Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Work and Energy Physics 100 Chapt 5 Physicist’s definition of “work” dist∥ dist Work = F x dist∥ Atlas holds up the Earth But he doesn’t move, dist∥ = 0 Work= Fx dist∥ = 0 He doesn’t do any work! Garcon does work when he picks up the tray but not while he carries it around the room dist is not zero, but dist∥ is 0 Why this definition? Newton’s 2nd law: F=m a Definition of work + a little calculus Work= change in ½mv2 This scalar quantity is given a special name: kinetic energy Work = change in KE This is called: the Work-Energy Theorem Units again… Kinetic Energy = ½mv2 work = F x dist∥ 2 m kg 2 s same! m N m =kg 2 m s =1Joule Work done by gravity end start dist dist∥ change in vertical height W=mg Work = F = x dist∥ -mg x change in height = -change in mg h Gravitational Potential Energy Workgrav = -change in mgh This is called: “Gravitational Potential Energy” (or PEgrav) change Workgrav in = PE-change in PE grav = -Work grav grav If gravity is the only force doing work…. Work-energy theorem: -change in mgh = change in ½ mv2 0 = change in mgh + change in ½ mv2 change in (mgh + ½ mv2) = 0 mgh + ½ mv2 = constant Conservation of energy mgh + ½ mv2 = constant Gravitational Potential energy Kinetic energy If gravity is the only force that does work: PE + KE = constant Energy is conserved Free fall (reminder) height t = 0s V0 = 0 t = 1s 80m 75m V1 = 10m/s 60m t = 2s V2 = 20m/s t = 3s 35m V3 = 30m/s t = 4s V4 = 40m/s 0m m=1kg free falls from 80m t = 0s V0 = 0 h0=80m mgh 800J ½ mv2 sum 0 800J 50J 800J t = 1s V1 = 10m/s; h1=75m 750J t = 2s V2 = 20m/s; h2=60m 600J 200J 800J 350J 450J 800J t = 3s V3 = 30m/s; h3=35m t = 4s V4 = 40m/s; h4=0 0 800J 800J pendulum T W=mg Two forces: T and W T is always to the motion (& does no work) ┴ Pendulum conserves energy E=mghmax E=mghmax hmax E=1/2 m(vmax)2 Roller coaster Work done by a spring Relaxed Position F=0 F x I compress the spring (I do + work; spring does -work) Work done by spring = - change in ½ kx2 Spring Potential Energy Workspring = -change in ½ kx2 This is the: “Spring’s Potential Energy” (or PEspring) Workspring = -change in PEspring change in PEspring = - If spring is the only force doing work…. Work-energy theorem: -change in ½ kx2 = change in ½ mv2 0 = change in ½ kx2 + change in ½ mv2 change in ( ½ kx2 + ½ mv2) = 0 ½ kx2 + ½ mv2 = constant Conservation of energy springs & gravity mgh + ½ kx2 + ½ mv2 = constant Gravitational spring potential energy potential energy Kinetic energy If elastic force & gravity are the only force doing work: PEgrav + PEspring + KE = constant Energy is conserved example grav PE KineticE Spring PE Two types of forces: “Conservative” forces forces that do + & – work “Dissipative” •Gravity •Friction •Elastic (springs, etc) •Viscosity •Electrical forces •…. •… -work heat -work change in PE forces forces that only do – work (no potential energy.) (-)Work done by frictionheat Thermal atomic motion Air solid Heat energy= KE and PE associated with the random thermal motion of atoms Work-energy theorem (all forces) Workfric = Work done dissipative Forces (always -) change in (PE+KE) potential energy From all Conservative forces Kinetic energy -Work change in in heat heat energy energy Work -change fric = = fric -change = (PE+KE) in Heat Energy change in Work – Energy Theorem (all forces) 0 = change in 0 = + (PE+KE) change in Heat Energy change in Heat Energy (Heat Energy+PE+KE) + PE + KE = constant Law of Conservation of Energy Energy conversion while skiing Potential energy Potential energykinetic energy Friction: energy gets converted to heat Units again Heat units: 1 calorie = heat energy required to raise the temp of 1 gram of H2O by 1o C Kg m2/s2 1 calorie= 4.18 Joules Food Calories 1 Calorie = 1000 calories = 1Kcalorie The Calories you read on food labels 1 Calorie= 4.18x103 Joules 7 x 106 J 8 x 105 J 2 x 106 J Power Rate of using energy: Units: Joule 1 second amout of energy Power = elapsed time = 1 Watt A 100 W light bulb consumes 100 J of electrical energy each second to produce light Other units Over a full day, a work-horse can have an average work output of more than 750 Joules each second 1 Horsepower = 750 Watts Kilowatt hours energy Power = time energy = power power unit Elec companies use: x Kilowatts (103 W) x time time unit = energy unit x hours (3600 s) 1 kilowatt-hour = 1kW-hr = 103 W x 3.6x103 s = 3.6x106 Ws J HECO charges us about 15 cents /kW-hr