Download Answers for the lesson “Apply the Remainder and Factor Theorems”

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts
no text concepts found
Transcript
LESSON
2.5
Answers for the lesson “Apply the Remainder
and Factor Theorems”
Skill Practice
1. If a polynomial f (x) is divided
by x 2 k, then the remainder
is r 5 f(k).
2. The red numbers are the
coefficients of the quotient and
the blue number is the remainder.
3
3. x 1 5 1 }
x24
26
4. 3x 1 4 1 }
x25
5.
6.
Copyright © Houghton Mifflin Harcourt Publishing Company. All rights reserved.
7.
8.
9.
10.
11.
9
x 1 4x 1 7 1 }
x21
8
2x 1 9 1 }
4x 2 1
24x 1 1
3x 1 8 1 }
x2 1 x
26
7x 1 11 1 }
x2 1 1
2122x 1 109
5x 2 2 12x 1 37 1 }}
x 2 1 2x 2 4
161x 1 84
4x 2 1 12x 1 44 1 }
x 2 2 3x 2 2
25
2x 1 3 1 }
x25
29
16. x 2 2 3x 1 5 1 }
x13
26
17. x3 1 x 2 2 2x 1 1 1 }
x26
10
18. x 3 2 x 2 1 5x 2 9 1 }
x15
19. The degree of the answer should
be reduced by 1;
1
.
x 2 1 2x 2 1 1 }
x22
20. The coefficient of x 2 was
not included.
2
215
12. 4x 2 5 1 }
x22
215
13. x 1 4 1 }
x14
18
14. x 1 3 1 }
x23
1
x 2 1 2x 2 1 1 }
x22
2
1
1
0
2
2
25
4
21
3
22
1
21. (x 2 6)(x 2 5)(x 1 1)
22. (x 2 1)(x 1 3)(x 1 4)
23. (x 2 8)(x 1 2)(x 1 4)
24. (x 1 3)(x 1 5)(x 1 10)
25. (x 2 4)(x 2 3)(x 1 9)
26. (x 2 6)(x 2 5)(x 1 2)
27. (2x 2 7)(x 2 3)(x 2 1)
28. (x 2 5)(3x 1 1)(x 1 4)
29. 21, 6
1
30. 24, }
4
218
15. x 2 2 x 2 4 1 }
x24
Algebra 2
Answer Transparencies for Checking Homework
66
2 3
31. 2}, }
5 2
2
32. 28, }
3
}
24 6 Ï 14
33. }
2
44. a. 40x 2 4x 3
}
11 6 Ï 41
34. }
10
c. 24 5 25x 2 4x 3, 1.386,
22.886; 1,386,000 radios
35. D
36. 2x 1 5
37. x 1 8
38. a. 23, 6
b. (x 2 6)(x 2 2)(x 1 3)
c. 23, 2, 6
39. A
40. a. 0.5
b. (x 2 0.5)(15x 2 1 11x 2 14)
c. (2x 2 1)(3x 2 2)(5x 1 7)
Problem Solving
Copyright © Houghton Mifflin Harcourt Publishing Company. All rights reserved.
b. P 5 25x 2 4x 3
41. 1 million T-shirts
42. 2 million MP3 players
43. f(x) 5 20.132x 2 1 11.2x 2
408,803
560.9 1 }
14.8x 1 725
d. No; the negative solution does
not make sense because the
company cannot produce a
negative number of radios.
45. P 5 20.0023x 3 1 0.249x 2 2
445,000
21.0x 1 1740 2 }
;
3.10x 1 256
divided the overnight stays
function by the total visits
function.
46. The only other solution is 24.
The company cannot produce a
negative number of DVDs.
Mixed Review of
Problem Solving
1. a. 1.64 3 1011
b. about 1.37 3 109 football fields
2. a. T(x) 5 8x3
b. C(x) 5 8x3 2 36x2 1
48x 2 16
c. I(x) 5 T(x) 2 C(x)
d. I(x) 5 36x 2 2 48x 1 16;
1936 in.3
Algebra 2
Answer Transparencies for Checking Homework
67
3. They will both exchange at the
same rate because they both have
a surface area-to-volume ratio
7. 4 ft;
4
6
of }x .
4. Sample answer:
f(x) 5 23x 4 1 2x 3 1 12
5. a. degree: 4, type: quartic
b. t
0
1
2
C 51 46.14 42.33
t
3
4
5
C 40.50 40.97 43.38
t
6
7
8
Copyright © Houghton Mifflin Harcourt Publishing Company. All rights reserved.
C 46.73 49.38 49.05
c. No; cell phone bills can not
be a negative amount as the
function shows after 2006.
6. a. r 5 100x 2 10x 3
b. P 5 70x 2 10x 3
c. 60 5 70x 2 10x 3; 23, 1
d. No; the manufacturer cannot
produce a negative number
of cameras.
Algebra 2
Answer Transparencies for Checking Homework
68
Related documents