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Work, Energy, and Power
Chapter 5
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Work

Work – the product of the magnitudes of
the component of force (along the
direction of displacement) and the
displacement
W = Fd

Work is done only when components of a
force are parallel to a displacement
Work (cont.)

Work is done only when components of a
force are parallel to a displacement
Work (cont.)

Work is done only when components of a
force are parallel to a displacement
W = F d (cos θ)
 Wnet = Fnet d (cos θ)

Sample Problem 5A

p. 169
How much work is done on a vacuum cleaner pulled 3.0 m by a
force of 50.0 N at an angle of 30.0o above the horizontal?
Given: F = 50.0 N, d = 3.0 m, θ = 30.0o
 Unknown: W
 Equation: W = F d (cos θ)
 Substitute: W = 50 N(3m) cos 30
 Solution: W = 130 J

Practice 5A




1. A tugboat pulls a ship with a constant net horizontal force of
5.00 x 103 N and causes the ship to move through a harbor. How
much work is done on the ship if it moves a distance of 3.00 km?
(1.50 x 107 J)
2. A weight lifter lifts a set of weights a vertical distance of 2.00 m.
If a constant net force of 350 N is exerted on the weights, what is
the net work done on the weight? (7.0 x 102 J)
3. A shopper in a supermarket pushes a cart with a force of 35 N
directed at an angle of 250 downward from the horizontal. Find the
work done by the shopper on the cart as the shopper moves along
a 50.0 m length of aisle. (1.6 x 103 J)
4. If 2.0 J of work is done in raising a 180 g apple, how gar is it
lifted? (1.1 m)
The sign of work is important.

Work is a scalar quantity and can be
positive or negative.

Work is positive when the component of
force is in the same direction as the
displacement.

Work is negative when the force is in the
direction opposite the displacement.
Homework

In your notebook, write and answer the
section review questions (1-6) on page
171 of your Physics textbook.