Download File: Ch16, Chapter 16: Chi-Square Analysis True/False 1. In a chi

File: Ch16, Chapter 16: Chi-Square Analysis
True/False
1. In a chi-square goodness-of-fit test, theoretical frequencies are also called expected
frequencies.
Ans: True
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
2. In a chi-square goodness-of-fit test, actual frequencies are also called calculated frequencies.
Ans: False
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
3. The number of degrees of freedom in a chi-square goodness-of-fit test is the number of
categories minus the number of parameters estimated.
Ans: False
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
4. The number of degrees of freedom in a chi-square goodness-of-fit test is the number of
categories minus the number of parameters estimated minus one.
Ans: True
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
5. A chi-square goodness-of-fit test is being used to test the goodness-of-fit of a normal
distribution (the mean and the standard deviation of which must be estimated) for a data with "k"
categories. This test has (k-3) degrees of freedom.
Ans: True
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
6. The null hypothesis in a chi-square goodness-of-fit test is that the observed distribution is the
same as the expected distribution.
Ans: True
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
7. The decision rule in a chi-square goodness-of-fit test is to reject the null hypothesis if the
computed chi-square is greater than the table chi-square.
Ans: True
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
8. When using the chi-square goodness-of-fit test, we must make sure that none of the expected
frequencies is less than 30.
Ans: False
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
9. A chi-square goodness-of-fit test to determine if the observed frequencies in seven categories
are uniformly distributed has six degrees of freedom.
Ans: True
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
10. A chi-square goodness-of-fit test to determine if the observed frequencies in ten categories
are Poisson distributed has nine degrees of freedom.
Ans: False
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
11. A two-way table used for a test of independence is sometimes called a contingency table.
Ans: True
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
12. In a chi-square test of independence the contingency table has 4 rows and 3 columns. The
number of degrees of freedom for this test is 12.
Ans: False
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
13. In a chi-square test of independence the contingency table has 4 rows and 3 columns. The
number of degrees of freedom for this test is 7.
Ans: False
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
14. In a chi-square test of independence the contingency table has 4 rows and 3 columns. The
number of degrees of freedom for this test is 6.
Ans: True
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
15. The null hypothesis for a chi-square test of independence is that the two variables are not
related.
Ans: True
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
Multiple Choice
16. A goodness of fit test is to be performed to see if consumers prefer any of three package
designs (A, B, and C) more than the other two. A sample of 60 consumers is used. What is the
expected frequency for category A?
a) 1/3
b) 20
c) 60
d) 10
e) 30
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
17. A goodness of fit test is to be performed to see if Web Surfers prefer any of four Web sites
(A, B, C and D) more than the other three. A sample of 60 consumers is used. What is the
expected frequency for Web site A?
a) 1/4
b) 20
c) 15
d) 10
e) 30
Ans: c
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
18. A variable contains five categories. It is expected that data are uniformly distributed across
these five categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 27, 30, 29, 21, and 24. Using  = .01, the degrees of freedom for this test are
_______.
a) 5
b) 4
c) 3
d) 2
e) 1
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
19. A variable contains five categories. It is expected that data are uniformly distributed across
these five categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 27, 30, 29, 21, and 24. Using  = .01, the critical value of chi-square is
_______.
a) 7.78
b) 15.09
c) 9.24
d) 13.28
e) 15.48
Ans: d
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
20. A variable contains five categories. It is expected that data are uniformly distributed across
these five categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 27, 30, 29, 21, and 24. Using  = .01, the observed value of chi-square is
_______.
a) 12.09
b) 9.82
c) 13.28
d) 17.81
e) 2.09
Ans: e
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Middle
21. A variable contains five categories. It is expected that data are uniformly distributed across
these five categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 27, 30, 29, 21, and 24. Using  = .01, the appropriate decision is _______.
