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Rational Function
function 𝑓(π‘₯) is the quotient of two
polynomial functions π‘Ž(π‘₯) and 𝑏(π‘₯), where 𝑏 is
nonzero.
 A rational
π‘Ž π‘₯
𝑓 π‘₯ =
𝑏 π‘₯
 The domain of a rational function is all real
numbers excluding those values for which
𝑏 π‘₯ = 0, or the zeroes of 𝑏 π‘₯ .
Rational Functions
1
π‘₯

𝑓 π‘₯ =

This is not piecewise.

The lines representing those
values are called
asymptotes.
Graph
𝑓
π‘₯ =
1
π‘₯βˆ’2
Asymptotes
line π‘₯ = 𝑐 is a vertical asymptote of 𝑓
if 𝑓 π‘₯ β†’ ±βˆž as π‘₯ β†’ 𝑐.
 The
Asymptotes
line 𝑦 = 𝑏 is a horizontal asymptote of
𝑓 if 𝑓 π‘₯ β†’ 𝐛 as π‘₯ β†’ ±βˆž.
 The
Find the Domain and the Asymptotes
𝑓
π‘₯ =
π‘₯+4
π‘₯βˆ’3
Check with a graph
Find the Domain and the Asymptotes
𝑔
π‘₯ =
8π‘₯ 2 +5
4π‘₯ 2 +1
Check with a Graph
Find the Domain and the Asymptotes
ο΅π‘š
ο΅β„Ž
π‘₯ =
π‘₯ =
15π‘₯+3
π‘₯+5
π‘₯ 2 βˆ’π‘₯βˆ’6
π‘₯+4
Vertical Asymptotes
 Vertical
asymptotes can only exist where the
domain of a function is discontinuous.
 But
just because a function is discontinuous
a particular value of π‘₯ doesn’t mean it will
form an asymptote, so check.
Holes
 Given
the polynomial function:
π‘₯2 βˆ’ 4
𝑓 π‘₯ = 2
π‘₯ βˆ’ 3π‘₯ βˆ’ 10
What is the domain of this?
Holes
π‘₯2 βˆ’ 4
𝑓 π‘₯ = 2
π‘₯ βˆ’ 3π‘₯ βˆ’ 10
Horizontal Asymptotes
Let 𝑓 be a rational function defined as:
π‘Ž π‘₯
𝑓 π‘₯ =
, 𝑏(π‘₯) β‰  0
𝑏 π‘₯
π‘Ž(π‘₯) and 𝑏 π‘₯ are polynomials with no common factors. Let π‘Ž(π‘₯)
have degree 𝑛 and 𝑏(π‘₯) have degree π‘š
 The graph may have 1 or 0 horizontal asymptotes using these
guidelines:
 If 𝑛 < π‘š, the horizontal asymptote is 𝑦 = 0.


π‘Ž
If 𝑛 = π‘š, the horizontal asymptote is 𝑦 = 𝑏 𝑛
π‘š

If 𝑛 > π‘š, there is no horizontal asymptote.
π‘₯-Intercepts and 𝑦-Intercepts
𝒙-intercepts of 𝑓(π‘₯) occur at the zeroes
of π‘Ž π‘₯ .
 All
 Why?
 The
𝑦-intercepts occur at 𝑓(0).
Find the Domain, Asymptotes, and π‘₯and 𝑦-intercepts
ο΅β„Ž
𝑛
π‘₯ =
2
π‘₯ 2 +2π‘₯βˆ’3
π‘₯ =
π‘₯ 2 βˆ’4
5π‘₯ 2 βˆ’5
Do Now
 Find
all asymptotes, holes, and intercepts
for:
π‘₯ 2 + 5π‘₯ βˆ’ 50
𝑓 π‘₯ = 2
π‘₯ + π‘₯ βˆ’ 30
Do Now
 Write
a procedure for determining the slant
asymptotes of rational equations.
 Use
that procedure to find all asymptotes
for:
3π‘₯ 3 βˆ’ 7π‘₯ 2 βˆ’ 22π‘₯ + 8
𝑓 π‘₯ =
π‘₯ 2 βˆ’ 7π‘₯ + 10
It Gets Cooler
𝑓
π‘₯ =
π‘₯2
π‘₯+1
 Graph
this function.
 Zoom
out.
 Zoom
out again.
 Keep
zooming!
Oblique/Slant Asymptotes
 We
call these oblique or slant asymptotes.
 What
 It
does oblique mean?
means slanted.
 These
occur when a graph approaches a
linear relationship at its ends.
Oblique/Slant Asymptotes
𝑓 be a rational function defined as:
π‘Ž π‘₯
𝑓 π‘₯ =
𝑏 π‘₯
 If 𝑛 = π‘š + 1, the graph has an oblique
asymptote.
 Let
𝑓
π‘₯ =
 The
π‘Ž π‘₯
𝑏 π‘₯
=π‘ž π‘₯ +
π‘Ÿ π‘₯
𝑏 π‘₯
asymptote will run along the line 𝑦 = π‘ž(π‘₯).
Slant Asymptote
π‘₯2
π‘₯+1

𝑓 π‘₯ =


We know this has a vertical asymptote at π‘₯ = βˆ’1.
Because 𝑛 > π‘š, there are no horizontal asymptotes.
Because 𝑛 = π‘š + 1, there is a slant asymptote.
Do the long division:

Slant asymptote at 𝑦 = π‘₯ βˆ’ 1.


Check the Graph
Determine any asymptotes, intercepts,
the domain of the function
ο΅β„Ž
𝑝
π‘₯ =
π‘₯ 2 +3π‘₯βˆ’3
π‘₯+4
π‘₯ =
π‘₯ 2 βˆ’4π‘₯+1
2π‘₯βˆ’3
More Practise
𝑓
π‘₯ =
π‘₯ 3 βˆ’2π‘₯ 2 +π‘₯+18
π‘₯ 2 βˆ’12π‘₯+35
Determine any asymptotes, intercepts,
the domain of the function
𝑔
𝑐
π‘₯ =
π‘₯ 2 +10π‘₯+24
π‘₯ 2 +π‘₯βˆ’12
π‘₯ =
π‘₯ 2 βˆ’2π‘₯βˆ’3
π‘₯ 2 βˆ’4π‘₯βˆ’5
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