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Writing Linear Equations in Point-Slope and Standard Form Chapter 6-2 Point-Slope Form Point-Slope Form For a given point (x1, y1) on a nonvertical line having slope m, the point-slope form of a linear equation is as follows. y – y1 = m(x – x1) Examples Write the point-slope form of an equation of the line that passes through the given point and has the given slope. 1. (3,5), m = 2 y - y1 = m(x – x1) y – 5 = 2(x – 3) 2. (2,9), m = 6 y - y1 = m(x – x1) y – 9 = 6(x – 2) More Examples 3. (-4,7), m = 12 y - y1 = m(x – x1) y – 7 = 12(x – (-4)) y – 7 = 12(x + 4) 4. (1,8), m = -10 y - y1 = m(x – x1) y – 8 = -10(x – 1) Point-Slope Form Write the point-slope form of an equation of the line that passes through the given pair of points. 1. (2,3), (4,5) First we must find the slope using the following m= 5–3 4–2 y2 – y1 x2 – x1 = 2 2 = 1 Now that we know the slope lets plug in point. y - y1 = m(x – x1) y – 3 = 1(x – 2) or y – 5 = 1(x – 4) Point-Slope Form Write the point-slope form of an equation of the line that passes through the given pair of points. 2. (2,2), (4,12) First we must find the slope using the following m = 12– 2 4–2 y2 – y1 x2 – x1 = 10 2 = 5 Now that we know the slope lets plug in point. y - y1 = m(x – x1) y – 2 = 5(x – 2) or y – 12 = 5(x – 4) Standard Form Standard Form Standard Form The standard form of a linear equation is Ax + By = C, where A, B, and C are integers, A > 0, and A and B are not both zero. Examples Write the standard form of an equation of the line that passes through the given point and has the given slope. 1.(3,5), m = 2 1st 2nd 3rd 4th 5th 6th y - y1 = m(x – x1) y – 5 = 2(x – 3) y – 5 = 2x – 6 y = 2x – 1 -2x + y = -1 2x – y = 1 Point-Slope Form Use Distributive Property Add 5 to -6 Subtract 2x Multiply by (-1) More Examples Write the standard form of an equation of the line that passes through the given point and has the given slope. 2. (4,7), m = -3 1st 2nd 3rd 4th 5th y - y1 = m(x – x1) y – 7 = -3(x – 4) y – 7 = -3x + 12 y = -3x + 19 3x + y = 19 Point-Slope Form Use Distributive Property Add 7 to 12 Add -3x More Examples Write the standard form of an equation of the line that passes through the given pair of points. 3. (2,2), (4,12) First we must find the slope using the following m = 12– 2 4–2 y2 – y1 x2 – x1 = 10 2 = 5 Now that we know the slope lets plug in point. y - y1 = m(x – x1) y – 2 = 5(x – 2) or y – 12 = 5(x – 4) #3 Continued y – 2 = 5(x – 2) 1st 2nd 3rd 4th 5th or y – 2 = 5(x – 2) y – 2 = 5x – 10 y = 5x – 8 -5x + y = -8 5x – y = 8 y – 12 = 5(x – 4) Point-Slope Form Use Distributive Property Add 2 to -10 Subtract 5x Multiply by (-1) The End