Download Chapter 4 4.2: Solving Algebraic Equations Objective… • The weight

Chapter 4
4.2: Solving Algebraic Equations
Objective…
Part A: Solve Algebraic Equations with Variables on the Same Side of the Equation
•
The weight of a bowling ball is 6 kilograms. Two bowling pins and a
bowling ball weighed 9 kilograms. What is the weight of a bowling pin?
Rewrite and solve:
Check:
Thought process…
1
2
3
4
Practice… Solve algebraic equations
2 + 5y = 12
8m – 4 = 20
Chapter 4
4.2: Solving Algebraic Equations
3 – 7y = 10
-9 – 7y = 26
*Balancing Equation
*Multiplying Equation
1
1
y− =2
6
3
1
1
y− =2
6
3
m + 1.5 – 0.5m = 4.5
4y – 3 + 0.5y = 1.5
6x + 2 = 8
5 – 3n = 20
9
4
m − =1
10
5
1 2
+ m=4
5 3
Part B: Solve Algebraic Equations with Variables on Both Sides of the Equation
• Paul and Rachel are asked to solve: 4x + 7 = x + 10
Paul’s Method (non fractions)
Rachel’s Method (non fractions)
4x + 7 = x + 10
4x + 7 = x + 10
Chapter 4
4.2: Solving Algebraic Equations
Practice… Solve each equation
Method 1 (non fractions)
Method 2 (non fractions)
8 – 5x = 2x + 22
8 – 5x = 2x + 22
9 – 2y = 6y - 15
9 – 2y = 6y - 15
2.9y + 2.7 = 1.1y – 9.9
2.9y + 2.7 = 1.1y – 9.9
11 – 4m = m + 6
11 – 4m = m + 6
3.4y – 5.2 = 3y + 2
3.4y – 5.2 = 3y + 2
Chapter 4
4.2: Solving Algebraic Equations
Method 1 (fractions)
3
1 3
m− = y+4
4
2 8
Method 2 (fractions)
3
1 3
m− = y+4
4
2 8
5
1 2
1
y− = y+
9
3 3
3
5
1 2
1
y− = y+
9
3 3
3
Part C: Solve Algebraic Equations in Factored Form
•
Solve: 2(3x + 1) = 11
Practice… Solve each equation
Method 1 (non fractions)
Method 2 (non fractions)
3(3x + 1) = 12
2(3x + 1) = 12
4(5m + 6) = 20
4(5m + 6) = 20
Chapter 4
4.2: Solving Algebraic Equations
1.2(2m – 2) = 15
1.2(2m – 2) = 15
1.5(p + 3) = 18
1.5(p + 3) = 18
Practice… Solve each equation
Method 1 (fractions)
1
( z +1) = 6
6
Method 2 (fractions)
1
( z +1) = 6
6
1
(8y −16) = 5
4
1
(8y −16) = 5
4
1
(q + 2) = 9
2
1
(q + 2) = 9
2
Chapter 4
4.2: Solving Algebraic Equations
•
Solve: 4(z + 1) + 2 = 18
Practice… Solve each equation
Problem
1.5(w + 2) + 2 = 8
2m + 5(2 – m) = 40
2(y – 3) + 2 = 14
3(y – 1) + y = 1
*multi-step problem
Thinking points