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02. Every Wednesday Free Suppliment EAMCET GRAND TEST www.ntnipuna.com, [email protected], www.facebook.com/ntnipuna 4006 3006 4006 3) 3008 MATHEMATICS 1. The position vectors of A, B, C are a , b , c and the points D, E, F are dividing BC, CA, AB respectively in the ratio m : n then centroid of DEF a b c 1) 3 3) 2. 2) a b c(m n) 3 4. 5. 6. If A = Lt x 4) O 12x 2 + 3x +11 , 3x 2 7x +8 C = Lt 1 1 1 ....n terms 1.2 2.3 3.4 x D = x ascending order is 1) C, D, B, A 3) A, B, D, C 7. 14. 0 1 15. 1 sin x If f(x) = 1 0 0 8. ex e 2 1 18. is x = 1) tanh2 x 3) cosh2 x 2) sech2 x 4) tanh x x for x 1 |x| 9. If f(x) = 10. is 1) 0 2) –1 3) 1 4) does not exists The nth term of the series 2 1 3 11. 2 1 2 5 2 2 1 2 19. R then f ’(0) 20. 2 2 3 7 .... is n(n 2) n(n 1) 2) 1) 6 4 n(n 1) n(2n 1) 4) 3) 6 6 1 If tn = (n + 2)(n + 3) for n = 1, 2, 3, 4 1 1 1 1 = …. then + + +....+ t1 t 2 t 3 t 2003 0 21. 0 6 0 0 0 6 6 6 18 12 6 If 1 b a3 b3 = k a 1 b 1 c and a, b, a2 b2 c2 c3 1 c are different values then k = 1) a + b + c 2) ab + bc + ca 3) a2 + b2 + c2 4) abc A lottery contains 100 tickets in which only one tickets contains prize. If a person purchases tickets of it one after one, until he gets prize ticket then probability that he gets it in 50th attempt is 1) 1/50 2) 50/100 3) 1/100 4) 99/100 There are 10 bulbs in which 6 are good bulbs and a room has 3 holders in which only 2 are good holders. If a person randomly picked 3 bulbs and fit them in 3 holders the probability for the room to get light is 1) 13/15 2) 4/5 3) 29/30 4) 2/3 The probability of a bomb hitting a bridge is ½ and one hit is sufficient to destroy it. The least number of bombs required so that the probability of the bridge being destroyed is greater than 0.8 is 1) 2 2) 3 3) 4 4) 5 If the mean of a binomial distribution with 9 trials is 6, then its variance is 32e4/3 81 32e 4/3 3) 81 32. 24. 26. 27. 28. 29. e4/3 27 32e 4/3 4) 27 2) Slopes of the tangents to the circle x2 + y2 = 10 drawn through the points (4, –2) are 3) –3, – If the equation 3x – 2y + z = 0, x – 14y + 15z = 0, x + 2y + 3z = 0 has non zero solution the = 1) 0 2) 29 3) 32 4) –30 2 31. 1 1) 3, – 3 4) 12 6 18 0 0 1 then their 1 sin x 6 2) 0 0 3) 0 1 0 16. 23. 25. 6 0 0 1) 0 6 0 0 0 6 1) 2 2) 3 3) 4 4) 2 With Poisson distribution 3P(x = 2) = 2P(x = 1) then P(x = 3) = 1) 1 – 3 then [A(Adj A)A 1 ]A = 1 c2 x 22. 1 continuous every where then f(0) = 1) 1/2 2) – 2 3) 1 4) 2 d sin tan dx If A = 2 1 3 2 17. 2) C, A, B, D 4) A, C, D, B 2) A stone is projected vertically upward which rises ‘s’ feet in ‘t’ seconds is given by s = 112t – 16t2. The maximum height reached by the stone is 1) 196 2) 216 3) 144 4) 28 The value of ‘a’ for which the function f(x) = a sin x + 1/3 sin 3x has an extremum at x = /3, is 1) 1 2) – 1 3) 0 4) 2 Angle between the two curves x2 – 3xy2 + 2 = 0 and 3x2y – y3 = 2 is 2) /3 1) /4 4) 0 3) /2 1 a2 sin 7x sin 5x x Lt 13. 