Download Genetics II practice quiz

Genetics II
Name:
1.
Date:
Which statement best describes amniocentesis?
1.
A.
Blood cells of an adult are checked for fragility.
B.
Saliva of a child is analyzed for amino acids.
C.
Urine of a newborn is analyzed for the amino acid phenylalanine.
D. Fluid surrounding an embryo is removed for cellular analysis.
2.
The charts show human chromosomes arranged in pairs.
2.
The chromosome numbered 1 through 22 are known as
A.
3.
ribosomes
B.
lysosomes
C.
centrosomes
D. autosomes
Traits that are controlled by genes found on an X-chromosome are said to be
A.
autosomal dominant
B.
autosomal recessive
C.
codominant
D. sex-linked
page 1
3.
Genetics II
4.
Shown is a pedigree chart. The chart shows that Sally is a carrier for red-green
color blindness.
4.
What is the probability that Barbara, who has no genes for color blindness, will
have a colorblind daughter?
A.
5.
0%
B.
25%
C.
50%
D. 100%
Which statement best describes Sally?
5.
A.
She has no genes for color blindness.
B.
She has one gene for color blindness located on an X-chromosome.
C.
She has one gene for color blindness located on a Y-chromosome.
D. She has two genes for color blindness.
6.
7.
Richard is colorblind because he inherited the trait from his
A.
father, Fred
B.
C.
mother, Kim
D. uncle, Joe
6.
grandfather, George
A man who has blood type AB marries a woman who has blood type B. This
couple would not normally have a child with which genotype?
A.
IAi
B.
IBIB
C.
I A BB
page 2
D. ii
7.
Genetics II
8.
What percentages can be expected in the o spring of a cross between a female
carrier for color blindness and a male with normal color vision?
A.
25% normal males, 25% colorblind males, 25% normal females, 25% carrier
females
B.
25% normal males, 25% colorblind males, 25% carrier females, 25%
colorblind females
C.
75% normal males, 25% carrier females
8.
D. 50% colorblind males, 50% colorblind females
9.
A man who has blood type A and a woman who has blood type B have a child
who had blood type O. The best explanation for this is that
A.
both parents are heterozygous for their blood type
B.
the woman is homozygous recessive for her blood type
C.
the alleles for blood type O are dominant over the alleles for the blood type A
and B
9.
D. blood type O is produced when the alleles represented by I A and I B are
combined
10.
Which statement concerning the concept of sex linkage in humans is correct?
A.
Hemophilia and color blindness are examples of recessive sex-linked traits.
B.
The genes involved in most sex-linked traits are located on the Y-chromosome.
C.
Sex-linked traits are observed more frequently in females than in males.
D. Sex-linkage was rst explained by James Watson as a result of his work with
DNA.
page 3
10.
Genetics II
11.
The chart shown displays the genotype of four babies with regard to blood type.
Which baby could not be the child of parents who both have type AB blood?
A.
12.
W
B.
X
C.
Y
D. Z
Baby
Genotype
W
IAIA
X
IBIB
Y
ii
Z
IAIB
The diagram shown represents a photographic enlargement of replicated
chromosomes from a fetal cell. For which technique would this photograph be used
to determine if the chromosomes of the fetus exhibit any genetic abnormalities?
A.
cleavage
B.
plasmolysis
C.
chemosynthesis
D. karyotyping
page 4
11.
12.
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Genetics II
1.
Answer:
D
2.
Answer:
D
3.
Answer:
D
4.
Answer:
A
5.
Answer:
B
6.
Answer:
C
7.
Answer:
D
8.
Answer:
A
9.
Answer:
A
10.
Answer:
A
11.
Answer:
C
12.
Answer:
D
01/17/2013