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Point-Slope Form Algebra 1 Learning Targets • I can interpret an equation in point-slope form • I can write an equation in point-slope form given the correct information Something to think about… • You are given two point: (1, 3) (-4, -12) – For us to write an equation through these points in slope-intercept (y = ax + b) form we need to know the: slope y-intercept – We can find the slope but the y-intercept can be difficult. – There is another form of a linear equation that can help!!!! Slope-Intercept Form • y = ax + b a = slope b = y-intercept Point-Slope Form • y = y1 + a(x – x1) a = slope (x1 , y1) = any given point Try one • You know a line has a slope of 3 and a point on that line is (6, 10), make an equation in point slope form. 10 + ____(x 3 6 y = ___ - ____) y1 a y = 10 + 3(x – 6) x1 Try one • You know a line has a slope of -1/3 and a point on that line is (-9, -4.5), make an equation in point slope form. -9 y =-4.5 ___ +-1/3 ____(x - ____) y1 a y = -4.5 – 1/3(x + 9) x1 Try one • You know a line has a slope of 0 and a point on that line is (7, -2), make an equation in point slope form. -2 + ____(x 0 7 y = ___ - ____) y1 y = -2 a x1 Examples 1. y = 5 + ½ (x – 2) Slope: ½ 2. y = -4 (x – 1) – 2 Slope: -4 3. y = 2/3 (x + 6) – 8 Slope: 2/3 y = ½x + 4 Point: (2, 5) y = -4x + 2 Point: (1, -2) y = 2/3 x – 4 Point: (-6, 2) Finding Slope • You are given two points: (-11, 0) (-7, 2) – Make and equation Slope = ½ Point = (-11, 0) or (-7, 2) Y = 0 + ½ (x + 11) or y = 2 + ½ (x + 7)