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Algebra I Seminar – Lesson 63
Part 1 – Bell Work – Slope
Find the slope between the following points.
a. (1, -2) and (1, 3)
b. (5, -2) and (-1, -5)
c. (3, 1) and (7, 1)
d. (0, 0) and (0, -6)
Part 2 – Mini-lesson – Intercepts
In this lesson we will try to draw a connection between intercepts and their
coordinates. Kids should be able to plot the points and determine whether
the points are x- or y-intercepts or neither. They should also be able to find
the coordinates of a given intercept. The key to this lesson is to stress the
proper usage of vocabulary.
Plot the points and determine
whether the points are x- or yintercepts or neither.
1. (-2, 0)
2. (-4, 3)
3. (6, 0)
4. (0, 3)
5. (0, 3)
6. (-3, -4)
7. (2, 0)
8. (0, 5)
9. (0, -2)
10. (6, 0)
Identify the coordinates of the
following intercepts.
1. x-int = 4
2. y-int = 3
3. x-int = -5
4. y-int = -1
5. y-int = 0
6. y-int = 4.4
7. x-int = 0.5
8. x-int = 4.56
9. y-int = -2.3
10. x-int = 3½
Part 3 – Independent Work
Part 4 – Exit Card
How can you identify an x- or y-intercept without graphing?
What point is both an x-intercept and a y-intercept?
Algebra I Seminar - Lesson 64
Part 1 – Bell Work – Intercepts
Plot a point at the following intercepts.
1. y-int = -2
2. x-int = 4
3. y-int = 3.2
4. y-int = -5
Part 2 – Mini-lesson – Graphing One-Variable Lines
In this lesson students will be given an x = or y = equation and will graph it by
creating two points. Eventually, students should realize that these are
horizontal and vertical lines. Ask them the slope of the graphed line to help
them draw the connection.
Graph the following lines.
1. x = 4
(
,
)
(
,
)
2. y = -2
(
,
)
(
,
)
3. y = 5
(
,
)
(
,
)
4. x = -3
(
,
)
(
,
)
5. x = 1.5
(
,
(
,
6. y = -3.3
(
,
(
,
7. y = -1
(
,
(
,
8. x = 5
(
,
(
,
)
)
)
)
)
)
)
)
Part 3 – Independent Work
Part 4 – Exit Card
Is there a way to graph a one-variable equation without plotting points? If so,
how can it be done?
Algebra I Seminar - Lesson 65
Part 1 – Bell Work
Graph the following lines.
5. y = -2
6. x = 3
7. y = 3.2
8. x = -5
Part 2 – Mini-lesson – Solving for y
Give a lesson on solving for y when an x is present in the equation. Follow
the format of the examples below.
Solve for y.
1. y + 3 = x
2. y – 5 = x
3. y + 7 = 4x
4. y – 9.2 = 6x
5. y + 4 = -2x
6. y – 6 = -5x
7. y – 3,3 = 4.5x
8. x = y + 3
9. x = y – 7
10. 4x = y + 2.2
11. -3x = y – 5
12. 6x = y - 5
Solve for y.
1. 2y = 10x
2. 3y = 12x
3. 4y = 6x
4. -2y = 14x
5. 5y = 7x
6. 3y = -12x
7. 6y = 9x
8. -4y = -12x
9. 3.6y = 9.1x
10. 22x = 4y
11. 12x = -6y
12. 10x = 40y
Solve for y.
1. 2y + 3 = 4x
2. -3y – 6 = 5x
3. 10x = 15 – 5y
4. 8x = 9 + 3y
5. 5y + 2 = 22x
6. 2 + 4x = 2y
7. 3 – 5x = 6y
8. 7 – 3y = 9x
9. 2 + 3y = 15x
10. 9x = 14 – 2y
11. 9x = 14 + 2y
12. 3x = 10 + 7y
Part 3 – Independent Work
Part 4 – Exit Card
Which of these is incorrect? Why?
Solve for y.
Student 1:
4y – 8 = 12x
+8
+8
4y = 12x + 8
Student 2:
4y – 8 = 12x
+8
4y = 20x
y = 3x + 2
y = 5x
+8
Algebra I Seminar - Lesson 66
Part 1 – Bell Work
Solve for y.
1. y + 3 = 5x
2. 4y = 12x
3. 2y + 5 = -6x
4. 5x = y + 3
Part 2 – Mini-lesson – Solving for y
Give a lesson on solving for y when an x is present in the equation. Follow
the format of the examples below. Today, we will place the x on the same
side of the equation as the y.
Solve for y.
1. 3x + 5y = 14
2. 4x – 6y = 9
3. 2y – 5x = 11
4. 3y + 3x = -9
5. -3y + 5x = 22
6. 5x – 5y = 18
7. 12 = 4x + 3y
8. 15 = 3x – 5y
9. 25 = -9x – 6y
10. 14 = -2y + 7x
Part 3 – Independent Work
Part 4 – Exit Card
What is the first step to solving the following equation? (Answer in your
words)
2y + 5x = 10
Algebra I Seminar - Lesson 67
Part 1 – Bell Work – Solve for y
1. 3x + 5y = 15
2. 4x – 5y = 11
3. 2y – 5x = 12
4. 4y + 4x = -9
Part 2 – Mini-lesson – Graphing
In this lesson, students will learn how to graph linear equations that are in
slope-intercept form. Use y-intercepts that are whole numbers, including
zero. Assign the following worksheet.
Part 3 – Independent Work
Part 4 – Exit Card
What is the first step in graphing an equation in slope-intercept form?
Graphing – Lesson 67
1
y = x -4
2
2
y =- x+3
5
Graph the equation.
2
y = x +1
3
y = 2x - 3
y=
1
x
2
1
y = - x -1
5
1
x -2
3
1
y =- x -3
3
y=
3
x +2
4
y=
y=
2
x
5
2
y=- x
3
3
y = - x +1
5