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10.5 Other Angles In a Circle Vertex on the circle When the vertex of the angle is on the circle, the measure of the angle is half the intercepted arc. Formed by two chords Formed by chord and tangent Chord/Tangent Two Chords What are the missing measures? m CD on AB = 53.73 C m GF on EF = 130.06 D G A E B F mGFH = 65.02 mCBD = 26.86 Angles inside the Circle If two chords intersect inside the circle, then the angle is the average of the intercepted arcs of the vertical angles. (half the sum) 80 ° What is the measure of Angle 1? ½( 80 + 30) 1 30° = 55 ° Angles Outside the Circle If a tangent/ tangent, secant/secant or tangent/secant intersect outside a circle the angle formed is half the difference of the intercepted arcs. a b Tangent/tangent a b Secant/secant a b Tangent/secant Angle = ½ (a-b) GUIDED PRACTICE for Example 1 Find the indicated measure. SOLUTION 1 m 1 = 2 (210o) = 105o SOLUTION o (98 ) 2 m TSR = = 196o GUIDED PRACTICE Find the value of the variable. SOLUTION The chords AC and CD intersect inside the circle. 1 (mAB + mCD) Use Theorem 10.12. 78° = 2 78o = 1 o (y + 95o) 2 Substitute. 156 = y +95 Simplify. 61 = y GUIDED PRACTICE Find the value of the variable. SOLUTION The tangent JF and the secant JG intersect outside the circle. 1 (mFG – mKH) Use Theorem 10.13. m FJG = 2 30o = 1 o (a – 44o) 2 Substitute. 60 = a - 44 Simplify. a = 104 CP GUIDED PRACTICE Find the value of the variable. SOLUTION Congruent triangles (HL) Trig using 3-4-5 m TQR = 1 (mTUR – mTR) 2 Use Theorem 10.13. 1 [(xo) –(360 –x)o] Substitute. 2 147.4 = x – 360 + x Solve for x. 73.7o 507.4 = 2x xo 253.7 Review of all angles with circles • Central angle = the intercepted arc. • Vertex on circle = half the intercepted arc. (chords sharing common endpoint or a chord and a tangent intersecting on circle.) • Vertex inside circle = half the sum • Vertex outside circle = half the difference Central = Inside –half sum On –half arc Outside---half difference Geometry Page 683 (1-6, 9-14,16-18,22-25,3439) Sophomore Math Page 683 (1-16, 22)