Download B Si Ge As Sb Te

Introductory Chemistry CHM 1025
Test #2
1 of 10
Section: 005 Name:__________________________ Date: March 16, 2015
[Each question is worth 4 points unless otherwise stated. Checking answer without showing
the set up or reasoning, when indicated, earns no credit. Good Luck!]
1. Identify, by symbol and name, all 6 metalloids found in the first 5 periods in the periodic
table.
[6 pts]
Period
2
5
boron
B
10.81
14
Period
3
Si
silicon
28.0855
32
Period germa
4
nium
Period
5
Ge
33
As arsenic
72.61
74.92159
antimo
ny
51
52
Sb
Te
121.760
127.60
telluriu
m
2. The following questions on Periodic Table are worth 2 points each:
a. Element M is a metal and its phosphide has the formula M3P2. To which group of
the Periodic Table does element M most likely belong?
1. (IA)
2. (IIA)
3. (IIIA)
4. (IVA)
5. (VA)
b. A selenium atom differs from a selenium ion in that, the atom has:
a greater number of electrons
a lesser number of electrons
a greater atomic
number
a greater atomic mass
a lesser number of protons
3. Write the number and name (if any) of the group (family) to which each of the following
elements belong:
Cesium Group 1A; alkali metal
Radium Group 2A; alkaline earth metal
Radon
Group 8A; noble gas
Chlorine Group 7A; halogen
Introductory Chemistry CHM 1025
Test #2
Section: 005 Name:__________________________
4. Write the correct name for the following elements:
a.
Sn:
tin
b.
Sb:
antimony
c.
Se
selenium
d.
Sr:
strontium
2 of 10
Date: March 16, 2015
5. Write the correct symbol for the following elements
a. Vanadium
V
b. Gallium
Ga
c. Germanium
Ge
d. Antimony
Sb
6. Write the correct name for each of the following compound.
a. Na3N
sodium nitride
b. NaNO3
sodium nitrate
c. NaNO2
sodium nitrite
7. Which pair of atoms constitutes a pair of isotopes of the same element?
a.
O2 & O3
b.
1
1
c.
12
6
d.
e.
H & 12H
C & 136 C
S 4 & S8
35
17
36
Cl & 17
Cl
8. What are the formulas for sulfite and chlorate ions, respectively?
a. SO4, ClO2
b. HSO4ClO4
c. SO32-, ClO3
d. SO4, ClO3
e. SO3, ClO4
10/21/2015
Introductory Chemistry CHM 1025
Test #2
Section: 005 Name:__________________________
9. Which formula/name pair is/are INCORRECT?
a.
Fe2S3
iron(II) sulfide
b.
FeSO3
iron(III) sulfite
c.
Fe2(SO3)3
iron(III) sulfate
d.
Fe2(SO4)3
iron(III) sulfate
e.
FeSO4
iron(II) sulfate
3 of 10
Date: March 16, 2015
10. The following table contains the names and formulas of various molecular compounds.
Choose the correct answers from the following to fill in the blanks:
Name
Formula
V2O5

Arsenic trichloride

N2O5

a. vanadium pentoxide, ArCl3, dinitrogen pentoxide
b. divanadium pentoxide, AsCl3, dinitrogen pentoxide
c. Vanadium(V) pentoxide, As(III)Cl3, nitrogen(III) pentoxide
d. Vanadium(V) pentoxide, AsCl3, dinitrogen pentoxide
e. Vanadium(II) pentoxide, As2Cl3, dinitrogen pentoxide
11. The following table contains the names and formulas of various ionic compounds.
Choose the correct answers from the following to fill in the blanks:
Name
Formula
Mercury(I) Sulfide

Ca3(PO4)2

Magnesium Chloride

a. HgS2, Calcium Phosphide, MgCl
b. Hg2S, Tricalcium diphosphate, MgCl
c. HgS, Calcium phosphate, MgCl2
d. Hg2S, Calcium phosphate, MgCl2
e. HgS, Calcium phosphite, MgCl2
12. Predict the formulas of the compounds formed between – strontium and nitrogen, and
aluminum and hydrogen:
a. SrN and AlH
b. SrN2 and AlH2
c. Sr2N3 and Al2H3
d. Sr3N2 and Al2H3
e. Sr3N2 and AlH3
10/21/2015
Introductory Chemistry CHM 1025
Test #2
Section: 005 Name:__________________________
13. Which of the following oxides of carbon exist?
4 of 10
Date: March 16, 2015
a. CO
b. CO2
c. CO3
d. a and b only
e. a, b, and c
14. How many atoms are present in 4.6 mol of carbon dioxide?[Show computation details]
a. 2.8  1024
b. 2.7  1024
c. 4.6  1024
d. 5.5  1024
e. 8.3  1024
6.022 1023 molecule of CO2
3 atoms
4.6 mols of CO2 

 8.3  1024 atom
mols of CO2
molecule of CO2
15. How many g of Cl atoms are present in 10.0 g of copper(I) chloride? [Show computation
details]
a. 3.6
b. 2.6
c. 2.8
d. 5.3
e. None of the above
1molCuCl
1molCl 35.453g Cl
10.0 g CuCl 


