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Quadratic Equations MTED 301 May 7, 2008 Diane Yum Quadratic Equation An equation that could be written as ax2+bx+c=0 Quadratic Equation An equation that could be written as ax2+bx+c=0 Standard form of a quadratic equation ax2+bx+c=0 Quadratic Equation An equation that could be written as ax2+bx+c=0 Standard form of a quadratic equation ax2+bx+c=0 - The quadratic is on the left and 0 is on the right. - Moreover, it is standard for the leading coefficient A to be positive. 3 different ways to solve a quadratic equation 3 different ways to solve a quadratic equation Solve by Factoring 3 different ways to solve a quadratic equation Solve by Factoring Solve by Completing the Square 3 different ways to solve a quadratic equation Solve by Factoring Solve by Completing the Square Solve by Using “Quadratic Formula” Solving by Factoring To solve a quadratic equation, Put all terms on one side of the equal sign, leaving zero on the other side (Standard Form) ② Factor ③ Set each factor equal to zero ④ Solve each of these equations ⑤ Check by inserting your answer in the original equation ① Example of factoring Ex) Solve for y: y2 = -6y – 5 First, change the equation into the standard form: y2 + 6y + 5 = 0 Factoring, (y+5) (y+1) = 0 Y+5 = 0 or y+1 = 0 Y = -5 or y = -1 Check your answer (-5)2 = -6(-5) – 5 or (-1)2 = -6(-1) -5 25 = 30 – 5 1 = 6-5 25 = 25 1 = 1 You got it right Solving by Completing the Square Completing the Square: Finding something to add to a quadratic to make it a perfect square Expression: (x+k)2 Applying our formula for squaring a binomial, we get (x+k)2 = x2 + 2xk + k2 So if you have an expression of the form x2+bx and you want to find something to add to it to make it a perfect square, then you need to Divide b by 2 to get k Square k to get k2 9 2 81 9 Ex) y2 – 9y ( ) 92 2 4 2 81 9 2 2 y 9y (y ) 4 2 Example of Completing the Square Ex) Solve x2 + 6x – 7 = 0 by completing the s quare 1) x2 + 6x – 7 = 0 2) x2 + 6x =7 3) (6/2)2 = 9 4) x2 + 6x + 9 = 7 + 9 5) (x + 3 )2 = 16 6) x+3 = +4, -4 7) x = -3 + 4 and -3 – 4 8) x = +1 and -7 Check your answer x2 +6x –7=0 (1)2 + 6(1) – 7 = 0 1 + 6 –7=0 and You got it right again x2 + 6x – 7 = 0 (-7)2 + 6(-7) – 7 = 0 49 – 42 - 7 = 0 Solving by Quadratic Formula Quadratic Formula : b b 4ac x 2a 2 Easy Steps to solve by quadratic formula 1) 2) 3) Find a, b, and c in the standard form Substitute numbers of a, b, and c in the quadratic formula Find the value of x Example of Quadratic Formula Ex) Solve the equation of 2x2 + 5x = 10 by using a quadratic formula ① Rewrite the equation into a standard form 2x2 + 5x – 10 = 0 ② Identify the values of a, b, and c a = 2, b = 5, c = -10 ③Substitute these values into the Quadratic Formula Substitution 5 (5) 4(2)(10) 5 25 80 5 105 x 2(2) 4 4 2 5 105 5 105 x and 4 4 You can substitute the x values into the o riginal equation to check the answer! Homework Due : Next Class Meeting Solve each equation by factoring, completing the square, or the quadratic formula. Solve (x+1)(x-3) = 0 2 Solve x + x – 4 = 0 Solve x2 – 3x – 4 = 0 2 Solve 6x + 11x – 35 = 0 Solve x2 – 48 = 0