a) reject the null hypothesis that the observed distribution is uniform
b) reject the null hypothesis that the observed distribution is not uniform
c) do not reject the null hypothesis that the observed distribution is uniform
d) do not reject the null hypothesis that the observed distribution is not uniform
e) do nothing
Ans: c
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Hard
22. A variable contains five categories. It is expected that data are uniformly distributed across
these five categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 26, 10, 17, 21, and 26. Using  = .01, the critical chi-square value is _______.
a) 13.277
b) 15.086
c) 7.779
d) 11.070
e) 14.356
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
23. A variable contains five categories. It is expected that data are uniformly distributed across
these five categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 26, 10, 17, 21, and 26. Using  = .01, the observed chi-square value is
_______.
a) 1.18
b) 9.10
c) 20.27
d) 4.51
e) 19.70
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
24. A variable contains five categories. It is expected that data are uniformly distributed across
these five categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 26, 10, 17, 21, and 26. Using  = .01, the appropriate decision is _______.
a) do not reject the null hypothesis that the observed distribution is uniform
b) do not reject the null hypothesis that the observed distribution is not uniform
c) reject the null hypothesis that the observed distribution is uniform
d) reject the null hypothesis that the observed distribution is not uniform
e) do nothing
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Hard
25. A variable contains five categories. It is expected that data are uniformly distributed across
these five categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 26, 10, 17, 21, and 26. Using  = .10, the appropriate decision is _______.
a) do not reject the null hypothesis that the observed distribution is uniform
b) do not reject the null hypothesis that the observed distribution is not uniform
c) reject the null hypothesis that the observed distribution is uniform
d) reject the null hypothesis that the observed distribution is not uniform
e) do nothing
Ans: c
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Hard
26. A variable contains four categories. It is expected that data are uniformly distributed across
these four categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 22, 35, 32, and 21. Using  = .05, the critical chi-square value is _______.
a) 13.277
b) 15.086
c) 7.8147
d) 11.070
e) 15.546
Ans: c
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
27. A variable contains four categories. It is expected that data are uniformly distributed across
these four categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 22, 35, 32, and 21. Using  = .05, the observed chi-square value is _______.
a) 5.418
b) 9.10
c) 20.27
d) 4.51
e) 7.86
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
28. A variable contains four categories. It is expected that data are uniformly distributed across
these four categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 22, 35, 32, and 21. Using  = .05, the appropriate decision is _______.
a) do not reject the null hypothesis that the observed distribution is uniform
b) do not reject the null hypothesis that the observed distribution is not uniform
c) reject the null hypothesis that the observed distribution is uniform
d) reject the null hypothesis that the observed distribution is not uniform
e) do nothing
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Hard
29. A variable contains four categories. It is expected that data are uniformly distributed across
these four categories. To test this, a sample of observed data is gathered on this variable resulting
in frequencies of 22, 35, 32, and 21. Using  = .10, the appropriate decision is _______.
a) do not reject the null hypothesis that the observed distribution is uniform
b) do not reject the null hypothesis that the observed distribution is not uniform
c) reject the null hypothesis that the observed distribution is uniform
d) reject the null hypothesis that the observed distribution is not uniform
e) do nothing
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Hard
30. A chi-square goodness of fit test is to be performed to see if data fit the Poisson distribution.
There are 6 categories, and lambda must be estimated. How many degrees of freedom should be
used?
a) 6
b) 5
c) 4
d) 3
e) 2
Ans: c
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
31. A chi-square goodness of fit test is to be performed to see if data fit the Poisson distribution.
There are 8 categories, and lambda must be estimated. How many degrees of freedom should be
used?
a) 8
b) 7
c) 6
d) 5
e) 4
Ans: c
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
32. A chi-square goodness of fit test is to be performed to see if data fit the Poisson distribution.
There are 8 categories, and lambda must be estimated. Alpha is chosen to be 0.10. The critical
(table) value of chi-square is _______.