 3.58 gCl
 63.646  35.453 g CuCl molCuCl 1molC
16. What is the mass of N in 30.0 g of the amino acid, glycine, NH2CH2CO2H? [Show
computation details]
a. 11.2
b. 16.1
c. 9.40
d. 3.40
e. None of the above
30 g glycine 
1mole of glycine
1mol N
14.0067 g N


mol N
14.0067  12.011 2  1.008  5  15.999  2  g glycine 1mole of glycine
 5.6
10/21/2015
Introductory Chemistry CHM 1025
Test #2
5 of 10
Section: 005 Name:__________________________
Date: March 16, 2015
17. A grain of sand weighs 7.7x10-4g. How many formula units of silicon dioxide, SiO2 are in
one grain of sand? [Show computation details]
1mol SiO2
6.022  1023 formula units SiO2
7.7  104 g SiO2 

1mol SiO2
 28.0855  15.999  2 SiO2
 7.7  1018 formula units SiO2
18. How many ions of Mg2+ are present in 3.27  102 mol of Mg2+(aq)? [Show computation
details]
a. 1.84  1021
b. 1.84  1025
c. 1.97  1022
d. 1.97  1026
e. None of the above
3.27  102 mol Mg 2 
6.022  1023 particles of Mg 2 ions
 1.97  1022 ions
2
mol Mg
19. An organic compound gave the following elemental analysis: 60.59% C, 7.12% H.
Further analysis revealed oxygen to be the only other element present. Calculate its
empirical formula. [Show computation details]
a. C5H7O2
b. C17H2O9
basis : 100 g
C
60.59 g 
c. C5H7O
d. C8H2O4
e. C6H10O2
1mol
 5.04mol ; 5.04mol
 2.50 ; 2  5
2.01mol
12.011g
1mol
 7.06mol ; 7.06mol
 3.50 ; 2  7
2.01mol
1.008 g
1mol
O 32.29 g 
 2.01mol ; 2.01mol
 1.00 ; 2  2
2.01mol
15.999 g
Thus the formula is C 5 H 7O2
H
7.12 g 
10/21/2015
Introductory Chemistry CHM 1025
Test #2
6 of 10
Section: 005 Name:__________________________
Date: March 16, 2015
20. The empirical formula of ethylene, used in ripening bananas, is CH2. Its molar mass is
28.06 g/mol. What is the molecular formula of ethylene? [Show computation details]
a. CH2
empirical formula mass =12.011  1.008  2  14.03 amu per formula
unit or 14.03 g unit.
b. C2H4
Since the molar mass of ethylene is 2  14.03g, the molecular
formula is C 2 H 4
c. C3H6
d. C2H6
e. C2H2
21. Phosphoric acid is made from reaction P4O10 with water according to the following
skeletal reaction:
P4O10 g   H 2O l   H 3 PO4( aq )
a. Write the balanced equation:
[4pts]
P4O10 g   6 H 2O l   4 H 3 PO4( aq )
b. Name the each of the compounds in the reaction
P4O10 g 

tetraphosrus pentoxide
[4pts]
6 H 2O l   4 H 3 PO4( aq )
water
phosphoric acid
22. Magnesium forms a compound with nitrogen gas to form a solid compound.
a. What is its chemical formula based on their expected ionic charges: [2pts]
Mg3 N 2(s)
b. Write the balanced chemical equation for the reaction showing the process of
production of the compound starting with magnesium and nitrogen. [4pts]
23.
3 Mg s   N 2 g   Mg3 N 2(s)
10/21/2015
Introductory Chemistry CHM 1025
Test #2
7 of 10
Section: 005 Name:__________________________
Date: March 16, 2015
Given the reaction Na2S(aq) + 2 AgNO3 (aq) → Ag2 S(s) + 2 NaNO3(aq)
How many grams of Ag2 S will form when 3.94 g of AgNO3 and an excess of Na2S are
reacted together? [Show computation details]
3.94 g AgNO3 
1molAgNO3
1molAg2 S 107.8682  2  32.07  g Ag2 S


1molAg2 S
107.8682  14.0067  15.999  3 g AgNO3l 2molAgNO3
 2.87 gAg2 S
24. Combustion of aspirin (C7H6O3) with air (O2) produces carbon dioxide and water vapor.
The sum of the coefficients of this balanced equation is: [Show computation details]
C7 H 6O3  7O2  7CO2  3H 2O
C
H
O
7
7
6
6
3
14
14
3
The sum of the coefficients in the above equation is 1+7+7+3=18
25. Calculate the mass of AgCl that can be prepared from 200. g of AlCl3 and sufficient
AgNO3, using this equation:
3 AgNO3 + AlCl3  3 AgCl + Al(NO3)3:
200.g AlCl3 
1molAlCl3
3molAgCl 107.8682  35.453 g AgCl


