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5.2 Properties of Parabolas
1. Graphing Parabolas
2. Finding Maximum and Minimum
Values
1) Graphing Parabolas
y = ax2 + bx + c
When b = 0, it becomes…
y = ax2 + c
The vertex of a graph of y = ax2 + c is
the y-intercept, (0,
c)
1) Graphing Parabolas
Example 1:
2
y

2
x
1
Graph
1) Graphing Parabolas
Example 1:
2
y

2
x
1
Graph
Step 1: Graph the vertex at (0, -1).
Step 2: Make a table of values using points on one side
of x-axis.
Step 3: Sketch the curve.
1) Graphing Parabolas
Example 1:
2
y

2
x
1
Graph
x
1
2
3
4
y
1) Graphing Parabolas
Example 1:
2
y

2
x
1
Graph
x
1
2
3
4
y
2(1)2 – 1 = 1
2(2)2 – 1 = 7
2(3)2 – 1 = 17
2(4)2 – 1 = 31
1) Graphing Parabolas
Take advantage of
Example 1:
2
y

2
x
1
Graph
corresponding
points to graph the other side of the
parabola.
y
35
x
1
2
3
4
y
1
7
17
31
30
25
20
15
10
5
0
-5
-4
-3
-2
-1
0
-5
1
2
3
4
5
1) Graphing Parabolas
For the equation y
= ax2 + bx + c,
the axis of symmetry is at
b

2a
1) Graphing Parabolas
Example 2:
Graph y = x2 – 2x – 3.
1) Graphing Parabolas
Example 2:
Graph y = x2 – 2x – 3.
Step 1: Find the axis of symmetry.
Axis of symmetry:
b
(2)


1
2a
2(1)
Equation for the axis of symmetry: x
=1
1) Graphing Parabolas
Example 2:
Graph y = x2 – 2x – 3.
Step 2: Find the vertex.
Sub x = 1 into the equation, solve for y.
y = (1)2 – 2(1) – 3
y = -4
The vertex is
at (1, -4).
1) Graphing Parabolas
Example 2:
Graph y = x2 – 2x – 3.
Step 3: Plot points and sketch the graph.
x
1
2
3
4
y
-4
1) Graphing Parabolas
Example 2:
Graph y = x2 – 2x – 3.
Step 3: Plot points and sketch the graph.
x
1
2
3
4
y
-4
(2)2 – 2(2) – 3 = -3
(3)2 – 2(3) – 3 = 0
(4)2 – 2(4) – 3 = 5
1) Graphing Parabolas
Example 2:
Graph y = x2 – 2x – 3.
y
-3
-2
6
5
4
3
2
1
0
-1 -1 0
-2
-3
-4
-5
1
2
3
4
5
2) Finding Maximum and Minimum
Values
The maximum or minimum occurs at the vertex..
If a < 0, the graph opens DOWN and the
vertex is a MAXIMUM.
If a > 0, the graph opens UP and the vertex is
a MINIMUM.
Homework
p. 248 #1-3, 10-12, 22-24, 31, 37-39, 45
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