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Barrys Discussion on a New 2nd Dimension Force Equation
By
Barry L. Crouse Ph.d Computer Information Systems
Barry Dynamic Dimensional Force Equation
F =
(m2 * m1) 2nd power
*
m2 * m1
( q1 ) 2nd power
(q2) 2nd power
(q3) 2nd power
(q4) 2nd power
* { x , sub-x}
Introduction
I would like to take the time for “Thanking Each and Everyone of you” for attempting to
read this scientific work. This work is theoretical in nature. The main concept is basically showing
Non-binding sub-atomic forces and why a new mathematical equation is necessary.
A preview of the chapters is as follows:
1).
2).
3).
4).
Updating Sir Isaac Newton's Equation
Apply data to the new equation
Table formatted data
Final thoughts
Again this work is theoretical so please keep that in mind when dealing with 2nd
dimensional forces and Non-binding sub-atomic particles.
Table of Contents
Chapter 1
Revising and Updating the Force Equation for the 2nd Dimension
Chapter 2
Testing the 2nd Dimensional Force Equation
Chapter 3
Table from Chapter 2
Chapter 4
Final Thoughts
Chapter 1
Revising and Updating the Force Equation for the 2nd Dimension
Today is 02/20/2013 University Place, Washington. I would like to propose a 2nd
Dimension Equation based on Force because in the 2nd Dimension sub-atomic particles are not binded
and pass through matter even within our own Universe. Before we begin, I would like to show two
Equations the 1st shows Sir Issac Newtons 16th Century equation that shows gravity and two masses
within our own Universe according to Wikipedia.
F = G * m1 * m2 / r2 The variables used are below
F = Force
G = Gravitational
m = active gravitational mass
r = distance.
Three or 4 years ago I proposed a Equation that recognized the distances, masses within
different dimensions. Please see below with the variables used.
F = G (m2*d2) – (m1*d1) / (r2*d2) – (r1*d1)
F = Force
G = Gravity
M = Mass
d = dimension
r = distance
As you can see, The problem with Sir Issac newtons Equation is that it did not address subatomic particles and different dimensions. The Equation I proposed showed different dimensions but
does not show sub-Atomic masses that becomes smaller to allow for it to pass through the 2nd
Dimension. The New equation I am proposing shows sub-Atomic masses becoming smaller and tests
the binary position of the distance. I am not concerned with a assigned value of distance but the
position of it. Please see Barry Dynamic Dimensional Force Equation below also in the 2nd
dimension in dealing with sub-atomic particles gravity variable is removed because as you know subatomic particles have next to nothing in dealing with weight and is not binded to matter { solid, liquid,
and gas } it passes through examples electrons, positrons, neutrinos, etc..
F =
(m2 * m1) 2nd power
*
m2 * m1
( q1 ) 2nd power
(q2) 2nd power
(q3) 2nd power
(q4) 2nd power
* { x , sub-x}
The Equation shows gravity is not binded to the 2nd dimension force along with q1 – q4
dynamic areas of space. X has the values to test conditions which are the following { 0 , 1 , -1, 1/2,
-1/2, ). Sub-X { 1/4 , -1/4 }
m2 = Internal mass- Sub-atomic 1st level
m1 = Internal mass- Sub-atomic 2nd level
q1 = Area 1 space
q2 = Area 2 space
q3 = Area 3 space
q4 = Area 4 space
x
= { 0 , 1, -1, 1/2, -1/2)
= 1st level
sub-x = { 1/4 , -1/4}2nd power = 2nd level
The 1st level of X tests 5 positions and they are 0, 1, -1, 1/2, -1/2 The fractions are tested as
fractional binary positions as proposed in previous works this is a way to say the binary switches of 1
and -1 positive and negative are tested along with the 1/2 and -1/2 which is fractional.