1molAgCl
 26.98154  35.453  3 g AlCl3 1molAlCl3
 645 g AgCl
10/21/2015
Introductory Chemistry CHM 1025
Test #2
Section: 005 Name:__________________________
8 of 10
Date: March 16, 2015
Common Units and Their Equivalents
Length
1 kilometer (km)
1 meter (m)
1 foot (ft)
1 inch (in)
=
=
=
=
=
0.6214 mile (mi)
39.37 inches (in)
1.094 yards (yd)
30.48 centimeter (cm)
2.54 cm (Exact)
1 kilogram (kg)
1 pound (lb)
1 ounce (oz)
=
=
=
2.204 pounds (lb)
453.59 gram (g)
28.35 gram (g)
=
=
=
=
1000 milliliters (mL)
1000 cubic centimeter (cm3) or (cc)
1.057 quarts (qt)
3.785 liters (L)
=
 r 2 , where r is the radius
Mass
Volume
1 liter (L)
1 liter (L)
1 US gallon (gal)
Others
Area of a circle
4 3
 r , where r is the radius
3
Volume of a rectangular parallelepiped
= length x width x height
Volume of a sphere
=
Fundamental Physical Constants
Elementary charge
Avogadro number
Electron rest mass
Proton rest mass
Neutron rest mass
Charge-to-mass ratio for electron
Atomic mass unit
Electron radius
Gas constant
Acceleration due to gravity
e: 1.60217733  10-19 C
NA: 6.0221367  1023 particles/mol
me: 9.1093897  10-31 kg
mp: 1.6726231  10-27 kg
mn: 1.6749286  10-27 kg
{e/me} = 1.75880  1011 C/kg
amu:1.66057  10-27 kg
re: 2.81792  10-15 m
R: 0.082057 L·atm/K·mol (8.31451 m2 kg/s2 K mol)
g: 9.80665 m/s2
10/21/2015
Introductory Chemistry CHM 1025
Test #2
9 of 10
Date: March 16, 2015
Section: 005 Name:__________________________
Periodic Table of the Elements
1
H
IIA
1.0079
3
4
2.998 x 108 m/s
2
Speed of Light, c
=
Avagadro’s Number, N
=6.022 x 1023particles/mole
Rydberg Constant, RH =
2.18 x 10-18 J
IIIA
IVA
VA
VIA
VIIA
He
4.002602
5
6
7
8
9
10
Li
Be
B
C
N
O
F
Ne
6.941
9.012182
10.81
12.011
14.0067
15.9994
18.998403
20.180
11
12
13
14
15
16
17
18
Na
Mg
22.98977
24.305
19
20
IIIB
21
IVB
22
VB
23
VIB
24
VIIB
25
┌── VIIIB ──┐
26
27
28
IB
IIB
29
30
Al
Si
P
S
Cl
Ar
26.98154
28.0855
30.97376
32.07
35.453
39.948
31
32
33
34
35
36
K
Ca
Sc
Ti
V
Cr
Mn
Fe
Co
Ni
Cu
Zn
Ga
Ge
As
Se
Br
Kr
39.0983
40.08
44.95591
47.867
50.9415
51.996
54.93805
55.845
58.93320
58.6934
63.546
65.39
69.723
72.61
74.92159
78.96
79.904
83.80
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
Rb
Sr
Y
Zr
Nb
Mo
Tc
Ru
Rh
Pd
Ag
Cd
In
Sn
Sb
Te
I
Xe
85.4678
87.62
88.90585
91.224
92.90638
95.94
(98)
101.07
102.90550
106.42
107.8682
112.41
114.818
118.71
121.760
127.60
126.90447
131.29
55
56
57
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
Cs
Ba
La*
Hf
Ta
W
Re
Os
Ir
Pt
Au
Hg
Tl
Pb
Bi
Po
At
Rn
132.9054
137.33
138.9055
178.49
180.9479
183.84
186.207
190.23
192.217
195.08
196.96654
200.59
204.3833
207.2
208.98037
(209)
(210)
(222)
87
88
89
104
105
106
107
108
109
110
111
112
114
116
Fr
Ra
Ac
(223)
(226)
(227)
(289)
(292)
70
71
†
Rf
Db
Sg
Bh
Hs
Mt
Ds
(263)
(262)
(266)
(267)
(277)
(268)
(281)
(272)
(285)
58
59
60
61
62
63
64
65
*
66
67
68
69
Ce
Pr
Nd
Pm
Sm
Eu
Gd
Tb
Dy
Ho
Er
Tm
Yb
Lu
140.12
140.90765
144.24
(145)
150.36
151.96
157.25
158.92534
162.50
164.93032
167.26
168.93421
173.04
174.967
10/21/2015
Introductory Chemistry CHM 1025
Test #2
10 of 10
Date: March 16, 2015
Section: 005 Name:__________________________
†
90
91
92
93
94
95
96
97
98
99
100
101
102
103
Th
Pa
U
Np
Pu
Am
Cm
Bk
Cf
Es
Fm
Md
No
Lr
232.0381
231.03588
238.0289
(237)
(244)
(243)
(247)
(247)
(251)
(252)
(257)
(258)
(259)
(262)
10/21/2015