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HW Day 17 2.4 WS Reasoning Using Properties from Algebra Name___________________ Period______Date_________ ____ 1. Which of the following is an example of the Transitive Property? a. b. c. d. ____ 2. If PQ = 3 and PQ + RS = 5, then 3 + RS = 5 is an example of the __________. a. Substitution Property of Equality b. Multiplication Property of Equality c. Transitive Property of Equality d. Reflexive Property of Equality bisects HNK. 3. a. Write an equation that shows the relationship between mHNJ and mJNK. b. Solve the equation and write a reason for each step. c. Find mHNK. Explain how you got your answer. . 4. Name the property which justifies the following conclusion: Given: Conclusion: 5. Name the property which justifies the following conclusion: Given: Conclusion: Identify the property that makes the statement true. 6. If XY = MN, then MN = XY. 7. If mP = mR and mR = mT, then mP = mT. 8. If MP = PQ and PQ = QR, then MP = QR. 9. If m1 + m2 = 25° and m1 = 9°, then 10. Solve the equations and write a reason for each step: a) b) c) . 2.4 WS Answer Section 1. ANS: D PTS: 1 DIF: Level A REF: MLGE0178 NAT: NCTM 9-12.ALG.2.b TOP: Lesson 2.5 Reason Using Properties from Algebra KEY: equality | symmetric | transitive | reflexive BLM: Knowledge NOT: 978-0-618-65613-4 2. ANS: A PTS: 1 DIF: Level A REF: MHGT0089 NAT: NCTM 9-12.ALG.2.b TOP: Lesson 2.5 Reason Using Properties from Algebra KEY: property | substitution | multiplication | transitive | reflexive BLM: Knowledge NOT: 978-0-618-65613-4 3. ANS: a. 3x – 4 = 2(x + 2) b. x = 8. 3x – 4 = 2x + 4, Distributive Property; 3x = 2x + 8, Addition Property of Equality; x = 8, Subtraction Property of Equality c. mHNK = 40. If x = 8, then mHNJ = 3(8) – 4 = 20 and mJNK = 2(8 + 2) = 20. mHNK = mHNJ + mJNK = 20 + 20 = 40. PTS: 1 DIF: Level C REF: GEO.02.05.MS.04 NAT: NCTM 9-12.ALG.2.b | NCTM 9-12.ALG.2.c STA: AZ.AZGLA.MTH.03.9-12.3.2.PO 7 | AZ.AZGLA.MTH.03.9-12.3.3.PO 4 | AZ.AZGLA.MTH.03.9-12.3.3.PO 5 TOP: Lesson 2.5 Reason Using Properties from Algebra KEY: Multi-Step | Angle bisector | Algebra BLM: Analysis NOT: 978-0-618-65613-4 4. ANS: Substitution property of equality PTS: 1 DIF: Level B REF: MLGE0454 NAT: NCTM 9-12.ALG.2.b STA: AZ.AZGLA.MTH.03.9-12.1.1.PO 2 TOP: Lesson 2.5 Reason Using Properties from Algebra KEY: property | distributive | substitution | algebra | equality | transitive BLM: Comprehension NOT: 978-0-618-65613-4 5. ANS: Multiplication property of equality PTS: 1 DIF: Level B REF: MLGE0455 NAT: NCTM 9-12.ALG.2.b TOP: Lesson 2.5 Reason Using Properties from Algebra KEY: property | multiplication | algebra | addition | equality | transitive BLM: Comprehension NOT: 978-0-618-65613-4 6. ANS: Symmetric Property of Equality PTS: TOP: KEY: NOT: 7. ANS: 1 DIF: Level A REF: BS022081 Lesson 2.5 Reason Using Properties from Algebra property | segment | TAAS2 | symmetric | TEKSb3E 978-0-618-65613-4 NAT: NCTM 9-12.ALG.2.b BLM: Knowledge Transitive Property of Equality PTS: 1 DIF: Level A REF: BS022082 STA: AZ.AZGLA.MTH.03.9-12.4.1.PO 6 TOP: Lesson 2.5 Reason Using Properties from Algebra KEY: property | angle | TAAS2 | TEKSb3E | transitive NOT: 978-0-618-65613-4 8. ANS: Transitive Property of Equality NAT: NCTM 9-12.ALG.2.b PTS: 1 DIF: Level A REF: BS022083 TOP: Lesson 2.5 Reason Using Properties from Algebra KEY: property | segment | TAAS2 | TEKSb3E | transitive NOT: 978-0-618-65613-4 9. ANS: Substitution Property of Equality NAT: NCTM 9-12.ALG.2.b PTS: 1 DIF: Level A REF: BS022084 TOP: Lesson 2.5 Reason Using Properties from Algebra KEY: property | angle | substitution | TAAS2 | TEKSb3E NOT: 978-0-618-65613-4 10. ANS: a) x=3 b) x= 6/11 c) x=18 NAT: NCTM 9-12.ALG.2.b PTS: 1 BLM: Knowledge BLM: Knowledge BLM: Knowledge