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Gene Interactions Chapter 4 I. Genotype-Phenotype Relationship • • Pleiotrophy Polygeny I A. Pleiotrophy • • • One gene locus can affect several different aspects of phenotype Diachete mutation in Drosophila has both dominant and recessive effects Dominant effects: – – Lateral wings Missing hair on thorax I A. Pleiotrophy • • Recessive effects: – Lethal when homozygous Sickle-cell anemia – – – – Spleen damage Joint pain Tower skull Anemia • Sickle-cell anemia effects • Effect of dominant mutation in rats I B. Polygeny • • One phenotype dependent upon action of many different genes Quantitative inheritance – – Height Weight II. Complementation Test • • Determines if mutants that alter phenotype are allelic (one locus) OR are from different loci Used for recessive alleles II. Complementation Test • • Produce heterozygote and examine phenotype If phenotype wild-type (non-mutant), alleles are complementary and are from different loci 1 • If phenotype mutant, alleles are non complementary and affect same locus (allelic) II. Complementation Test • F1 hybrid a’/a’’ • • Mutant phenotype (no wild dominant alleles) Non-complementary, ONE locus II. Complementation Test • F1 hybrid a1/a2 • • Wild-type phenotype (mutations in different genes) Complementary mutations, TWO loci II. Complementation Test • • • • • Harebell example Wild flowers blue Mutant flowers white Three mutant white homozygous strains When each strain crossed with blue – – F1 blue F2 3:1 blue:white monogenic II. Complementation Test • • Are the three mutants allelic (monogenic) or from different loci? Mutants – – – $ (dollar) £ (pound) ¥ (yen) 2 II. Complementation Test If allelic • Have no wild type alleles • Thus get mutant phenotype (white) II. Complementation Test If different loci • Each mutant supplies wild type allele for other locus • F1 is dihybrid • Have dominant allele at each locus • Have wild type phenotype complementary $x£ • F1 white • No complementation • $ and £ allelic £x¥ • F1 blue • Complementation • £ and ¥ not allelic • Each mutant provides wild allele for other locus • Two loci $x¥ • What would F1 be? • Complementary or non comp? • $ and ¥ allelic or not allelic? • One or two loci? III. Lethal Alleles • • Can alter Mendelian ratios if lethal embryonically Yellow and wild-type mice III. Lethal Alleles P Yellow x Yellow F1 2/3 Yellow, 1/3 Wild-type 3 Why? Two alleles AY – yellow A – wild type III. Lethal Alleles P Yellow x Yellow AY A AY A III. Lethal Alleles • • Sublethals: reduce viability, but not by 100% Also called semi-lethal III. Lethal Alleles • • • • Aa x aa Expect 1:1 ratio May consistently 55 (Aa) : 45 (aa) aa not lethal but reduces viability IV. Gene Interaction and Modified Dihybrid Ratios Normal dihybrid ratio: • 9/16 A_B_ • 3/16 A_bb • 3/16 aaB_ • 1/16 aabb IV. Gene Interaction and Modified Dihybrid Ratios • • • • • If two loci interact 9:3:3:1 ratio modified Modified ratios still on basis of “16” Result of epistasis Genotype at one locus masks or modifies expression of alleles at second locus Broad definition, includes “suppressor” loci discussed in textbook IV A. Co-epistasis 4 • • • • Interacting genes, different biochemical pathways Keep 9:3:3:1 ratio Each “part” of ratio has distinct phenotype Two different biochemical pathways IV A. Co-epistasis: Corn Snake Coloration • Two loci – – o+ = orange color; o = no orange b+ = black color; b = no black IV A. Co-epistasis: Corn Snake Coloration • P orange x o+o+ b/b black o/o b+b+ IV A. Co-epistasis: Corn Snake Coloration • F1 camouflaged o+o b+/b IV A. Co-epistasis: Corn Snake Coloration • F2 9 3 3 1 o+_ o+_ oo oo b+_ bb b+_ bb camouflaged orange black albino IV A. Co-epistasis: Corn Snake Coloration • Two separate biochemical pathways b+ precursor black pigment camouflaged precursor orange pigment o+ IV B. Interacting Genes in SAME Pathway • Will examine mutations – – With same phenotype With different phenotypes IV B 1. Mutations with SAME Phenotype • Harebell: blue or white flowers + + • Dihybrid cross of w1 w1 w2 w2 9 w1+_ w2_ blue • F2 3 w1+_ w2w2 white 3 w1w1 w2+_ white 5 1 w1w1 w2w2 white IV B 1. Mutations with SAME Phenotype • • • Thus, get 9:7 ratio of blue:white Duplicate recessive epistasis Homozygous recessive at either locus blocks effects of