Survey
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
10.3 Inscribed Angles Using Inscribed Angles • An inscribed angle is an angle whose vertex is on a circle and whose sides contain chords of the circle. The arcinscribed angle that lies in the interior of an inscribed angle and has endpoints on the angle is called the intercepted arc of the angle. intercepted arc Theorem 10.8: Measure of an Inscribed Angle A • If an angle is inscribed in a circle, then its measure is one half the measure of its intercepted arc. mADB = ½m AB C D B Ex. 1: Finding Measures of Arcs and Inscribed Angles • Find the measure of the blue arc or angle. S R m QTS = 2mQRS = T 2(90°) = 180° Q Ex. 1: Finding Measures of Arcs and Inscribed Angles • Find the measure of the blue arc or angle. m ZWX = 2mZYX = 2(115°) = 230° W Z Y X Ex. 1: Finding Measures of Arcs and Inscribed Angles • Find the measure of the blue arc or angle. m NMP = ½ m NP N 100° M P ½ (100°) = 50° Ex. 2: Comparing Measures of Inscribed Angles A • Find mACB, mADB, and mAEB. E The measure of each angle is half the measure of AB m AB = 60°, so the measure of each angle is 30° B D C Theorem 10.9 A • If two inscribed angles of a circle intercept the same arc, then the angles are congruent. • C D D B C Ex. 3: Finding the Measure of an Angle G • It is given that mE = 75°. What is mF? • E and F both intercept GH , so E F. So, mF = mE = 75° E 75° F H Using Properties of Inscribed Polygons • If all of the vertices of a polygon lie on a circle, the polygon is inscribed in the circle and the circle is circumscribed about the polygon. The polygon is an inscribed polygon and the circle is a circumscribed circle. Theorem 10.10 • If a right triangle is inscribed in a circle, then the hypotenuse is a diameter of the circle. Conversely, if one side of an inscribed triangle is a diameter of the circle, then the triangle is a right triangle and the angle opposite the diameter is the right angle. • B is a right angle if and only if AC is a diameter of the circle. A B C Theorem 10.11 • A quadrilateral can be inscribed in a circle if and only if its opposite angles are supplementary. • D, E, F, and G lie on some circle, C, if and only if mD + mF = 180° and mE + mG = 180° F E C G D Ex. 5: Using Theorems 10.10 and 10.11 B • Find the value of each variable. • AB is a diameter. So, C is a right angle and mC = 90° • 2x° = 90° • x = 45 Q A 2x° C Ex. 5: Using Theorems 10.10 and 10.11 D • Find the value of each variable. • DEFG is inscribed in a circle, so opposite angles are supplementary. • mD + mF = 180° • z + 80 = 180 • z = 100 z° E 120° 80° y° G F Ex. 5: Using Theorems 10.10 and 10.11 D • Find the value of each variable. • DEFG is inscribed in a circle, so opposite angles are supplementary. • mE + mG = 180° • y + 120 = 180 • y = 60 z° E 120° 80° y° G F Ex. 6: Using an Inscribed Quadrilateral A • In the diagram, ABCD is inscribed in circle P. Find the measure of each angle. 2y° D 3y° 3x° B • ABCD is inscribed in a 2x° circle, so opposite C angles are supplementary. To solve this system of linear equations, • 3x + 3y = 180 you can solve the first equation for y to • 5x + 2y = 180 get y = 60 – x. Substitute this expression into the second equation. Ex. 6: Using an Inscribed Quadrilateral • • • • • • 5x + 2y = 180. 5x + 2 (60 – x) = 180 5x + 120 – 2x = 180 3x = 60 x = 20 y = 60 – 20 = 40 Write the second equation. Substitute 60 – x for y. Distributive Property. Subtract 120 from both sides. Divide each side by 3. Substitute and solve for y. x = 20 and y = 40, so mA = 80°, mB = 60°, mC = 100°, and mD = 120°