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Confidence Interval Concept Check A laboratory scale is known to have a standard deviation of 0.001 gram in repeated weighings. Scale readings in repeated weighings are Normally distributed, with mean equal to the true weight of the specimen. If you weigh a specimen three times on this scale, the mean result has standard deviation of … a. b. c. d. 0.001 gram 0.000577 gram 0.000333 gram a, b, and c are all incorrect 62% 29% 10% 0% a. b. c. d. Three weighings of a specimen on the scale described previously (Normal with σ = 0.001) give 3.412 grams, 3.416 grams, and 3.414 grams. What is a 95% confidence interval for the true mean weight? a. (3.4129, 3.4151) b. (3.4134, 3.4147) c. (3.409, 3.419) 86% 5% a. b. 10% c. Another specimen is weighed 8 times on the same scale (N, σ = 0.001). The average weight is 4.1602 grams. What is a 99% confidence interval for the true mean weight of this specimen? 90% a. (4.15988, 4.16052) b. (4.15951, 4.16089) c. (4.15929, 4.16111) 10% 0% a. b. c. Same scale (N, σ = 0.001)…How many times must you weigh a specimen in order to get a margin of error no larger than +/0.0005 with 95% confidence? 90% a. b. c. d. 4 times 5 times 15 times 16 times 0% a. 5% b. 5% c. d. An opinion poll says that the result of their latest sample has a margin of error of plus or minus three percentage points, with 95% confidence. This means that… a. b. c. We can be certain that the poll result is within three percentage points of the truth about the population. We could be certain that the poll result is within three percentage points of the truth if there were no nonresponse. The poll used a method that gives a result within three percentage points of the truth in 95% of all samples. 90% 5% a. 5% b. c. A government report says that a 90% confidence interval for the mean income of American households is $59,067 +/- $356. This is based on a random sample of 60,000 households. If the same sample results had come from a sample of 15,000 households, the new margin of error would be… a. b. c. d. +/- $712 +/- $356 +/- $178 a, b, and c are all incorrect 90% 0% a. b. 5% c. 5% d. Suppose that the survey in the previous problem (MOE = $356) had obtained the sample mean $59,067 from a sample of 60,000 households in Ohio (population 11.5 million) instead of from all households in the United States (population 300 million). The margin of error for 90% confidence would be … 95% a. About +/- $356 b. Greater than +/$356 c. Less than +/- $356 0% a. b. 5% c. Same report (MOE=$356 with 90% confidence)…Suppose the report had used 95% confidence rather than 90% confidence. The margin of error would be… 95% a. +/- $356 b. Greater than +/$356 c. Less than +/- $356 5% 0% a. b. c. Data on the blood cholesterol levels of 6 rats (milligrams per deciliter of blood) give a sample mean of 85 and a sample standard deviation of 12. A 95% confidence interval for the mean blood cholesterol of rats under this condition is… 76% a. (72.4, 97.6) b. (73.0, 97.0) c. (75.4, 94.6) 24% 0% a. b. c. We prefer the t procedures to the z procedures for inference about a population mean because… 100% a. Z can be used only for large samples b. Z requires that you know the population standard deviation c. Z requires that you can regard your data as an SRS from the population 0% a. 0% b. c. You have an SRS of 15 observations from a Normally distributed population with s = 1.765. What critical value would you use to obtain a 98% confidence interval for a population mean? a. b. c. d. 2.326 2.602 2.624 a, b, and c are all incorrect 67% 29% 5% 0% a. b. c. d. Which of the following math terms is correctly spelled? a. b. c. d. e. f. g. h. Pythagorean Isocseles Supplimentary Statisticaly Empiracal Rule Test of Significants Criticle Value Parrabola 13% 13% a. b. 13% 13% 13% c. d. e. 13% f. 13% 13% g. h.