Download Math 125 Lab Section 63965

Math 125 Lab Section 63965
University of Kansas
January 17th, 2017
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Math 125 Lab Section 63965
January 17th, 2017
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Please tell us
(1) Preferred name,
(2) Where you’re from,
(3) What your major is,
On your paper, please answer the following:
(4) What is the highest mathematics course you’ve completed?
(5) Describe how you perceive your abilities with algebraic manipulations?
with trigonometry? with graphing functions?
(6) Have you worked in groups before? How do you feel about working in
small, 2-3 person groups?
(7) Is there anyone in class that you would prefer to work with?
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Laboratory Section 63965 Policies
5% of the final grade is assigned by lab sections.
Quiz Participation
4%
1%
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January 17th, 2017
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Laboratory Section 63965 Policies
5% of the final grade is assigned by lab sections.
Quiz Participation
4%
1%
Some quizzes will be individual and some in groups. You will not
know in advance.
Anyone later than 15 minutes to class will be considered absent.
Participation means that you will be engaged in the discussion and
work with your peers.
The internet will exist after class ends! Don’t waste your time and
money with distractions.
Office: Snow 559
Office Hours: T 11 am, R 11 am and by appointment.
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Precalculus
1
2
3
4
5
6x 2 + x − 2
. Find its domain and simplify
2x 2 + x − 1
f (x + h) − f (x)
1
Simplify the expression
For f (x) = 2 and h 6= 0.
h
x
What are the values of the other five trigonometric functions at θ if
sin(θ) = 47 ?
Sketch the graph of the following function:
 2
 x + 3 x < −2
2x − 3 −2 ≤ x ≤ 0
f (x) =

2 sin(x) x > 0
For the function g (x) =
Factor
3
1
2
6
1
18(x + 2)−2 (x − 1) 2 − 6(x + 2)−1 (x − 1) 2
6(2x + 1)2 (x 2 + 4)1/2 + 2x(2x + 1)3 (x 2 + 4)−1/2
A piece of wire 20 cm long is cut into two pieces. One piece is bent
into a square and the other is bent into a circle. Assuming that the
radius of the circle has length x, find a function A(x) for the sum of
the areas contained inside the square and circle.
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Answers
1
Domain (in interval notation):
(−∞, −1) ∪ (−1, 1/2) ∪ (1/2, +∞)
3x + 2
for x 6= −1, 1/2
x +1
Simplification:
2
−2x − h
x 2 (x + h)2
cos(x) =
tan(x) =
3
4
5
33
7
4
√
33
csc(x) =
sec(x) =
7
4
√7
33
√
cot(x) =
33
4
Next Slide
√
1
2
6
√
6 x − 1(2x − 5)
(x + 2)2
2(2x + 1)2 (5x 2 + x + 12)
√
x2 + 4
A(x) = πx 2 +
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(20−2πx)
4
2
20 with natural domain 0, 2π
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Answers
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