - å n i éëh (T ) - h (298)ùû ý
i'
i
ïî prod.
react.
ï
25þ
Chemical Equilibrium
• Compare
The first reaction gives greater heat release, but
the second reaction produces more entropy.
So, how does the reaction know when to stop?
26
Chemical Equilibrium
Gibbs free energy defines the compromise
Equilibrium is found when dG/dε = 0
Equilibrium Constant
• Quantify equilibrium
• Consider the generic reaction
• Keep in mind that during an equilibration
process, reactants/products co-exist
where ni and ni’ are the number of moles of the
ith reactant and i’th product, respectively
28
Equilibrium Constant
• For equilibrium at constant T & P, we have
• Mass conservation requires
Cannot be zero
29
Standard Gibbs Free Energy
é
æP
g i (T , P ) = h f (T ) - Tsi (T ) = h f (T ) - T ê si ( T ) - R u ln ç
èP
ë
æPö
= h f (T ) - Tsi (T ) + R uT ln ç ÷
èP ø
Standard Gibbs free energy (T, po = 1 atm)
and then,
öù
÷ø ú
û
Back to Equilibrium Constant
Gibbs free energy of reaction
Rearrange to give
or the equlibrium constant
Note Kp is a function of temperature only
31
Equilibrium Constant
The equilibrium constant may also be defined by concentrations
where
Note Kc can be a function of pressure
32
About Equilibrium Constant
• Kp is a function of temperature only
• Forward/backward equilibrium constant
33
About Equilibrium Constant
• Alternatively, for
• The larger the equilibrium constant, the
greater the completion of a reaction
34
About Equilibrium Constant
35
Adiabatic Flame Temperature
Reactants
(P, T0)
Adiabatic Reactor
(P)
Products
(P, Tad)
Adiabaticity gives
Let T0 = 298 K
i.e., heat of combustion is used entirely to raise the
temperature of the products
36
Adiabatic Flame Temperature
37
Adiabatic Flame Temperature
Effect of Pressure
38
Equilibrium Composition
Effect of Pressure
39
Thermochemical Properties
40
Thermochemical Properties
The NASA Polynomials
41
Thermochemical Properties
• Alex Burcat’s compilation (Elke Goos)
http://garfield.chem.elte.hu/Burcat/burcat.html
• Active tables (Ruscic)
42