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Transcript 
Chapter 7: Unit Conversions
(Proportion method)
If a student weighs 80 kg, how
much does he weigh in pounds?
Step 1. Find a conversion factor
that relates the units of interest
to one another (page 34 table).
1 kg ≈ 2.205 pounds
Chapter 7: Unit Conversions
(Proportion method)
If a student weighs 80 kg, how
much does he weigh in pounds?
Step 2. Express the conversion
factor as a ratio (fraction):
1 kg
2.205 pounds
Chapter 7: Unit Conversions
(Proportion method)
If a student weighs 80 kg, how
much does he weigh in pounds?
Step 3. Express the problem as a
ratio with an unknown:
80 kg
?
Chapter 7: Unit Conversions
(Proportion method)
Step 4. Set up a proportion
equation such that the units in both
numerators are the same and the
units in both denominators are the
same:
1 kg
2.205 pounds
=
80 kg
?
Chapter 7: Unit Conversions
(Proportion method)
Step 5. Solve for the unknown:
?
=
?
=
80 kg (2.205 pounds)
1 kg
176.4 pounds
Chapter 7: Unit Conversions
(Proportion method)
Step 6. Check that the answer
makes sense
?
=
176.4 pounds
Chapter 7: Unit Conversions
(Unit canceling method)
Convert 2.80 kg to pounds.
Step 1. Write the problem as an
equation.
2.8 kg = ? pounds
Chapter 7: Unit Conversions
(Unit canceling method)
Convert 2.80 kg to pounds.
Step 2. Find a conversion factor
such that the units cancel
(page 34).
1 lb
0.454 kg
Chapter 7: Unit Conversions
(Unit canceling method)
Convert 2.80 kg to pounds.
Step 3. Place the conversion factor
into the equation.
1 lb
2.80 kg X
0.454 kg
=?
Chapter 7: Unit Conversions
(Unit canceling method)
Step 4. Solve the equation;
multiply 2.80 kg by the
conversion factor:
1 lb
2.80 kg X
0.454 kg
≈ 6.17 lb
Chapter 7: Word Problems
Requiring Multiple Steps
Transgenic sheep can secrete a human protein,
AAT, into their milk. AAT is valuable in the
treatment of emphysema. The concentration
of AAT in the milk is 15 g/L. A sheep can
produce 400 liters of milk each year. AAT is
worth $110/gram. What is the value of a year’s
production of AAT from such transgenic sheep?
400 L
year
X
15 g
L
X
$110
= $?/year
gram
= $660,000/year
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