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Chemistry 11 The Mole I – Practice Problems Answers – Please do not print. Show all your work in a clear, organized and complete manner. Respect significant figures. A. MOLES AND NUMBERS 1. Calculate the number of moles in each of the following: a) 1.2 x 10 30 atoms of gold c) 6 2.4 x 10 20 2. –4 molecules of sugar n = 5.00 x 10 mol worms n = 4.0 x 10 28 4 n = 2.0 x 10 mol b) 3.01 x 10 d) mol 8.00 x 10 12 homework assignments n = 1.33 x 10 –11 mol Calculate the following: a) the number of atoms in 5.0 moles of copper 3.0 x 10 b) 24 d) atoms 3.31 x 10 the number of molecules in -15 3.0 x 10 mole of carbon dioxide e) 9 1.8 x 10 molecules c) the number of bananas in -8 8.88 x 10 mol of bananas the number of hydrogen atoms in 0.00275 mole of water 16 H atoms the number of oxygen atoms in 3 1.2 x 10 mol of Mg(NO3)2 4.3 x 10 5.35 x 10 21 27 oxygen atoms bananas B. MOLES AND MASS 3. Calculate the molar mass of: a) KBr e) M = 119.01 g/mol b) O2 M = 120.37 g/mol f) M = 32.00 g/mol c) Ca(NO3)2 (NH4)3PO4 M = 149.12 g/mol C6H12O6 (glucose) M = 180.18 g/mol g) M = 164.10 g/mol d) MgSO4 NaC5H8NO4 (MSG) M = 169.13 g/mol h) C10H14N2 (nicotine) M = 162.26 g/mol Chemistry 11 4. Calculate the mass (in grams) of the following: a) -3 1.75 x 10 mol of oxygen gas mass = 0.0560 g b) 2 3.4 x 10 mol of KBr 4 mass = 4.0 x 10 g c) 0.00670 mol of C6H12O6 mass = 1.21 g d) 8.35 x 10 -12 mol of MSG mass = 1.41 x 10 5. –9 g Calculate the number of moles in each of the following: a) 43.2 g of Ca(NO3)2 n = 0.263 mol b) -3 8.27 x 10 g of MgSO4 n = 6.87 x 10 c) –5 mol 7.2 mg of nicotine -5 n = 4.4 x 10 mol d) 2 2.82 x 10 kg of ammonium phosphate 3 n = 1.89 x 10 mol 6. You have a sample of an “unknown metal chloride” with the formula XCl2. Experiments show that the sample contains 0.20 mole of the compound, and its mass is 22.2 g. What is the identity of element X? M = 22.2 g / 0.20 mol = 111 g/mol Mr = Ar (X) + 2 Ar (Cl) 111 = Ar (X) + 2 (35.45) ∴ Ar (X) = 111 – 70.90 = 40 ∴ element X is most likely calcium (Ar = 40.08) Chemistry 11 C. MASS, MOLES AND NUMBERS 7. Calculate the number of atoms in: a) 72.0 g of lead # atoms = 72.0 g x (1 mol / 207.19 g) x (6.02 x 10 b) 23 atoms / 1 mol) = 2.09 x 10 2 2 27 atoms 23 molecules /1 mol) x ( 2 oxygen atoms /1 molecule) Calculate the mass of a) b) atoms of silver 21 atoms x (1 mol / 6.02 x 10 23 atoms) x (107.87 g / 1 mol) = 0.821 g 18 molecules of ammonia (NH3) 18 molecules x (1 mol / 6.02 x 10 2.9 x 10 mass = 2.9 x 10 c) 21 4.58 x 10 mass = 4.58 x 10 23 -5 molecules) x (17.04 g / 1 mol) = 8.2 x 10 g 26 molecules of glucose (C6H12O6) 26 molecules x (1 mol / 6.02 x 10 1.47 x 10 mass = 1.47 x 10 23 4 molecules) x (180.18 g / 1 mol) = 4.40 x 10 g Calculate the number of hydrogen atoms in a) 2.5 mg of water # H atoms = 2.5 mg x (1 g / 1000 mg) x (1 mol / 18.02 g) x (6.02 x 10 20 = 1.7 x 10 H atoms b) 23 molecules / 1 mol) x (2 H atoms/1 molecule) 3 8.0 x 10 kg of methane (CH4) 3 # H atoms=(8.0 x10 kg) x (1000g /1kg) x (1 mol /16.05 g) x (6.02 x 10 30 = 1.2 x 10 H atoms 10. atoms /1 mol) = 1.1 x 10 -2 -2 9. 23 7.00 x 10 g of oxygen gas = O2 # atoms = 7.00 x 10 g x (1 mol / 32.00 g) x (6.02 x 10 21 = 2.63 x 10 atoms 8. atoms 3.5 x 10 kg of gold # atoms = 3.5 x 10 kg x (1000 g / 1 kg) x (1 mol / 196.97 g) x (6.02 x 10 c) 23 23 molecules /1mol) x (4 H atoms/1 molecule) a) What is Avogadro’s favourite board game? Moleopoly ….. HA HA ha ha haaa! b) What is Avogadro’s favourite chip dip? Guacamole …. HA HA ha ha haaa ha ha!