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GEOMETRY MODULE 1 LESSON 28 PROPERTIES OF PARALLELOGRAMS OPENING EXERCISE Consider the figure to the right. 1. If the triangles are congruent, state the congruence. Take care to list vertices in a corresponding order. βπ΄πΊπ β βπππ½ 2. Which triangle congruence criterion guarantees part 1? AAS Μ Μ Μ Μ corresponds with π½π Μ Μ Μ 3. ππΊ HOMEWORK QUESTIONS Problem Set Module 1 Lesson 25 is due today. DISCUSSION How can we use our knowledge of triangle congruence criteria to establish other geometry facts? For instance, what can we now prove about properties of parallelograms? What we know about parallelograms ο· A parallelogram is a quadrilateral in which both pairs of opposite sides are parallel. What we can assume about parallelograms ο· The opposite sides are congruent (equal in measure). ο· The opposite angles are congruent (equal in measure). ο· The diagonals bisect each other. MOD1 L28 1 PRACTICE If a quadrilateral is a parallelogram, then its opposite sides and angles are equal in measure. Given: Parallelogram ABCD Prove: π΄π· = πΆπ΅, π΄π΅ = πΆπ· πβ π΄ = πβ πΆ, πβ π΅ = πβ π· STEP JUSTIFICATION 1 Parallelogram ABCD Given 2 πβ π΄π΅π· = πβ πΆπ·π΅ Alternate interior angles from Μ Μ Μ Μ π΄π΅ β₯ Μ Μ Μ Μ π·πΆ 3 π΅π· = π·π΅ Reflexive Property 4 πβ πΆπ΅π· = πβ π΄π·π΅ Alternate interior angles from Μ Μ Μ Μ π΄π΅ β₯ Μ Μ Μ Μ π·πΆ 5 βπ΄π΅π· β βπΆπ·π΅ ASA 6 π΄π· = πΆπ΅, π΄π΅ = πΆπ· Property of congruent triangles 7 πβ π΄ = πβ πΆ Property of congruent triangles πβ π΄π΅π· + πβ πΆπ΅π· = πβ π΄π΅πΆ 8 Angle addition πβ πΆπ·π΅ + πβ π΄π·π΅ = πβ π΄π·πΆ 9 πβ π΄π΅π· + πβ πΆπ΅π· = πβ πΆπ·π΅ + πβ π΄π·π΅ Addition property of equality 10 πβ π΅ = πβ π· Substitution MOD1 L28 2 If a quadrilateral is a parallelogram, then the diagonals bisect each other. Given: Parallelogram ABCD Prove: π΄πΈ = πΆπΈ, π·πΈ = π΅πΈ STEP JUSTIFICATION 1 Parallelogram ABCD Given 2 πβ π΅π΄πΆ = πβ π·πΆπ΄ Alternate interior angles from Μ Μ Μ Μ π΄π΅ β₯ Μ Μ Μ Μ π·πΆ 3 πβ π΄πΈπ΅ = πβ πΆπΈπ· Vertical Angles 4 π΄π΅ = πΆπ· Opposite sides of a parallelogram are equal in length. 5 βπ΄πΈπ΅ β βπΆπΈπ· AAS 6 π΄πΈ = πΆπΈ, π·πΈ = π΅πΈ Property of congruent triangles Now we have established why the properties of parallelograms that we have assumed to be true are in fact true. By extension, these facts hold for any type of parallelogram: rectangles, squares, and rhombuses (diamond shape with four equal sides). Given: Rectangle GHIJ Prove: πΊπΌ = π»π½ (The diagonals are equal in length.) STEP JUSTIFICATION 1 Rectangle GHIJ Given 2 πΊπ½ = πΌπ» Opposite sides of a parallelogram are equal in length. 3 πΊπ» = π»πΊ Reflexive Property 4 β π½πΊπ» = β πΌπ»πΊ = 90° Definition of Rectangle 5 βπΊπ»π½ β βπ»πΊπΌ SAS 6 πΊπΌ = π»π½ Property of congruent triangles MOD1 L28 3 CONVERSE PROPERTIES Given: π΄π΅ = πΆπ·, π΄π· = π΅πΆ Prove: The quadrilateral ABCD is a parallelogram STEP JUSTIFICATION 1 π΄π΅ = πΆπ·, π΄π· = π΅πΆ Given 2 π΅π· = π·π΅ Reflexive Property 3 βπ΄π΅π· β βπΆπ·π΅ SSS β π΄π΅π· β β πΆπ·π΅ 4 Property of congruent triangles β π΄π·π΅ β β πΆπ΅π· Μ Μ Μ Μ π΄π΅ β₯ Μ Μ Μ Μ πΆπ· 5 Alternate Interior Angles Converse Μ Μ Μ Μ β₯ πΆπ΅ Μ Μ Μ Μ π΄π· 6 The quadrilateral ABCD is a parallelogram. Definition of Parallelogram ON YOUR OWN Given: Diagonals Μ Μ Μ Μ π΄πΆ and Μ Μ Μ Μ π΅π· bisect each other. Prove: The quadrilateral ABCD is a parallelogram 1 STEP JUSTIFICATION Diagonals Μ Μ Μ Μ π΄πΆ and Μ Μ Μ Μ π΅π· bisect each other. Given 2 π΄πΈ = πΈπΆ 3 πβ π΄πΈπ΅ = πβ π·πΈπΆ 4 βπ΄πΈπ΅ β βπ·πΈπΆ 5 πβ π΄π΅π· = πβ πΆπ·π΅ 6 7 MOD1 L28 Μ Μ Μ Μ β₯ πΆπ· Μ Μ Μ Μ π΄π΅ π·πΈ = πΈπ΅ πβ π΄πΈπ· = πβ π΅πΈπΆ βπ΄πΈπ· β βπ΅πΈπΆ πβ π΄π·π΅ = πβ πΆπ΅π· Μ Μ Μ Μ β₯ πΆπ΅ Μ Μ Μ Μ π΄π· The quadrilateral ABCD is a parallelogram Definition of Segment Bisector Vertical Angles SAS Property of congruent triangles Alternate Interior Angles Converse Definition of Parallelogram 4