other locus w1+ w2+ colorless colorless blue pigment IV B 2. Mutations with Different Phenotypes • • Blue-eyed Mary flower color P white x + + ww m m magenta w w mm + + IV B 2. Mutations with Different Phenotypes • F1 blue w w m+m + IV B 2. Mutations with Different Phenotypes • F2 m+_ blue 9 3 3 1 w+_ m_ ww m+_ ww mm • • 9:3:4 ratio Recessive epistasis • • • • • • One pathway Colorless precursor Intermediate a pigment (magenta) Final product a pigment (blue) Block second step, get magenta Block first step, get white magenta white white IV C. Interacting Genes in Different Pathways • • • Foxglove Flower Petal Coloration Variation controlled by three loci M locus – – M makes anthocyanin (purple) m no anthocyanin (white) IV C. Interacting Genes in Different Pathways • D locus – D makes large amount of anthocyanin (deep purple) 6 w+_ – d makes lesser amount of anthocyanin (light purple) IV C. Interacting Genes in Different Pathways • W locus – – W prevents pigment deposition except in throat spots (speckling effect) w allows even pigment deposition all over petal (even color) IV C. Interacting Genes in Different Pathways • • P dark purple x white w/purple spots MM DD ww MM dd WW As homozygous for MM, ignore IV C. Interacting Genes in Different Pathways • F1 white w/purple spots Dd Ww IV C. Interacting Genes in Different Pathways • F2 • • 9 D_ W_ white w/purple spots 3 dd W_ white w/purple spots 3 D_ ww dark purple 1 dd ww light purple 12:3:1 ratio Dominant epistasis (W epistatic to D locus) Various Epistatic Ratios V. Penetrance and Expressivity V A. Penetrance • • Percentage of individuals with a genotype who show the phenotype associated with that genotype Up to this point, we have assumed full penetrance V A. Penetrance 7 • • • • Eyeless mutation in Drosophila Causes reduction in eye facet number Homozygous recessive (ee) strains – – 85% have reduced eyes 15% appear “wild type” 85% penetrant V A. Penetrance • • • Polydactyly in humans Extra fingers and toes Dominant, yet may skip generations in pedigree V A. Penetrance • • III-2 lacks polydactyly Some progeny of III-2 polydactylous V A. Penetrance in Down Syndrome V A. Penetrance in Klinefelter Syndrome V B. Expressivity • • Even when genotype has phenotypic effect (penetrant), may be range of phenotypic variation Eyeless mutation (ee) – – Of the 85% penetrant, range from no eyes to nearly normal Most have ¼ to ½ reduction V B. Expressivity Polydactyly • Extra toes only V B. Expressivity Polydactyly • Extra fingers only V B. Expressivity Polydactyly • Extra fingers AND toes V B. Expressivity Polydactyly • Asymmetrical by side V C. Why is There Variable Penetrance and Expressivity? • Environmental Effects (norm of reaction) 8 • • Epistasis (broad sense, including modifier and suppressor genes) Developmental Noise VI. Conditional Mutants • • Alleles expressed only under narrow range of environmental conditions Change environment, change phenotype VI A. Temperature Effects • • • C locus of Mammals allows color expression (c blocks color expression) cc epistatic to other loci albinism ch (Himalayan) allele heat sensitive enzyme – – Warm temperature, enzyme inactive, pigment not made Cooler temperature, enzyme active, pigment made Himalayan Rabbit • Abdomen/thorax warmer, enzyme inactive white • Ears, nose, paws cooler, enzyme active black • If shave hairs on back and cool the region, new hair black VI B. Nutritional Effects • Lethal mutant: lack of enzyme in metabolic pathway for some molecule – – Amino acid synthesis Toxin degradation VI B. Nutritional Effects Neurospora • Leucine deficient (leu-) strain • Can’t make leucine VI B. Nutritional Effects Neurospora • Grown on minimal media leu- strains can’t grow • Which of the 20 spots are leu+? VI B. Nutritional Effects Neurospora • Shown are colonies on miminal media + leucine • Represents leu+ cultures that grew on minimal media VI B. Nutritional Effects Neurospora 9 • So which colonies are leu-? VI B. Nutritional Effects Neurospora • If leucine present, leu- strains live • If leucine absent, leu- strains die VI B. pH Effects • • • Lousewort Two color phases, yellow and red Color differences due to soil pH VI B. pH Effects • • • • pH 6.5 yellow pH 5.8 red Extract yellow pigment, lower pH to 5.8, turns red Dr. Newberry Last revised 8 September 2003 10