The 2nd level or sub-level underneath the sub-level is tested as sub-x. A easier way to
understand this is a shell within a shell. The Equation attempts to show passing from the 1st to 2nd
dimension. I will now begin in the next chapter to test the equation with the variables. I shall name the
new Equation the Barry Dynamic Dimensional Force Equation
03/07/2013
Barry L. Crouse ph.d Computer Information Systems
Chapter 2
Testing the 2nd Dimensional Force Equation
I will now begin by naming the variables in the Equation and than supply the
value names and test the equation.
m2 = .04
m1 = .004
q1 = .60
q2 = - .70
q3 = 1
q4 = .75
x
= { 0 , 1, -1, 1/2, -1/2) = 1st level
sub-x = { 1/4 , -1/4} 2nd power = 2nd Level
F =
(m2 * m1) 2nd power
*
m2 * m1
F=
( q1 ) 2nd power * { x , sub-x 2ndpower}
(q2) 2nd power
(q3) 2nd power
(q4) 2nd power
(.04 * .004) 2nd power
.04 * .004 * (.60 ) 2nd power * 0
• ( -.70) 2nd power * 0
• ( 1) 2nd power * 0
• .(.75) 2nd power * 0
the Values returned for the value x returns 0 in this event. I will now test for the 1
or on position.
F=
(.04 * .004) 2nd power
.04 * .004
0.000000026
0.00016
F=
√ 0.0001625
* (.60) 2nd power * 1
F=
0.012747549 * (.60) 2nd power * 1
F=
0.012747549 * 0.36 * 1
F=
0.004589118 = q1 area of space
I will now obtain the other areas of space using F = 0.012747549
F = 0.012747549 * (-.70) 2nd power * 1
F=
0.012747549 * 0.49 * 1
F=
0.00062463 = q2 area of space
F=
0.012747549 * (1) 2nd power * 1
F=
0.012747549 = q3 Area of space
F=
0.012747549 * (.75) 2nd power * 1
F=
0.012747549 * 0.5625
F=
0.007170496 = q4 area of space
I will now use the value of -1 to obtain the inverse of 1 this is accomplished by taking
the values returned on q1 through q4 area of space and multiply by -1.
q1 Area of space =
F = 0.004589118 * -1
q1 area of space =
F = −0.004589118
q2 area of space =
F= - 0.00062463
q3 area of space =
F = -0.012747549
q4 area of space =
F = - 0.007170496
If you noticed, The values returned are less than 1. I also was able to obtain a Negative
force in this equation meaning a positive and negative force electrons and Positrons that are not binded
to this Universe but I still have to test for the values of 1/2 and -1/2 or Fractional binary positions.
Q1 = area of space = F
= 0.004589118 * .50
Q1= area of space = F
= 0.002294559
Q2 = area of space = F
= 0.00062463 * .50
Q2 = area of space = F
= 0.000312315
Q3 = area of space = F
=
0.012747549 * .50
Q3= area of space = F
=
0.006373775
Q4 = area of space=F
=
0.007170496 * .50
Q4 = area of space=F
=
0.003585248
I have evaluated the x value of 1/2 or .50. The -1/2 or -.50 is a inverse relationship
meaning the numbers on the positive side will show the same as the negative side.
Q1= area of space= F
= - 0.004589118
Q2= area of space=F
= - 0.000312315
Q3= area of space=F
= - 0.006373775
Q4= area of space=F
= - 0.003585248
I will now use the subset of x by multiply 1/4 to the 2nd power to represent the subvalues of X.
Q1 = area of space = F
= 0.004589118 * (.25) 2nd
Q1= area of space= F
= 0.00028682
Q2= area of space= F
= 0.00062463 * (.25) 2nd power
Q2 =area of space= F
= 0.000039039
Q3=area of space= F
= 0.012747549 * (.25) 2nd power
Q3= area of space=F
= 0.000796722
Q4=area of space=F
= 0.007170496 * (.25) 2nd power
Q4=area of space=F
= 0.000448156
The value of -1/4 is the inverse of 1/4 or .25.