a) 10.645
b) 12.017
c) 3.828
d) 16.812
e) 17.345
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
33. A researcher believes that a variable is Poisson distributed across six categories. To test this,
the following random sample of observations is collected:
Category
Observed
0
47
1
56
2
39
3
22
4
18
5
10
Using  = 0.10, the critical chi-square value for this goodness-of-fit test is _______.
a) 1.064
b) 13.277
c) 9.236
d) 8.799
e) 7.779
Ans: e
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
34. A researcher believes that a variable is Poisson distributed across six categories. To test this,
the following random sample of observations is collected:
Category
Observed
0
47
1
56
2
39
3
22
4
18
5
10
Using  = 0.10, the observed chi-square value for this goodness-of-fit test is ____.
a) 2.28
b) 14.56
c) 17.43
d) 1.68
e) 2.67
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Hard
35. A researcher believes that a variable is Poisson distributed across six categories. To test this,
the following random sample of observations is collected:
Category
0
1
2
3
4
>5
Observed
7
18
25
17
12
5
Using  = 0.10, the critical value of chi-square for the data is _______.
a) 9.236
b) 7.779
b) 1.064
c) 13.277
d) 12.89
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
36. A researcher believes that a variable is Poisson distributed across six categories. To test this,
the following random sample of observations is collected:
Category
Observed
0
7
1
18
2
25
3
17
4
12
>5
5
Using  = 0.10, the value of the observed chi-square for the data is _______.
a) 19.37
b) 2.29
c) 1.74
d) 3.28
e) 4.48
Ans: c
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Hard
37. Sami Schmitt believes that number of cars arriving at his Scrub and Shine Car Wash follow a
Poisson distribution. He collected a random sample and constructed the following frequency
distribution to test his hypothesis.
Cars per 15 minute interval
0
1
2
3
4
Observed Frequency
5
15
17
12
10
The number of degrees of freedom for this goodness-of-fit test is _______.
a) 5
b) 4
c) 3
>5
8
d) 2
e) 1
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
38. Sami Schmitt believes that number of cars arriving at his Scrub and Shine Car Wash follow a
Poisson distribution. He collected a random sample and constructed the following frequency
distribution to test his hypothesis.
Cars per 15 minute interval
Observed Frequency
0
5
1
15
2
17
3
12
4
10
>5
8
Using  = 0.05, the critical value of chi-square for this goodness-of-fit test is ____.
a) 9.49
b) 7.81
c) 7.78
d) 11.07
e) 12.77
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
39. Sami Schmitt believes that number of cars arriving at his Scrub and Shine Car Wash follow a
Poisson distribution. He collected a random sample and constructed the following frequency
distribution to test his hypothesis.
Cars per 15 minute interval
Observed Frequency
0
5
1
15
2
17
3
12
The observed value of chi-square for this goodness-of-fit test is _____.
a) 0.73
b) 6.72
c) 3.15
d) 7.81
e) 9.87
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
4
10
>5
8
Difficulty: Hard
40. Sami Schmitt believes that number of cars arriving at his Scrub and Shine Car Wash follow a
Poisson distribution. He collected a random sample and constructed the following frequency
distribution to test his hypothesis.
Cars per 15 minute interval
Observed Frequency
0
5
1
15
2
17
3
12
4
10
>5
8
Using  = 0.05, the appropriate decision for this goodness-of-fit test is ____.
a) reject the null hypothesis that the observed distribution is Poisson
b) reject the null hypothesis that the observed distribution is not Poisson
c) do not reject the null hypothesis that the observed distribution is not Poisson
d) do not reject the null hypothesis that the observed distribution is Poisson
e) do nothing
Ans: d
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Hard
41. Ophelia O'Brien, VP of Consumer Credit of American First Banks (AFB), monitors the
default rate on personal loans at the AFB member banks. One of her standards is: "no more than
5% of personal loans should be in default." On each Friday, the default rate is calculated for a
sample of 500 personal loans. Last Friday's sample contained 30 defaulted loans. Ophelia's null
hypothesis is _______.
