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Ch. 5 – Applications of Derivatives 5.6 – Related Rates • Ex: Find the derivative of the volume of a sphere with respect to its radius. – Differentiate each variable with respect to r! 4 V r3 3 dV 2 dr 4 r dr dr dV 4 r 2 dr • Ex: Find the derivative of the volume of a sphere with respect to time. – Now differentiate each variable with respect to t! 4 V r3 3 dV 2 dr 4 r dt dt – This equation relates two rates, dV/dt and dr/dt, so this problem is a related rates problem! – Related Rates problems are useful when observing the change in variables over time! • Ex: Find an equation that relates the volume of a cylinder over time with its radius and height over time. – Use Product Rule! V r 2h dV dr 2 dh ( r ) 2 r h dt dt dt dV dr 2 dh r 2 rh dt dt dt • Ex: A spherical kickball is being inflated. When the radius is 3 in., the volume is changing at a rate of 2π in/s. What is the rate at which the radius is growing when the radius is 3 in? – Always label what you know and what you need to find... – ...then set up an equation that relates all of your rates. You’ll probably need to differentiate an existing equation with respect to t. 4 3 V r 3 Know @ r 3 in, dV in 2 dt s dV 2 dr 4 r dt dt Find dr @r 3 dt – Plug in the known values ONLY AFTER DIFFERENTIATING. Otherwise, you will be differentiating constants, not variables. dr 2 4 (3) dt 2 dr 1 in dt 18 s • Ex: A man is 18 m away from a child. The child releases a balloon that rises at a rate of 4 m/s. How quickly is the angle of elevation from the man to the balloon increasing 6 s after the child releases the balloon? B – Draw and label a picture to help you! – Find an equation that relates your rates... Know @ t 6 s, dh m 4 dt s h tan 18 θ M d 1 dh (sec ) dt 18 dt 2 – At t = 6 , the height of the balloon will be... – ...24 m, and using tanθ = 24/18, θ will be... – ...≈.927 radians! Now plug n’ chug! d 1 sec (.927) (4) dt 18 2 h d radians .08 dt s 18 m C Find d @t 6 dt