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Resolution of Vectors into Rectangular Components To break a vector, ~v , into rectangular components means to break them into x and y (or horizontal and vertical components). The horizontal and vertical components of ~v are normally expressed as v~x and v~y respectively. The vector ~v is always the sum of its components, ~v = v~x + v~y . In order to solve for the magnitudes of v~x and v~y we must use trigonometry for right angled triangles. Example 1.1. Find v~x and v~y for the vector in the following diagram. Since we have a right angle triangle, cos 65◦ = vx 28N sin 65◦ = vy 28N ⇒ vx = cos 65◦ · 28N vy = sin 65◦ · 28N ⇒ v~x = 11.8 N [Right] ⇒ v~y = 25.4 N [Down]. By breaking vectors into their rectangular components, we can add vectors in a new way. This method is very adaptable and useful in cases where the sine and cosine law methods are cumbersome. It will also be used more exclusively later in the course. *Explore the GSP file VectorAdditionByComponents.gsp Assign the students questions from the text for them to practice breaking vectors into components. Example 1.2. Inclined Plane Example A box weighing 140 N is resting on a ramp that is inclined at an angle of 20◦ . Resolve the weight vector F~g into rectangular components that are parallel and perpendicular to the plane. 1 In this case, we must break F~g into rectangular components as shown in the diagram on the right. However, in order to calculate the magnitudes of the components, we must first determine the angle θ. From the next diagram we can see that x + z = 90◦ since the sum of angles in a triangle must be 180◦ , but it is also clear that z + y = 90◦ . Thus, x = y, and so the angle θ is in fact the same measure as the angle of the incline, and θ = 20◦ . Now to calculate the components, we have that g// = (140N ) sin 20◦ g⊥ = (140N ) cos 20◦ g// = 48 N g⊥ = 132 N 2