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Partial Fraction Decomposition Sec. 7.4a First, remind me……………………..…what’s a rational function? f x y x g x with g x 0 In this section, we will write a rational function as a sum of rational functions where each denominator is a power of a linear factor or a power of an irreducible quadratic factor. Example: 3x 4 2 1 2 x 2x x x 2 Each fraction in the sum is a partial fraction, and the sum is a partial fraction decomposition of the original rational function. Steps to Partial Fraction Decomposition of f(x)/d(x) 1. If the degree of f > degree of d: Divide f by d to obtain the quotient q and the remainder r and write f x d x q x r x d x 2. Factor d(x) into a product of factors of the form ax 2 bx c , where ax bx c v 2 mx n or is irreducible v u Steps to Partial Fraction Decomposition of f(x)/d(x) 3. For each factor mx n : The partial fraction decomposition of r(x)/d(x) must include the sum u A1 A2 2 mx n mx n where A1 , A2 , , Au Au mx n u are real numbers v 4. For each factor ax bx c : The partial fraction decomp. of r(x)/d(x) must include the sum 2 B1 x C1 B2 x C2 2 2 ax bx c ax 2 bx c where B1 , B2 , , BV and C1 , C2 , , Cv Bv x Cv ax 2 bx c v are real numbers Guided Practice Write the terms for the partial fraction decomposition of the given rational function. Do not solve for the corresponding constants. 5x 1 x 3 x 3 x 2 1 B1 x C1 A1 A2 A3 A4 2 3 + + 2 x 1 x3 x x x Today, we’ll just focus on the linear factors, like these… Guided Practice Find the partial fraction decomposition of the given function. 5x 1 2 x 2 x 15 Write the partial fractions! Factor the denominator! 5x 1 x 3 x 5 A1 A2 5x 1 x 3 x 5 x 3 x 5 “Clear the fractions” by multiplying everything by the denominator! 5x 1 A1 x 5 A2 x 3 5 x 1 A1 x 5 A1 A2 x 3 A2 5x 1 A1 A2 x 5 A1 3 A2 Guided Practice Find the partial fraction decomposition of the given function. 5x 1 2 3 2 x 2 x 15 x 3 x 5 5x 1 A1 A2 x 5 A1 3 A2 Equate the coefficients from each side of the equation! Solve the system! (I don’t care how!!!) A1 A2 5 5 A1 3 A2 1 A1 2 A2 3 Can we verify this answer algebraically? Graphically? Guided Practice Find the partial fraction decomposition of the given function. 5x 1 2 3 2 x 2 x 15 x 3 x 5 Another (easier?) way to solve for the constants: Plug in 5 for x, then plug in –3 for x: 5x 1 A1 x 5 A2 x 3 A1 2 A2 3 Guided Practice Find the partial fraction decomposition of the given function. x 2x 4 A3 A2 x 2 x 4 A1 3 2 2 2 x 4x 4x x x 2 x x 2 x 2 2 2 Clear fractions: x 2 x 4 A1 x 2 A2 x x 2 A3 x 2 2 Expand and combine like terms: x2 2x 4 A1 A2 x2 4 A1 2 A2 A3 x 4 A1 Guided Practice Find the partial fraction decomposition of the given function. x 2x 4 1 2 2 3 2 x 4 x 4 x x x 2 x 2 2 2 x2 2x 4 A1 A2 x2 4 A1 2 A2 A3 x 4 A1 Compare coefficients: A1 A2 1 4 A1 2 A2 A3 2 4 A1 4 Solve the system: A1 1 A2 2 A3 2 Guided Practice Find the partial fraction decomposition of the given function. x 2x 4 1 2 2 3 2 x 4 x 4 x x x 2 x 2 2 2 The other way to solve for the A’s: x 2 x 4 A1 x 2 A2 x x 2 A3 x 2 Use x = 2, solve for A 3 Use x = 0, solve for A 1 Use any other x, solve for A 2 A1 1 A2 2 A3 2 2 More PFD: Denominators with Irreducible Quadratic Factors Now let’s apply a similar process when working with irreducible quadratic factors… (see “Step 4” in your notes from the previous slides!!) Find the partial fraction decomposition of A Bx C x 4x 1 2 3 2 x x x 1 x 1 x 1 2 Factor the denominator by grouping: x x x 1 x x 1 x 1 x 1 x 2 1 3 2 2 Clear fractions: x 4 x 1 A x 1 Bx C x 1 2 2 Expand and combine like terms: x 4 x 1 A B x B C x A C 2 2 Find the partial fraction decomposition of 3 2 x 2 x 4x 1 2 3 2 x x x 1 x 1 x 1 2 x 4 x 1 A B x B C x A C 2 2 Compare coefficients: A B 1 B C 4 AC 1 Solve the system: A 3 B 2 C 2 Find the partial fraction decomposition of 2 x x 5x 3 2 x 2 1 2 B1 x C1 B2 x C2 2 2 2 x 1 x 1 Clear fractions: 2 x x 5 x B1 x C1 x 1 B2 x C2 3 2 2 Expand and combine like terms: 2 x x 5x B1x C1x B1 B2 x C1 C2 3 2 3 2 Find the partial fraction decomposition of 2 x x 5x 3 2 x 2 1 2 2x 1 3x 1 2 2 2 x 1 x 1 2 x x 5x B1x C1x B1 B2 x C1 C2 3 2 3 2 B1 2 C1 1 B1 B2 5 C1 C2 0 B2 3 C2 1 Compare coefficients: Find the partial fraction decomposition of 3x 2 4 x 2 1 2 B1 x C1 B2 x C2 2 2 2 x 1 x 1 Clear fractions: 3x 4 B1 x C1 x 1 B2 x C2 2 2 Expand and combine like terms: 3x2 4 B1 x3 C1 x2 B1 B2 x C1 C2 Find the partial fraction decomposition of 3x 2 4 x 2 1 2 3 1 2 2 2 x 1 x 1 3x 4 B1 x C1 x B1 B2 x C1 C2 2 3 2 B1 0 C1 3 B1 B2 0 C1 C2 4 B2 0 C2 1 Compare coefficients: