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Name _______________________________________ Date ___________________ Class __________________ LESSON 6-3 Practice C Conditions for Parallelograms 1. In parallelogram ABCD, AC 3 13 and BD 5 5 . AC is contained in the line 11 3 with equation y x 2, and BD is contained in the line with equation y x 6. 2 2 If A and B are both in Quadrant I, find the vertices of ABCD. (Hint: All coordinates are in integers.) Use the figure for Exercises 2 and 3. A B and C D. 2. Name the conditions under which the figure would be a parallelogram. ________________________________________________________________________________________ 3. Tell which sides of the figure must be parallel under all conditions. Explain your answer. 4. Sketch a parallelogram with perpendicular diagonals. Tell which sides and angles of the parallelogram have to be congruent. Explain your answer. 5. Sketch a parallelogram with perpendicular congruent diagonals. Tell which sides and angles of the parallelogram have to be congruent. Explain your answer. 6. Find the measure(s) of the parallelogram’s angles in your sketch for Exercise 5. ________ Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 6-21 Holt Geometry 7. PQ RS 26 ; QR PS 5 2 ; PQRS is a parallelogram. LESSON 6-3 Practice A 8. Possible answer: UV TW 2 5 ; slope of UV slope of TW 2; TUVW is a parallelogram. Practice C 1. W Y and X Z 2. WX ZY and WZ XY 3. Possible answer: W is supplementary to X and to Z. 1. A(4, 4), B(2, 5), C(2, 5), D(0, 26) 2. Possible answer: A C 4. Possible answer: WX ZY and WX ZY 3. AB || CD ; possible answer: because A B and C D and the sum of the interior angle measures of a quadrilateral is 360°, 2mA 2mD 360° or 2(mA mD) 360°. Therefore mA mD 180°. A and D are supplementary, so by the Converse of the Same-Side Interior Angles Theorem, AB || CD 5. WY and XZ bisect each other. 6. WX ZY and WZ XY 7. 8. 5; 5 10. 4 9. 4. All four sides are congruent, and the two pairs of opposite angles are congruent; possible answer: because the diagonals are perpendicular, all four angles created by the intersecting diagonals are right angles and therefore congruent. And because the diagonals bisect each other, all four of the right triangles are congruent by SAS. By CPCTC, all four of the parallelogram’s sides must be congruent. The two pairs of opposite angles are congruent as for any parallelogram. 4 4 ; 3 3 11. BC 12. BC moves up or down but stays vertical. Practice B 1. ABCD is a parallelogram. mA mC 72 and mB mD 108 EFGH is not a parallelogram. HI 8.6 and FI 7.6. EG does not bisect HF . 3. No, the diagonals do not necessarily bisect each other. 5. 4. Yes, the triangles with numbered angles are by AAS. By CPCTC, the parallel sides are congruent. 5. No, x x may not be 180. 6. slope of JK slope of LM 1; slope 2 of KL slope of JM 3 ; JKLM is a parallelogram. All four sides are congruent, and all four angles are congruent; possible answer: the sides are congruent for the same reasons given in Exercise 4. But because the diagonals are congruent and bisected, each right triangle.created by the diagonals is an isosceles right triangle. The acute angles of these triangles have measure 45°, so all the angles of the Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. A57 Holt Geometry Name _______________________________________ Date ___________________ Class __________________ parallelogram have measure 90°. 6. 90° Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 6-20 Holt Geometry