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Equations – Success if you can do these
3x = 6
4x + 2 = 3x + 7
x/4 = 2
5x – 3 = 7 + 3x
x + 3 = 17
3(x + 2) = 12
x – 4 = 13
4(x + 5) = 32
3x + 4 = 25
3(2x – 2) = 2(x + 6)
4x – 3 = 17
4(3x + 5) = 2(x + 15)
How to solve the
4(x + 3) = 40
type of equation
The 4,
3 and
40 could be any
numbers
4(x + 3) = 40
Get rid of
the brackets
4(x + 3) = 40
X x + 3
4 4x + 12
4x + 12 = 40
Get rid of
the brackets
4(x + 3) = 40
X x + 3
4 4x + 12
4x + 12 = 40
Get rid of
the brackets
Subtract 12
from both
sides
4(x + 3) = 40
X x + 3
4 4x + 12
Get rid of
the brackets
Subtract 12
from both
sides
4x + 12 = 40
4x + 12 – 12 = 40 – 12
4(x + 3) = 40
X x + 3
4 4x + 12
Get rid of
the brackets
Subtract 12
from both
sides
4x + 12 = 40
4x + 12 – 12 = 40 – 12
4x =28
4(x + 3) = 40
X x + 3
4 4x + 12
Get rid of
the brackets
Subtract 12
from both
sides
4x + 12 = 40
4x + 12 – 12 = 40 – 12
Divide both sides by 4
4x =28
4(x + 3) = 40
X x + 3
4 4x + 12
Get rid of
the brackets
Subtract 12
from both
sides
4x + 12 = 40
4x + 12 – 12 = 40 – 12
Divide both sides by 4
4x =28
4x/4 = 28/4
4(x + 3) = 40
X x + 3
4 4x + 12
Get rid of
the brackets
Subtract 12
from both
sides
4x + 12 = 40
4x + 12 – 12 = 40 – 12
Divide both sides by 4
4x =28
4x/4 = 28/4 = 7
Solve this equation
5(x + 2) = 3(x + 10)
5(x + 2) = 3(x + 10)
Get rid of
the brackets
5(x + 2) = 3(x + 10)
5x + 10 = 3x + 30
Get rid of
the brackets
5(x + 2) = 3(x + 10)
Get rid of
the brackets
5x + 10 = 3x + 30
5x + 10 –10 = 3x + 30 –10
Subtract 10
from both sides
5(x + 2) = 3(x + 10)
Get rid of
the brackets
5x + 10 = 3x + 30
5x + 10 –10 = 3x + 30 –10
5x = 3x + 20
Subtract 10
from both sides
5(x + 2) = 3(x + 10)
Get rid of
the brackets
5x + 10 = 3x + 30
5x + 10 –10 = 3x + 30 –10
5x = 3x + 20
Subtract 10
from both sides
Subtract 3x
from both sides
5(x + 2) = 3(x + 10)
Get rid of
the brackets
5x + 10 = 3x + 30
5x + 10 –10 = 3x + 30 –10
5x = 3x + 20
5x – 3x = 3x + 20 –3x
2x = 20
Subtract 10
from both sides
Subtract 3x
from both sides
5(x + 2) = 3(x + 10)
Get rid of
the brackets
5x + 10 = 3x + 30
5x + 10 –10 = 3x + 30 –10
5x = 3x + 20
Subtract 10
from both sides
Subtract 3x
from both sides
5x – 3x = 3x + 20 –3x
2x = 20
Divide both sides by 2
5(x + 2) = 3(x + 10)
Get rid of
the brackets
5x + 10 = 3x + 30
5x + 10 –10 = 3x + 30 –10
5x = 3x + 20
Subtract 3x
from both sides
5x – 3x = 3x + 20 –3x
2x = 20
Divide both sides by 2
2x/2 = 20/2
x = 10
Subtract 10
from both sides
Remember, always do the same thing to both sides.
Felix is checking that you do this properly.
5x + 3 = 43 + 3x
5x + 3 – 3 = 43 – 3
5x = 40 + 3x
5x – 3x = 40 + 3x – 3x
2x = 40
x = 20
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