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LECTURE 16 CAPACITORS Instructor: Kazumi Tolich Lecture 16 2 ¨ Reading chapter 20.5 & 20.6 ¤ Capacitance ¤ Parallel-plate capacitor ¤ The storage of electrical energy ¤ Dielectrics Capacitors 3 ¨ ¨ ¨ A capacitor is a device consisting of two conductors: one conductor with charge 𝑄, and the other with charge −𝑄. The symbol for a capacitor in a circuit diagram is The capacitance of the capacitor is defined as 𝑄 𝐶= 𝑉 Quiz: 1 4 ¨ A capacitor of capacitance 𝐶 holds a charge 𝑄 when the potential difference across the plates is 𝑉 . If the charge on the plates is doubled to 2𝑄 , what is the capacitance of the capacitor now? Quiz: 16-1 answer 5 ¨ ¨ ¨ 𝐶 The capacitance is a function of geometry only. The geometry did not change, so the capacitance did not change. You might think that capacitors depend on charge and potential difference by looking at the ' definition of capacitance: 𝐶 = . However, the charge a capacitor store is proportional to the ( potential difference. And that proportionality constant is the capacitance, 𝑉 = 𝐶𝑄. The slope 𝐶 is independent of the value of 𝑄. Parallel plate capacitors/Demo: 1 6 ¨ The electric field between the plates is uniform and given by 𝐸= ¨ 𝑄 𝜖+ 𝐴 The potential difference between the plates is given by ∆𝑉 = 𝐸𝑑 = ¨ The capacitance of a parallel-plate capacitor is 𝐶= ¨ 𝑄𝑑 𝜖+ 𝐴 𝜖+ 𝐴 𝑑 Demo: variable capacitors (tuning capacitor used in AM radios) Quiz: 2 7 ¨ Suppose a parallel plate capacitor is fully charged by a battery and then disconnected from the battery. The positive plate has a charge + 𝑞 and the negative plate has a charge −𝑞. The plate separation is doubled from its initial separation. How did the potential between the plates change? A. B. C. Remained the same. Doubled Halved Quiz: 16-2 answer 8 ¨ ¨ ¨ ¨ Doubled ∆𝑉 = 𝐸𝑑 Since the capacitor is isolated, the amount of charge does not change. So, 𝐸 is constant. Dielectrics 9 ¨ ¨ If we place a non-conducting dielectric material between the plates of a capacitor, molecules within can be polarized. The capacitance with a dielectric installed is increased and given by 𝐶 = 𝜅𝐶+ where 𝐶+ is the capacitance without any dielectric, and 𝜅 is the dielectric constant. ¤ The dielectric constant is a property of the material. ¤ 𝜅 of air is very close to 1 (close to vacuum). Quiz: 3 10 ¨ A charge 𝑄 is placed on a plate of an isolated parallel-plate capacitor, and −𝑄 is placed on the other plate. The voltage across the plates is 𝑉. Now a dielectric material with a dielectric constant 𝜅 > 1 is inserted between the plates without touching them. Has the potential difference between the plates increased, decreased, or stayed the same? A. B. C. Increased Decreased Stayed the same Quiz: 16-3 answer/Demo: 2 11 ¨ Decreased. Since the capacitor is isolated, the amount of charge on the capacitor does not change. The capacitance increases to 𝐶 = 𝜅𝐶+ . ¨ 𝐶 = , so the voltage must decrease. ¨ 𝑉= ¨ ¨ ' ( (4 5 Quiz: 4 12 ¨ A parallel-plate capacitor is connected to an ideal battery. A charge 𝑄 is on a plate, and −𝑄 is on the other plate. Now a dielectric material with a dielectric constant 𝜅 > 1 is inserted between the plates without touching them. Has the amount of charge stored on the plate with a positive charge increased, decreased, or stayed the same? A. B. C. Increased Decreased Stayed the same Quiz: 16-4 answer 13 ¨ increased. Since the capacitor is connected to a battery, the potential difference across the capacitor remains constant, the voltage of the battery. The capacitance increases to 𝐶 = 𝜅𝐶+ . ¨ 𝐶 = , so the charge must increase. ¨ ¨ ' ( Example: 1 14 ¨ A parallel-plate capacitor is constructed with circular plates of radius r = 0.056 m. The plates are separated by d = 0.25 mm, and the space between the plates is filled with a dielectric with dielectric constant κ. When the charge on the capacitor is Q = 1.2 µC, the potential difference between the plates is V = 750 V. Find the value of κ. Dielectric breakdown/Demo: 3 15 ¨ ¨ ¨ Dielectric breakdown occurs when a material is ionized in very high electric fields and becomes a conductor. The magnitude of the E field for which dielectric breakdown occurs in a material is called the dielectric strength of that material. The dielectric strength of air is ~3×106 V/m. ¤ ¤ ¨ In air, the existing ions are accelerated in the electric field, collides with air molecules, ionizing them. The dielectric discharge occurs more often during a dry day because moisture in the air can conduct the charge away before breakdown occurs. Demo: Jacob’s ladder ¤ 15,000 volts applied to two long vertical electrodes forms a spark at the bottom. Electrostatic field energy/Demo: 4 16 ¨ The energy stored in a capacitor is the total amount of energy required to charge the plates, 1 1 𝑄7 1 7 𝑈 = 𝑄𝑉 = = 𝐶𝑉 2 2 𝐶 2 ¨ The density of this energy stored in the electric filed is 𝑢9 = ¨ electric energy 1 = 𝜖+ 𝐸 7 volume 2 Demo: capacitor energy ¤ Three capacitors with a total capacitance of 4.5 mF are charged to 400 volts. ¤ 𝑈 = 𝐶𝑉 7 = H H 7 7 4.5 mF 400 V 7 = 360 J Quiz: 5 17 ¨ Consider a parallel-plate capacitor whose plates are given equal and opposite charges and are separated by a distance 𝑑. Suppose the plates are then pulled apart until they are separated by a distance 2𝑑. What is the ratio of the final to initial electrical energies, stored in the capacitor, 𝑈R ⁄𝑈S ? Quiz: 16-5 answer 18 ¨ ¨ 2 The charge on the plates does not change, so the electric field and energy density do not change: 𝑢9 = ¨ UVUWXYSW UZUY[\ ]^V_`U = H 𝜖+ 𝐸 7 7 The volume the electric field occupies doubles so the stored energy doubles. Applications of capacitors 19 ¨ Camera flash Defibrillator Capacitor microphone ¤ A diaphragm acts as one plate of a parallelplate capacitor. ¨ Stud finder ¨ ¨ ¤ ¤ A stud finder has a capacitor with its plates arranged side by side. When it is moved over a stud, the capacitance increases since the stud acts as a dielectric material.