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Multiplication of Brackets - FOIL Thursday, 06 July 2017 © RIVERMEAD Mathematics Department Aim of the lesson: Expand the product of two linear expressions. E.g. (x + 1)(x + 2) = x2 + 3x + 2 1 Reminder: Multiply out the expression 3a(4a + 7) 3a(4a + 7) = 12a² + 21a But what happens when there are 2 brackets (x + 7)(x + 3) = x² + 3x + 7x + 21 = x² + 10x + 21 Remember the mnemonic First Outside FOIL Inside Last 2 (1) (x + 3)(x + 6) Multiply the brackets x² + 9x + 18 (x + 6)(x - 4) = x² - 4x + 6x - 24 = x² + 2x - 24 (x - 7)(x + 2) = x² + 2x - 7x - 14 = x² (x - 5)² - 5x - 14 = (x - 5)(x - 5) = x² - 5x - 5x + 25 = x² - 10x + 25 Left click to see answers (2) (x + 4)(x - 3) x² + x + 12 (3) (x – 3)(x + 5) x² + 2x – 15 (4) (x – 5)(x - 1) x² – 6x + 5 (5) (x + 2)² x² + 4x + 4 (6) (x – 4)² x² - 8x + 16 3 To see a dynamic display http://www.msubillings.edu/asc/algebra_helps.htm Then multiplying brackets - Foil 4 Multiply the brackets (1) (4x + 3)(5x + 6) 20x² + 39x + 18 (2x + 6)(3x - 4) = 6x² - 8x + 18x - 24 = 6x² + 10x - 24 (4x - 7)(3x + 2) = 12x² + 8x - 21x - 14 = 12x² - 13x - 14 (3x - 5)² = (3x - 5)(3x - 5) = 9x² - 15x - 15x + 25 = 9x² - 30x + 25 (2) (3x + 4)(2x - 3) 6x² - x - 12 (3) (5x – 3)(2x + 5) 10x² + 9x – 15 (4) (2x – 5)(2x - 1) 4x² – 12x + 5 (5) (5x + 2)² 25x² + 20x + 4 Left click to see answers (6) (3x – 4)² 9x² - 24x + 16 5 Multiply the brackets (1) (4x + y)(5x + 2y) 20x² + 13xy + 2y² (5x + 4y)(3x – 4y) = 15x² - 20xy + 12xy - 16y² = 15x² - 8xy - 16y² (2) (3x + 2y)(3x – 2y) 9x² – 4y² (5x – 7y)(3x + y) = 15x² + 5xy - 21xy - 7y² (3) (5x – 3y)(2x + 3y) = 15x² - 16xy - 7y² (4x – 5y)² = (4x – 5y)(4x – 5y) = 16x² - 20xy - 20xy + 25y² = 16x² - 40xy + 25y² 10x² + 9xy – 9y² (4) (2x – 5y)(3x - y) 6x² – 17xy + 5y² (5) (x + 2y)² x² + 4xy + 4y² Left click to see answers (6) (3x – 7y)² 9x² - 42xy + 49y² 6 Remember this topic as you will have one of these in your exam. Vocabulary: FOIL Product Expression 7