Q1= area of space= F
= - 0.00028682
Q2 =area of space= F
= - 0.000039039
Q3= area of space=F
= - 0.000796722
Q4=area of space=F
= - 0.000448156
This concludes testing the equation for F or force using dynamic areas of space, binary
positions of x and sub-x. I will now present the data in a table format so that it is easier to read and
understand in the next chapter.
03/04/2013
Barry L. Crouse Ph.d Computer Information System
Chapter 3
Table from Chapter 2
Areas of Space
Area of Space Value
X and Sub-X Values
Returned Value
1
2
3
4
.60
- .70
1
.75
0
0
0
0
0
0
0
0
1
2
3
4
.60
-.70
1
.75
1
1
1
1
0.004589118
0.00062463
0.012747549
0.007170496
-1
-1
-1
-1
- 0.004589118
- 0.00062463
- 0.012747549
- 0.007170496
1
2
3
4
.60
-.70
1
.75
1
2
3
4
.60
-.70
1
.75
.50
.50
.50
.50
0.002294559
0.000312315
0.006373775
0.003585248
1
2
3
4
.60
-.70
1
.75
-.50
-.50
-.50
-.50
-0.002294559
-0.000312315
-0.006373775
-0.003585248
Areas of Space
Area of Space Value
X and Sub-X Values
Returned Value
1
2
3
4
.60
-.70
1
.75
(.25) 2nd power
(.25) 2nd power
(.25) 2nd power
(.25) 2nd power
0.00028682
0.000039039
0.000796722
0.000448156
1
2
3
4
.60
-.70
1
.75
-(.25) 2nd power
-(.25) 2nd power
-(.25) 2nd power
-(.25) 2nd power
- 0.00028682
- 0.000039039
- 0.000796722
- 0.000448156
I would now like to provide some observations in relations to interrupting the table
information. The observations are as follows
1). The Equation showed mass becoming smaller as expected from a binary number
to a fractional binary Equation or sub-x.
2). X-Values compared from 1 to .50 showed a very discreet change and is expected
within our own Universe Sub-Atomic to Atomic.
3). The value 1 returned a greatest Force than the other values of X while the sub-x
showed the smallest amount of force this is showing as a number decreases
within the Equation than the binding of that mass is not dependent on our
Universe and supports the idea as mass is not binded to our Dimensional space.
This than allows for binary positions of speed and velocity that exceed the speed
of light because I am not depended on our Universal Space-time but the 2nd
dimensional forces start to become a factor which are binary positions.
I will now provide my final thoughts on this topic in Chapter 4.
Barry L. Crouse Ph.d Computer Information Systems
03/04/2013
Chapter 4
Final Thoughts
Science Pyramid 1600 – 2013 R.I.P.
Cracks
Sink hole
I will now provide my thoughts on this topic. This work as 1st shown is basically
theoretical based on sub-atomic particles and 2nd dimensional forces. As we know, sub-atomic particles
are not binded to matter within our universe and in fact passes through it therefore gravity on a non
binding sub-atomic particle should be represented to show and reflect this. My equation reflected this.
Sir Issac Newton wrote the equation based on particles that had gravity and binded within our own
universe. The equation was written roughly 400 years ago and does not reflect sub-atomic particles and
non binding forces.
This study of Physics and Mathematics in dealing with 2nd dimensional forces
could lead to new opportunities in new research and development but probably not within the
Academic circles do to the inability to adapting to dynamic changes.
I have attempted to modernize and update four Equations because as more
information is obtained Mathematical Equations and Physics will need to reflect this and along with
modernizing these fields. This should create new career opportunities first in Research and
Development next creating practical applications through new products that reflect a new Economy
with careers and jobs.
I have updated the four Equations as follows:
1).
2).
3).
4).
Barry Equality Field equation | Einsteins Theory of General Relativity
Barry binary 2nd dimension Equality Field Equation | The Lorentz factor
Barrys Cosmological Dynamic binary position | Cosmological Constant
Barry Dynamic Dimensional Force Equation | Sir Issac Newton Gravity
Date 03/18/2013
Barry L. Crouse Ph.d Computer Information Systems