Download Complete Soultions to Practice Test 16

COMPASS
Practice Test 16
1. Which equation best describes
the data in this table?
A. 2X + Y = -12
B. 2X = -6
X
Y
-3
-6
0
-4
3
-2
C. 2X - 3Y = 12
D. 2Y + 3X = 12
E. -3X + Y = -8
One way to get the answer would be
to plug each ordered pair into each equation
until you found the one equation that
all of the ordered pairs work with.
1 Which equation best describes
the data in this table?
Calculate the slope
2  (4) 2
m

30
3
Plug into Point Slope
y  y1  m( x  x1 )
2
y  (4)  ( x  0)
3
Answer C
X
Y
-3
-6
0
-4
3
-2
Write in
standard
form.
2
y4 x
3
3 y  12  2 x
2 x  3 y  12
2 x  3 y  12
2
For all x,
18
A. 9
18
x 4
2
x 4
2
6
B. 3
18  6 x2  4
C. 5
D. 7
18 6 x  4

6
6
E. 4
3 x 4
2
2
6 x ?
2
 3
2


x 4
2
9  x2  4
4
4
5 x
2
Answer C

2
18
32

2
3
3
A.
2
D.
14
5
B.
5 10
E.
17 2
6
9
6

4
2
C.
6
18
32

3
2
3
9(2)
16(2) 3 2 4 2
18
32





2
3
2
3
2
3
(3)3 2 (2)4 2 9 2 8 2
17 2





(3)2
(2)3
6
6
6
Answer E
4
For all a  b, b  0,
A.
2
10a
2
ab  b
5a
b
2a
a b
5(a  b)
B.
2b
5b
D.
2(a  b)
2b
C.
5(a  b)
E. ab  b
2
10a
2
4
5a
b
2a
a b
For all a  b, b  0,
5a
b 
2a
a b
5a(a  b)
2ab
5(a  b)

2b
Answer B
5
Which of these equations defines a line
that is parallel to the line given by the
equation y = -0.5x + 5?
1
A. y  x  5
2
1
B. y  x  2
5
2
C. y  x  1
5

1
D. y  x  7
2
E. y  1 x  2
5
5
Which of these equations defines a line
that is parallel to the line given by the
equation y = -0.5x + 5?
1. Identify the slope of
the line.
2. Find the equation of
the line with the
same slope.
Answer D
y  0.5 x  5
1
 m1  0.5  
2
So which
equation has a
slope of -0.5?
1
y   x7
2
6
In the standard (x, y ) plane, what is the distance


between 3 3,  1 and
A.
6
B.
9
C.
3 3
6

3, 2 ?
D.
27
E. 9  9 3
6
In the standard (x, y ) plane, what is the distance




between 3 3,  1 and 6 3, 2 ?
Use the distance
formula.
d

6
d

 x2  x1    y2  y1 
2
3  3 3   2  (1)  
2
2
3 3 
2
  3
 9 (3)    9  27  9  36
Answer A
2
6
2
7
What is the solution of the system of equations
below?
x  2 y  7a
3x  2 y  5a
A.
 3a, 2a 
B.
 3a, 2a 
C.
 4, 4
D.
 4,  4
E.
 2, 0 
7
What is the solution of the system of equations
below?
x  2 y  7a
3x  2 y  5a
4x
(3ax)  2 y  7a
3a
 3a
2 y  4a
 12a
4 x 12a

4
4
2 y 4a

2
2
x  3a
y  2a
Answer A
(3a, 2a)
x, ( x  3)  3(2 x  3)  ?
2
8 For all
A.
x
2
B. x  12 x
2
C.
x  6x
2
D.
x  12 x  18
E.
x  12 x  18
2
2
8 For all
x, ( x  3)  3(2 x  3)  ?
2
( x  3)  3(2 x  3)  ( x  3)( x  3)  3(2 x  3)
2
 x  6x  9  6x  9
2
x
Answer A
2
9)
8
-2/3
2
3
=? 8 
1
8
A.
4
B.
1
4
C.
4
2
3

1
 
3
2

8
D.
16
3
E.
1
4
1
 2
2
1

4
x  kx  24
 x  2?
x  12
2
10
What is the value of k when
A.
10
B.
10
C.
14
D.
14
E.
2
Answer C
x  kx  24
 x  2?
x  12
2
10
What is the value of k when
x  kx  24
 x2
x  12
2
x  kx  24   x  2  x  12 
2
x  kx  24  x  12 x  2 x  24
2
2
x  kx  24  x  14 x  24
2
2
 x  24 x  24
2
2
kx   14 x
kx  14x
 kx 14 x

x
x
k  14
Answer C