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7-6 7-6 Choosing Choosinga aFactoring FactoringMethod Method Warm Up Lesson Presentation Lesson Quiz Holt Holt McDougal Algebra 1Algebra Algebra11 Holt McDougal 7-6 Choosing a Factoring Method Objectives Choose an appropriate method for factoring a polynomial. Combine methods for factoring a polynomial. Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Recall that a polynomial is in its fully factored form when it is written as a product that cannot be factored further. Holt McDougal Algebra 1 7-6 Choosing a Factoring Method To factor a polynomial completely, you may need to use more than one factoring method. Use the steps below to factor a polynomial completely. Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Example 2A: Factoring by GCF and Recognizing Patterns Factor 10x2 + 48x + 32 completely. Check your answer. 10x2 + 48x + 32 2(5x2 + 24x + 16) Factor out the GCF. 2(5x + 4)(x + 4) Factor remaining trinomial. Check 2(5x + 4)(x + 4) = 2(5x2 + 20x + 4x + 16) = 10x2 + 40x + 8x + 32 = 10x2 + 48x + 32 Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Example 2B: Factoring by GCF and Recognizing Patterns Factor 8x6y2 – 18x2y2 completely. Check your answer. 8x6y2 – 18x2y2 2x2y2(4x4 – 9) Factor out the GCF. 4x4 – 9 is a perfect-square trinomial of the form a2 – b2. 2x2y2(2x2 – 3)(2x2 + 3) a = 2x, b = 3 Check 2x2y2(2x2 – 3)(2x2 + 3) = 2x2y2(4x4 – 9) = 8x6y2 – 18x2y2 Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Check It Out! Example 2a Factor each polynomial completely. Check your answer. 4x3 + 16x2 + 16x 4x3 + 16x2 + 16x 4x(x2 + 4x + 4) 4x(x + 2)2 Factor out the GCF. x2 + 4x + 4 is a perfect-square trinomial of the form a2 + 2ab + b2. a = x, b = 2 Check 4x(x + 2)2 = 4x(x2 + 2x + 2x + 4) = 4x(x2 + 4x + 4) = 4x3 + 16x2 + 16x Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Check It Out! Example 2b Factor each polynomial completely. Check your answer. 2x2y – 2y3 2y(x2 – y2) Factor out the GCF. 2y(x2 – y2) is a perfect-square trinomial of the form a2 – b2. 2y(x + y)(x – y) a = x, b = y 2x2y – 2y3 Check 2y(x + y)(x – y) = 2y(x2 + xy – xy – y2) = 2x2y +2xy2 – 2xy2 – 2y3 = 2x2y – 2y3 Holt McDougal Algebra 1 7-6 Choosing a Factoring Method If none of the factoring methods work, the polynomial is said to be unfactorable. Helpful Hint For a polynomial of the form ax2 + bx + c, if there are no numbers whose sum is b and whose product is ac, then the polynomial is unfactorable. Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Example 3A: Factoring by Multiple Methods Factor each polynomial completely. 9x2 + 3x – 2 9x2 + 3x – 2 ( x + )( x + ) Factors of 9 Factors of –2 1 and –2 1 and 9 1 and –2 3 and 3 –1 and 2 3 and 3 (3x – 1)(3x + 2) Holt McDougal Algebra 1 The GCF is 1 and there is no pattern. a = 9 and c = –2; Outer + Inner = 3 Outer + Inner 1(–2) + 9(1) = 7 3(–2) + 3(1) = –3 3(2) + 3(–1) = 3 7-6 Choosing a Factoring Method Example 3B: Factoring by Multiple Methods Factor each polynomial completely. 12b3 + 48b2 + 48b The GCF is 12b; (b2 + 4b + 4) is a perfect-square 12b(b2 + 4b + 4) trinomial in the form of (b + )(b + ) a2 + 2ab + b2. Factors of 4 Sum 1 and 4 5 2 and 2 4 a = 2 and c = 2 12b(b + 2)(b + 2) 12b(b + 2)2 Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Example 3C: Factoring by Multiple Methods Factor each polynomial completely. 4y2 + 12y – 72 4(y2 + 3y – 18) (y + )(y + ) Factor out the GCF. There is no pattern. b = 3 and c = –18; look for factors of –18 whose sum is 3. Factors of –18 Sum –1 and 18 17 –2 and 9 7 –3 and 6 3 The factors needed are –3 and 6 4(y – 3)(y + 6) Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Example 3D: Factoring by Multiple Methods. Factor each polynomial completely. (x4 – x2) x2(x2 – 1) Factor out the GCF. x2(x + 1)(x – 1) x2 – 1 is a difference of two squares. Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Check It Out! Example 3a Factor each polynomial completely. 3x2 + 7x + 4 3x2 + 7x + 4 ( x + )( x + ) Factors of 3 Factors of 4 1 and 4 3 and 1 2 and 2 3 and 1 4 and 1 3 and 1 (3x + 4)(x + 1) Holt McDougal Algebra 1 a = 3 and c = 4; Outer + Inner = 7 Outer + Inner 3(4) + 1(1) = 13 3(2) + 1(2) = 8 3(1) + 1(4) = 7 7-6 Choosing a Factoring Method Check It Out! Example 3b Factor each polynomial completely. 2p5 + 10p4 – 12p3 2p3(p2 + 5p – 6) (p + )(p + ) Factor out the GCF. There is no pattern. b = 5 and c = –6; look for factors of –6 whose sum is 5. Factors of – 6 Sum – 1 and 6 5 The factors needed are –1 and 6 2p3(p + 6)(p – 1) Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Check It Out! Example 3c Factor each polynomial completely. 9q6 + 30q5 + 24q4 3q4(3q2 ( q+ Factor out the GCF. There is no pattern. + 10q + 8) )( q+ ) Factors of 3 Factors of 8 1 and 8 3 and 1 2 and 4 3 and 1 4 and 2 3 and 1 3q4(3q + 4)(q + 2) Holt McDougal Algebra 1 a = 3 and c = 8; Outer + Inner = 10 Outer + Inner 3(8) + 1(1) = 25 3(4) + 1(2) = 14 3(2) + 1(4) = 10 7-6 Choosing a Factoring Method Check It Out! Example 3d Factor each polynomial completely. 2x4 + 18 2(x4 + 9) Factor out the GFC. x4 + 9 is the sum of squares and that is not factorable. 2(x4 + 9) is completely factored. Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Holt McDougal Algebra 1 7-6 Choosing a Factoring Method Lesson Quiz Tell whether the polynomial is completely factored. If not, factor it. 1. (x + 3)(5x + 10) 2. 3x2(x2 + 9) no; 5(x+ 3)(x + 2) completely factored Factor each polynomial completely. Check your answer. 3. x3 + 4x2 + 3x + 12 4. 4x2 + 16x – 48 4(x + 6)(x – 2) (x + 4)(x2 + 3) 5. 18x2 – 3x – 3 3(3x + 1)(2x – 1) 6. 18x2 – 50y2 2(3x + 5y)(3x – 5y) 7. 5x – 20x3 + 7 – 28x2 (1 + 2x)(1 – 2x)(5x + 7) Holt McDougal Algebra 1