a) p > 0.05
b) p = 0.05
c)   30
d)  > 30
e) s > 30
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
42. Ophelia O'Brien, VP of Consumer Credit of American First Banks (AFB), monitors the
default rate on personal loans at the AFB member banks. One of her standards is "no more than
5% of personal loans should be in default." On each Friday, the default rate is calculated for a
sample of 500 personal loans. Last Friday's sample contained 30 defaulted loans. Using  =
0.01, critical chi-square value is _______.
a) 6.63
b) 9.21
c) 7.88
d) 10.60
e) 12.34
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
43. Ophelia O'Brien, VP of Consumer Credit of American First Banks (AFB), monitors the
default rate on personal loans at the AFB member banks. One of her standards is "no more than
5% of personal loans should be in default." On each Friday, the default rate is calculated for a
sample of 500 personal loans. Last Friday's sample contained 30 defaulted loans. Using  =
0.01, observed chi-square value is _______.
a) 13.38
b) 26.29
c) 2.09
d) 1.05
e) 3.98
Ans: d
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
44. Ophelia O'Brien, VP of Consumer Credit of American First Banks (AFB), monitors the
default rate on personal loans at the AFB member banks. One of her standards is "no more than
5% of personal loans should be in default." On each Friday, the default rate is calculated for a
sample of 500 personal loans. Last Friday's sample contained 30 defaulted loans. Using  =
0.01, the appropriate decision is _______.
a) reject the null hypothesis p > 0.05
b) do not reject the null hypothesis p = 0.05
c) reject the null hypothesis  > 30
d) do not reject the null hypothesis   30
e) do nothing
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
45. The executives of CareFree Insurance, Inc. feel that "a minority of our employees perceive an
authoritarian management style at CareFree." A random sample of 200 CareFree employees is
selected to test this hypothesis. Eighty employees rate the management as authoritarian. Using 
= 0.05, the null hypothesis is __________.
a)  > 80
b)   80
c) p > 0.50
d) p = 0.50
e) s ≥ 0.80
Ans: d
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
46. The executives of CareFree Insurance, Inc. feel that "a minority of our employees perceive an
authoritarian management style at CareFree." A random sample of 200 CareFree employees is
selected to test this hypothesis. Eighty employees rate the management as authoritarian. Using 
= 0.05, the critical value of chi-square is _______.
a) 7.38
b) 5.02
c) 3.84
d) 5.99
e) 6.99
Ans: c
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Easy
47. The executives of CareFree Insurance, Inc. feel that "a minority of our employees perceive an
authoritarian management style at CareFree." A random sample of 200 CareFree employees is
selected to test this hypothesis. Eighty employees rate the management as authoritarian. Using 
= 0.05, the observed value of chi-square is __________.
a) 8.00
b) 2.82
c) 4.00
d) 9.71
e) 9.97
Ans: a
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
48. The executives of CareFree Insurance, Inc. feel that "a minority of our employees perceive an
authoritarian management style at CareFree." A random sample of 200 CareFree employees is
selected to test this hypothesis. Eighty employees rate the management as authoritarian. Using 
= 0.05, the appropriate decision is ________.
a) do not reject the null hypothesis p > 0.50
b) reject the null hypothesis p = 0.50
c) reject the null hypothesis  > 80
d) do not reject the null hypothesis   80
e) do nothing
Ans: b
Response: See section 16.1 Chi-Square Goodness-of-Fit Test
Difficulty: Medium
49. A test of independence is to be performed. The contingency table has 4 rows and 5 columns.
What would the degrees of freedom be?
a) 20
b) 9
c) 7
d) 12
e) 19
Ans: d
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
50. A contingency table is to be used to test for independence. There are 3 rows and 3 columns
in the table. How many degrees of freedom are there for this problem?
a) 6
b) 5
c) 4
d) 3
e) 1
Ans: c
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
51. A contingency table has five rows and six columns. When applying a chi-square test of
independence to this table, the number of degrees of freedom is _____.