8 | x | 3x , 3 | x | 2x B = Lt x 12. a b c 3(m n) With 3 non-zero, non-collinear vectors a , b , c . If 3 a + b is collinear with c and a + 3 c in collinear with b then for some nonzero scalar K, 3 a + b + 9 c is 1) k( a + b + c ) 2) k a 4) O 3) k c If a , b are two unit vectors such that a + 2 b and 5 a – 4 b are perpendicular to each other then angle between is 2) 60o 1) 90o o 3) 45 4) 30o If area of triangle ABC is and D is any point then | AB CD BC AD CA BD | = 2) 1) /2 4) 4 3) 2 ((i – j) (j – k) (i + 5k)) = 1) 5i – 4j – k 2) 3i – 2j + k 3) 4i – 5j – k 4) 5i + 4j – k 3. 4003 3007 4006 4) 3009 1) 1 3 33. 1 2) –3, 3 1 4) 3, 3 2 10x 10 3 10x 10 2) 1 3 30. 34. 35. 36. 37. 2 3 8 3) 9 1) 1 2 3x log 6 2 3x 1 x then the value of f(5x) If f(x) = 2x interms of f(x) is 1) 5f(x) 2) 1/5f(x) 3) 1/5[f(x) + 2] 4) 5[f(x) + 1/2] Let n(A) = 4 and n(B) = 5, the number of all possible many – one functions from A to B is 1) 625 2) 505 3) 120 4) 20 The arithmetic mean of the first n odd natural numbers is 1) n 2) (n + 1)/2 3) (n – 1) 4) 2n The arithmetic mean of the squares of the first n natural numbers is (n 1) 6 (n 2 1) 3) 6 38. 2) 4) n n(n 1) 2 2) n(n + 1) 3) (n + 1) e2 39. If I1 = 0 4) dx and I2 = log x 1) I1 < I2 3) I1 = I2 40. 41. 2) 42. (n 1)(2n 1) 6 The mean of first n natural numbers is 1) 4 3 5 4) 3 4 2 3 2 2 4) 3 2 3x 2 3x 1) 2) The value of m for which the line y mx 2 becomes a tangent to the hyperbola 4 x 2 9 y 2 36 is is 4) dx 4 cos 2 x 9 sin 2 x 1 3 1) tan 1 tan x 6 2 n 1 2 2 ex then x 1 2) I1 > I2 4) I1 = –I2 C 2) 1 2 3 tan x log 12 2 3 tan x 3) 1 2 3 tan x log 4 2 3 tan x C 4) 1 2 3 tan x log 6 2 3 tan x C of the semi major axis is 2 3 8 3) 3 x 1 2 3x log 2 2 3x 3) log10 1 and eccentricity is , then the length 2 1) x 1 x 1 x 1) log10 Equation of the common radical axis of the conjugate coaxial system of the given coaxial system x2 + y2 + 4x – 3y – 2 + (2x – 3y + 5) = 0 1) 2x – 3y + 5 = 0 2) 3x + 2y + 5 = 0 3) 2x – 3y + 17/2 = 0 4) 3x + 2y + 3 = 0 The two circles x2 + y2 – 2x – 2y – 7 = 0 and x2 + y2 + 4x + 6y – 3 = 0 are such that 1) touch extremely 2) touch internally 3) cut orthogonally 4) neither intersect nor touch [A] : The locus of point of intersection of perpendicular tangent drawn to the circle x2 + y2 – 4x – 6y – 12 = 0 is the circle x2 + y2 – 4x – 6y + 12 = 0. [R] : Locus of point of intersection of perpendicular tangents, is a circle which is concentric with given circle and radius is 2 times of radius of given circle. 1) Both A and R are true and R is the correct explanation of A 2) Both A and R are true but R is not the correct explanation of A 3) A is false R is true 4) A is true R is false Length of the double originate of the parabola y2 = 8x which subtends an angle 60o at the vertex is 2) 16 1) 16 3 4) 32 3) 8 3 Slope of common tangent to the parabola y2 = 4x and x2 = 32y is 1) 1/2 2) – 1/2 3) 2 4) – 2 The focus of an ellipse is at the origin the directrix is the line x 4 If a = 3i – 2j + k, b = 2i – 4j – 3k, c = –i +2j + 2k then a + b + c = 1) 3i – 4j 2) 3i + 4j 3) 4i – 4j 4) 4i + 4j The points 2i + 4j – k, 4i + 5j + k, 3i + 6j – 3k from 1) an equilateral triangle 2) an isosceles triangle 3) a right angled triangle 4) a right angled isosceles triangle Inverse of the function f(x) = C The area bounded by the curve y = x and y = x3 is 1) 1/4 2) 1/6 3) 1/12 4) 1/2 Area of the region bounded by y x , the x-axis and the ordinates