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Equations – Success if you can do these 3x = 6 4x + 2 = 3x + 7 x/4 = 2 5x – 3 = 7 + 3x x + 3 = 17 3(x + 2) = 12 x – 4 = 13 4(x + 5) = 32 3x + 4 = 25 3(2x – 2) = 2(x + 6) 4x – 3 = 17 4(3x + 5) = 2(x + 15) How to solve the 4(x + 3) = 40 type of equation The 4, 3 and 40 could be any numbers 4(x + 3) = 40 Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40 Get rid of the brackets 4(x + 3) = 40 X x + 3 4 4x + 12 4x + 12 = 40 Get rid of the brackets Subtract 12 from both sides 4(x + 3) = 40 X x + 3 4 4x + 12 Get rid of the brackets Subtract 12 from both sides 4x + 12 = 40 4x + 12 – 12 = 40 – 12 4(x + 3) = 40 X x + 3 4 4x + 12 Get rid of the brackets Subtract 12 from both sides 4x + 12 = 40 4x + 12 – 12 = 40 – 12 4x =28 4(x + 3) = 40 X x + 3 4 4x + 12 Get rid of the brackets Subtract 12 from both sides 4x + 12 = 40 4x + 12 – 12 = 40 – 12 Divide both sides by 4 4x =28 4(x + 3) = 40 X x + 3 4 4x + 12 Get rid of the brackets Subtract 12 from both sides 4x + 12 = 40 4x + 12 – 12 = 40 – 12 Divide both sides by 4 4x =28 4x/4 = 28/4 4(x + 3) = 40 X x + 3 4 4x + 12 Get rid of the brackets Subtract 12 from both sides 4x + 12 = 40 4x + 12 – 12 = 40 – 12 Divide both sides by 4 4x =28 4x/4 = 28/4 = 7 Solve this equation 5(x + 2) = 3(x + 10) 5(x + 2) = 3(x + 10) Get rid of the brackets 5(x + 2) = 3(x + 10) 5x + 10 = 3x + 30 Get rid of the brackets 5(x + 2) = 3(x + 10) Get rid of the brackets 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 Subtract 10 from both sides 5(x + 2) = 3(x + 10) Get rid of the brackets 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 Subtract 10 from both sides 5(x + 2) = 3(x + 10) Get rid of the brackets 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 Subtract 10 from both sides Subtract 3x from both sides 5(x + 2) = 3(x + 10) Get rid of the brackets 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 5x – 3x = 3x + 20 –3x 2x = 20 Subtract 10 from both sides Subtract 3x from both sides 5(x + 2) = 3(x + 10) Get rid of the brackets 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 Subtract 10 from both sides Subtract 3x from both sides 5x – 3x = 3x + 20 –3x 2x = 20 Divide both sides by 2 5(x + 2) = 3(x + 10) Get rid of the brackets 5x + 10 = 3x + 30 5x + 10 –10 = 3x + 30 –10 5x = 3x + 20 Subtract 3x from both sides 5x – 3x = 3x + 20 –3x 2x = 20 Divide both sides by 2 2x/2 = 20/2 x = 10 Subtract 10 from both sides Remember, always do the same thing to both sides. Felix is checking that you do this properly. 5x + 3 = 43 + 3x 5x + 3 – 3 = 43 – 3 5x = 40 + 3x 5x – 3x = 40 + 3x – 3x 2x = 40 x = 20