a) 9
b) 20
c) 30
d) 11
e) 12
Ans: b
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
52. A contingency table has seven rows and five columns. When applying a chi-square test of
independence to this table, the number of degrees of freedom is _____.
a) 24
b) 35
c) 12
d) 10
e) 11
Ans: a
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
53. Contingency tables should not be used with expected cell frequencies _______.
a) less than the number of rows
b) less than the number of columns
c) less than 5
d) less than 30
e) less than 50
Ans: c
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
54. Use the following set of observed frequencies to test the independence of the two variables.
Variable one has values of 'A' and 'B'; variable two has values of 'C', 'D', and 'E'.
A
B
C
12
20
D
10
24
E
8
26
Using  = 0.05, the critical chi-square value is _______.
a) 9.488
b) 1.386
c) 8.991
d) 3.357
e) 5.991
Ans: e
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
55. Use the following set of observed frequencies to test the independence of the two variables.
Variable one has values of 'A' and 'B'; variable two has values of 'C', 'D', and 'E'.
A
B
C
12
20
D
10
24
E
8
26
Using  = 0.05, the observed chi-square value is _______.
a) 0
b) 0.69
c) 1.54
d) 21.28
e) 8.29
Ans: c
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Medium
56. Use the following set of observed frequencies to test the independence of the two variables.
Variable one has values of 'A' and 'B'; variable two has values of 'C', 'D', and 'E'.
A
B
C
12
20
D
10
24
E
8
26
Using  = 0.05, the expected frequency in row 1 (A) column 1 (C) is _______.
a) 9.6
b) 12
c) 16
d) 10
e) 20
Ans: a
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
57. Sam Hill, Director of Media Research, is analyzing subscribers to the Life West of the Saline
magazine. He wonders whether subscriptions are influenced by the head of household’s
employment classification. His staff prepared the following contingency table from a random
sample of 300 households.
Subscribes
Yes
No
Head of Household Classification
Clerical
Managerial Professional
10
90
60
60
60
20
Sam's null hypothesis is ______________.
a) "head of household classification" is related to "subscribes"
b) "head of household classification" is not independent of "subscribes"
c) "head of household classification" is independent of "subscribes”
d) "head of household classification" influences "subscribes"
e) “clerical is not related to managerial”
Ans: c
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
58. Sam Hill, Director of Media Research, is analyzing subscribers to the Life West of the Saline
magazine. He wonders whether subscriptions are influenced by the head of household’s
employment classification. His staff prepared the following contingency table from a random
sample of 300 households.
Subscribes
Yes
No
Head of Household Classification
Clerical
Managerial Professional
10
90
60
60
60
20
Using  = .05, the critical value of chi-square is ______________.
a) 5.99
b) 3.84
c) 5.02
d) 7.37
e) 9.99
Ans: a
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
59. Sam Hill, Director of Media Research, is analyzing subscribers to the Life West of the Saline
magazine. He wonders whether subscriptions are influenced by the head of household’s
employment classification. His staff prepared the following contingency table from a random
sample of 300 households.
Subscribes
Yes
No
Head of Household Classification
Clerical
Managerial Professional
10
90
60
60
60
20
The observed value of chi-square is ______________.
a) 5.99
b) 28.30
c) 32.35
d) 60.65
e) 50.78
Ans: d
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Medium
60. Sam Hill, Director of Media Research, is analyzing subscribers to the Life West of the Saline
magazine. He wonders whether subscriptions are influenced by the head of household’s
employment classification. His staff prepared the following contingency table from a random
sample of 300 households.
Subscribes
Yes
No
Head of Household Classification
Clerical
Managerial Professional
10
90
60
60
60
20
Using  = .05, the appropriate decision is ______________.
a) reject the null hypothesis and conclude the two variables are independent
b) do not reject the null hypothesis and conclude the two variables are independent
c) reject the null hypothesis and conclude the two variables are not independent
d) do not reject the null hypothesis and conclude the two variables are not independent
e) do nothing
Ans: c
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: High
61. Catherine Chao, Director of Marketing Research, is evaluating consumer acceptance of
alternative toothpaste packages. She wonders whether acceptance is influenced by children in
the household. Her staff prepared the following contingency table from a random sample of 100
households.
