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Department of Mathematics, University of Wisconsin-Madison Math 114 Worksheet Sections 6.1-6.3 1. Convert each angle in degrees to radians. (a) 330◦ Solution: 330◦ = 330◦ * 11π π = radians 180◦ 6 (b) −180◦ Solution: −180◦ = −180◦ * π = −π radians 180◦ 2. Convert each angle in radians to degrees. (a) − 2π 3 Solution: − (b) − 2π 180◦ 2π =− * = −120◦ 3 3 π 3π 2 Solution: − 3π 180◦ 3π =− * = −270◦ 2 2 π 3. Find the radius r if the length of the arc of a circle of radius r is 6 centimeters and the central angle θ is 14 radian. Solution: l = rθ [θ in radians] =⇒ 6 = r ∗ 1 =⇒ r = 24 cm 4 4. Find the angle θ if the area of the arc of a circle of radius r is 8 square meters and the radius of the circle formed by the central angle θ is 6 meters. Solution: Area = θ θ θ 4 ∗ πr2 =⇒ 8 = ∗ 62 =⇒ 8 = ∗ 36 =⇒ θ = radians 2π 2 2 9 5. Find the exact value of each expression. Do not use a calculator. 1 (a) tan 45◦ cos 30◦ √ 3 3 = 2 2 √ Solution: tan 45◦ cos 30◦ = 1 ∗ (b) 5 cos 90◦ − 8 sin 270◦ Solution: 5 cos 90◦ − 8 sin 270◦ = 5 ∗ 0 − 8 sin(180◦ + 90◦ ) = 0 − (−8 sin 90◦ ) = 8 ∗ 1 =8 (c) 2 sin π4 + 3 tan 3π 4 √ √ √ 1 √ + 3 tan(π − π4 ) = 2 − 3 tan π4 = 2 − 3 ∗ 1 = 2 − 3 Solution: 2 sin π4 + 3 tan 3π 4 = 2∗ 2 6. The point (−1, −2) is on the terminal side of an angle θ in standard position. Find the exact value of each of the six trigonometric functions of θ. Solution: We are in the third quadrant, so all trigonometric functions except tan θ and cot θ will be neagtive. √ √ For the given angle, |Opposite| = 2, |Adjacent| = 1, and|Hypotenuse| = 22 + 12 = 5 √ sin θ = − √25 csc θ = − 25 √ cos θ = − √15 − sec θ = 5 tan θ = 2 cot θ = 12 7. Find the exact value of each expression. Do not use a calculator. (a) sin 390◦ Solution: sin 390◦ = sin(360◦ + 30◦ ) = sin 30◦ = 1 2 (b) sec 420◦ Solution: sec 420◦ = 1 1 1 1 = = = 1 =2 cos 420◦ cos(360◦ + 60◦ ) cos 60◦ 2 (c) cos 270◦ Solution: cos 270◦ = cos(180◦ + 90◦ ) = − cos 90◦ = 0 (d) sin2 40◦ + cos2 40◦ 2 Solution: sin2 40◦ + cos2 40◦ = 1 (e) tan 200◦ · cot 20◦ Solution: tan 200◦ · cot 20◦ = tan(180◦ + 20◦ ) · cot 20◦ = tan 20◦ · cot 20◦ = 1 (f) f (−a) if f (θ) = tan θ and f (a) = 2 Solution: f (−a) = tan(−a) = − tan a = −f (a) = −2 (g) f (a) + f (a + π) + f (a + 2π) if f (θ) = tan θ and f (a) = 2 Solution: f (a) + f (a + π) + f (a + 2π) = tan(a) + tan(a + π) + tan(a + 2π) = tan(a) + tan(a) + tan(a) = 3 tan(a) = 3f (a) = 3 ∗ 2 = 6 8. Find the exact value of each remaining trigonometric functions of θ if sin θ = − 23 , π < θ < 3π 2 . Solution: We are in the third quadrant, so all trigonometric functions except tan θ and cot θ will be negative. p √ Since sin θ = − 23 , if |Opposite| = 2, then |Hypotenuse| = 3, and |Adjacent| = (32 − 22 ) = 5 csc θ = − 23 √ tan θ = √25 cot θ = 25 √ cos θ = − 5 3 sec θ = − √35 9. Find the exact value of: sin 1◦ + sin 2◦ + sin 3◦ + ... + sin 358◦ + sin 359◦ Solution: sin 1◦ + sin 2◦ + sin 3◦ + ... + sin 358◦ + sin 359◦ = sin 1◦ + sin 2◦ + .... sin 179◦ + sin 180◦ ◦ ◦ ◦ + sin 359 + sin 358 + .... sin 181 = sin 1◦ + sin 2◦ + .... sin 179◦ + sin 180◦ ◦ ◦ ◦ + sin −1 + sin −2 + .... sin −179 = 0 + 0 + ......0 + sin 180◦ = 0 3