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6/5/2015 SOLVING EQUATIONS For instance, if 2x + 3 = 17, then 7 is the only value of x that will make this a true sentence. • The single most important skill in algebra • Goal: Find the one value of the variable that makes the sentence true. • We can solve equations by doing the OPPOSITE of what has been done to the variable in the problem. If a problem says +, you subtract. If a problem has multiplication, you divide. • • So x = 7. By doing the opposite, we keep the sides of the equation balanced. As long as you do the SAME thing to both sides of an equation, it will remain balanced. 1 6/5/2015 7x – 13 = 50 7x – 13 = 50 +13 +13 7x = 63 7x – 13 = 50 +13 +13 7x = 63 7 7 x = 9 -5x + 7 = 82 -5x + 7 = 82 -7 -7 -5x = 75 -5x + 7 = 82 -7 -7 -5x = 75 -5 -5 x = -15 2 6/5/2015 4x + 25 = 13 4x + 25 = 13 - 25 -25 4x = -12 4 4 x = -3 4x + 25 = 13 - 25 -25 4x = -12 When you solve equations, you also do the opposite of the order of operations. • Add/subtract first • Then divide/multiply Solve these equations: Solve these equations: 4a + 11 = 59 4a + 11 = 59 Î a = 12 -2b + 13 = 5 -2b + 13 = 5 Î b=4 5c – 72 = 98 5c – 72 = 98 Î c = 34 -4d + 11 = 47 -4d + 11 = 47 Î d = -9 3 6/5/2015 Solve these equations: Solve these equations: 5x – 18 = 40 5x – 18 = 40 Îx = 58/5 or 11.6 2y + 73 = 54 -3z + 5 = 1 2y + 73 = 54 Îy = -19/2 or -9.5 _ 4 -3z + 5 = 1 Îz = /3 or 1.3 Some equations are even easier. Some equations are even easier. n + 4 = 13 n + 4 = 13 Just subtract 4 … x = 9 5x = 35 5x = 35 Just divide by 5 … x = 7 Solve 17 = 3x – 7 4 6/5/2015 Solve Solve 17 = 3x – 7 +7 +7 24 = 3x 17 = 3x – 7 +7 +7 24 = 3x 3 3 8= x Solve Solve 19 – 2x = 104 19 – 2x = 104 -19 -19 -2x = 85 Solve 19 – 2x = 104 -19 -19 -2x = 85 -2 -2 x = -85/2 or -42.5 If you know the basic steps, you can quickly do equations with more difficult numbers using a calculator. 5 6/5/2015 12x + 1794 = 2127 12x + 1794 = 2127 963 – 25x = 704 963 – 25x = 704 n + 13 = 22 7 What about this? n + 13 = 22 7 Fractions mean division, so to cancel, we’ll subtract 13 and then multiply by 7. Î n = 63 6 6/5/2015 Things that can complicate solving equations … Parentheses • Use distributive property first. Like terms • Combine them first. 3(2x – 5) = 27 3(2x – 5) = 27 3(2x – 5) = 27 6x – 15 = 27 6x = 42 x = 7 7 6/5/2015 -7(2x – 11) = 98 -7(2x – 11) = 98 -14x + 77 = 98 -14x = 21 x = -3/2 or -1.5 4p + 3 – 2p + 7 + 5p + 2 = 17 4p + 3 – 2p + 7 + 5p + 2 = 17 7p + 12 = 17 7p =5 p = 5/7 5(3x + 5) – 3(2x – 1) = 145 5(3x + 5) – 3(2x – 1) = 145 15x + 25 – 6x + 3 = 145 8 6/5/2015 5(3x + 5) – 3(2x – 1) = 145 15x + 25 – 6x + 3 = 145 9x + 28 = 145 The goal is always to simplify. Make the problem look like the easy ones we know how to solve. 7x – 15 = 2x + 70 5(3x + 5) – 3(2x – 1) = 145 15x + 25 – 6x + 3 = 145 9x + 28 = 145 9x = 117 x = 13 Variable on Both Sides • Find the smaller number of the variable, and subtract that on both sides. • Solve the remaining problem. 7x – 15 = 2x + 70 -2x -2x 5x – 15 = 70 9 6/5/2015 7x – 15 = 2x + 70 -2x -2x 5x – 15 = 70 5x = 85 x = 17 5x + 13 = 7x + 40 5x + 13 = 7x + 40 -5x -5x 13 = 2x + 40 5x + 13 = 7x + 40 -5x -5x 13 = 2x + 40 x = -27/2 or -13.5 3(2x + 7) = 3x + 4 + x + 9 3(2x + 7) = 3x + 4 + x + 9 6x + 21 = 4x + 13 10 6/5/2015 3(2x + 7) = 3x + 4 + x + 9 6x + 21 = 4x + 13 2x + 21 = 13 2x = -8 x = -4 Yesterday you saw this equation: 3x + 5(4x – 2) – 2(x – 4) = 4(2x – 7 + 3x) 3x + 20x – 10 – 2x + 8 = 8x – 28 + 12x 3x + 5(4x – 2) – 2(x – 4) = 4(2x – 7 + 3x) 3x + 20x – 10 – 2x + 8 = 8x – 28 + 12x 21x – 2 = 20x – 28 3x + 5(4x – 2) – 2(x – 4) = 4(2x – 7 + 3x) Solve it. 3x + 5(4x – 2) – 2(x – 4) = 4(2x – 7 + 3x) 3x + 20x – 10 – 2x + 8 = 8x – 28 + 12x 21x – 2 = 20x – 28 -20x -20x x–2= -28 +2 +2 x = -26 11 6/5/2015 Special equations 2(3x – 7) = 6x + 11 2(3x – 7) = 6x + 11 6x – 14 = 6x + 11 ????? 10x – 15 = 5(2x – 3) When variables cancel out… • 10x – 15 = 5(2x – 3) 10x – 15 = 10x – 15 ????? 10x – 15 = 5(2x – 3) 10x – 15 = 10x – 15 -15 = -15 • • An equation with infinitely many solutions can also be called an IDENTITY. If you have the exact same thing on both sides (like 8 = 8), the answer is ALL REAL NUMBERS or INFINITELY MANY SOLUTIONS. If there is something different on the 2 sides (like 5 = 7), there is NO SOLUTION. 2(3x – 7) = 6x + 11 6x – 14 = 6x + 11 -14 = 11 12 6/5/2015 • If there is something different on the 2 sides (like 5 = 7), there is NO SOLUTION. 2(3x – 7) = 6x + 11 6x – 14 = 6x + 11 -14 = 11 13