Preferred Package
Pump
Tube
Children in Household
Pre-teenagers
teenagers
none
30
20
10
10
10
20
Catherine's null hypothesis is ______________.
a) "children in household" is not independent of "preferred package"
b) "children in household" is independent of "preferred package"
c) "children in household" is related to "preferred package"
d) "children in household" influences "preferred package"
e) “pump” is independent of “tube”
Ans: b
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
62. Catherine Chao, Director of Marketing Research, is evaluating consumer acceptance of
alternative toothpaste packages. She wonders whether acceptance is influenced by children in
the household. Her staff prepared the following contingency table from a random sample of 100
households.
Preferred Package
Pump
Tube
Children in Household
Pre-teenagers
teenagers
none
30
20
10
10
10
20
Using  = .05, the critical value of chi-square is ______________.
a) 5.02
b) 3.84
c) 7.37
d) 6.09
e) 5.99
Ans: e
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
63. Catherine Chao, Director of Marketing Research, is evaluating consumer acceptance of
alternative toothpaste packages. She wonders whether acceptance is influenced by children in
the household. Her staff prepared the following contingency table from a random sample of 100
households.
Preferred Package
Pump
Tube
Children in Household
Pre-teenagers
teenagers
none
30
20
10
10
10
20
Using  = .05, the observed value of chi-square is ______________.
a) 5.28
b) 9.49
c) 13.19
d) 16.79
e) 18.79
Ans: c
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Medium
64. Catherine Chao, Director of Marketing Research, is evaluating consumer acceptance of
alternative toothpaste packages. She wonders whether acceptance is influenced by children in
the household. Her staff prepared the following contingency table from a random sample of 100
households.
Preferred Package
Pump
Tube
Children in Household
Pre-teenagers
teenagers
none
30
20
10
10
10
20
Using  = .05, the appropriate decision is ______________.
a) reject the null hypothesis and conclude the two variables are not independent
b) do not reject the null hypothesis and conclude the two variables are not independent
c) reject the null hypothesis and conclude the two variables are independent
d) do not reject the null hypothesis and conclude the two variables are independent
e) do nothing
Ans: a
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Hard
65. Anita Cruz recently assumed responsibility for a large investment portfolio. She wonders
whether industry sector influences investment objective. Her staff prepared the following
contingency table from a random sample of 200 common stocks.
Investment
Objective
Growth
Income
Industry Sector
Electronics Airlines Healthcare
100
10
40
20
20
10
Anita's null hypothesis is ______________.
a) "investment objective" is related to "industry sector"
b) "investment objective" influences "industry sector"
c) "investment objective" is not independent of "industry sector"
d) "investment objective" is independent of "industry sector"
e) “growth” and “income” are independent
Ans: d
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
66. Anita Cruz recently assumed responsibility for a large investment portfolio. She wonders
whether industry sector influences investment objective. Her staff prepared the following
contingency table from a random sample of 200 common stocks.
Investment
Objective
Growth
Income
Industry Sector
Electronics Airlines Healthcare
100
10
40
20
20
10
Using  = .01, critical chi-square value is ______________.
a) 9.21
b) 7.88
c) 15.09
d) 16.81
e) 18.81
Ans: a
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
67. Anita Cruz recently assumed responsibility for a large investment portfolio. She wonders
whether industry sector influences investment objective. Her staff prepared the following
contingency table from a random sample of 200 common stocks.
Investment
Objective
Growth
Income
Industry Sector
Electronics Airlines Healthcare
100
10
40
20
20
10
Using  = .05, critical chi-square value is ______________.
a) 9.21
b) 7.88
c) 15.09
d) 5.99
e) 7.89
Ans: d
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
68. Anita Cruz recently assumed responsibility for a large investment portfolio. She wonders
whether industry sector influences investment objective. Her staff prepared the following
contingency table from a random sample of 200 common stocks.
Investment
Objective
Growth
Income
Industry Sector
Electronics Airlines Healthcare
100
10
40
20
20
10
Using  = .01, observed chi-square value is ______________.
a) 24.93
b) 8.17
c) 32.89
d) 6.59
e) 4.89
Ans: c
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
69. Anita Cruz recently assumed responsibility for a large investment portfolio. She wonders
whether industry sector influences investment objective. Her staff prepared the following
contingency table from a random sample of 200 common stocks.
Investment
Objective
Growth
Income
Industry Sector
Electronics Airlines Healthcare
100
10
40
20
20
10
Using  = .01, appropriate decision is ______________.
a) reject the null hypothesis and conclude the two variables are not independent
b) reject the null hypothesis and conclude the two variables are independent
c) do not reject the null hypothesis and conclude the two variables are not independent
d) do not reject the null hypothesis and conclude the two variables are independent
e) do nothing
Ans: b
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Hard
70. A gasoline distributor wonders whether an individual’s income level influences the grade of
gasoline purchased.
Personal
Type of Gasoline
Income
Regular Premium
Extra Premium
Less than $30,000
90
10
20
$30,000 or More
60
60
60
The null hypothesis is ______________.
a) "income” is independent of "type of gasoline”
b) "income” influences "type of gasoline”
c) "income” is not independent of "type of gasoline”
d) “income" is related to "type of gasoline"
e) “regular” is independent of “premium”
Ans: a
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
71. A gasoline distributor wonders whether an individual’s income level influences the grade of
gasoline purchased.
Personal
Type of Gasoline
Income
Regular Premium
Extra Premium
Less than $30,000
90
10
20
$30,000 or More
60
60
60
Using  = .01, critical chi-square value is ______________.
a) 15.09
b) 7.88
c) 9.21
d) 16.81
e) 17.89
Ans: c
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
72. A gasoline distributor wonders whether an individual’s income level influences the grade of
gasoline purchased.
Personal
Type of Gasoline
Income
Regular Premium
Extra Premium
Less than $30,000
90
10
20
$30,000 or More
60
60
60
Using  = .01, observed chi-square value is ______________.
a) 24.93
b) 4.44
c) 32.89
d) 51.79
e) 54.98
Ans: d
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Medium
73. A gasoline distributor wonders whether an individual’s income level influences the grade of
gasoline purchased.
Personal
Type of Gasoline
Income
Regular Premium
Extra Premium
Less than $30,000
80
30
30
$30,000 or More
70
40
50
Using  = .05, critical chi-square value is ______________.
a) 15.09
b) 5.99
c) 9.21
d) 16.81
e) 23.87
Ans: b
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Easy
74. A gasoline distributor wonders whether an individual’s income level influences the grade of
gasoline purchased.
Personal
Type of Gasoline
Income
Regular Premium
Extra Premium
Less than $30,000
80
30
30
$30,000 or More
70
40
50
Using  = .05, observed chi-square value is ______________.
a) 15.79
b) 4.44
c) 32.89
d) 51.79
e) 5.79
Ans: e
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: Medium
75. A gasoline distributor wonders whether an individual’s income level influences the grade of
gasoline purchased.
Personal
Type of Gasoline
Income
Regular Premium
Extra Premium
Less than $30,000
80
30
30
$30,000 or More
70
40
50
Using  = .05, appropriate decision is ______________.
a) reject the null hypothesis and conclude the two variables are not independent
b) reject the null hypothesis and conclude the two variables are independent
c) do not reject the null hypothesis and conclude the two variables are not independent
d) do not reject the null hypothesis and conclude the two variables are independent
e) do nothing
Ans: d
Response: See section 16.2 Contingency Analysis: Chi-Square Test of Independence
Difficulty: High