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Algebra 1 Honors
4.3 Solving an equation for “y”
**Solving for “y” means to rearrange the given equation so the “y” is on the left of the = sign
and the “x” term and constant (# with no variable) are on the right.
This concept will be used quite a bit in Unit 5 to graph an equation. So make sure you MASTER
it!
y = mx + b
Constant (# w/ no variable)
x-term
Teacher
a.
2x + y = 6
Student
-3x + y = -2
b.
–4x – y = 3
-5x – y = 6
c.
5x - 2y = 8
d.
x + 3y + 5 = 9
2 - x + 4y = 8
e.
4(x + 3y) = -y + 3
6(x - 2y) = 2y - 7
2x - 3y = -3
Reference Glencoe Textbook: Page 167 and 215 (ex: 2)
4.3 ASSIGNMENT:
Solve each equation for y.
1.
x + y = -2
2.
y + 4x = 8
3.
-7x + y = 9
4.
5.
-2x + y = 5 – 4x
6.
-x + y – 8 = 1
-3x + y = 6
C Level
7.
4x - y = -8
8.
-3x - y = 6
9.
-7x - y = 9
B Level
10.
13.
2y + 6x = 10
10x + 6y = y - 15
11.
14.
-2x – 5y = 10
-9x + 10y = 2y - 24
Reference Glencoe Textbook: Page 167 and 215 (ex: 2)
12.
15.
-x – 3y = 9
A Level (16-18 only)
3x - 2y = 4y + 6
16.
5(x + y) = 2y - 13
17.
3(2x - y) = y - 8
18.
-(x - 4y) = 7y + 2
Practice Test
Level C
1C.
Solve the equation for y.
Level B
1B.
Solve the equation for y.
5x - y = -12
Level A
1A.
Solve the equation for y.
6x – 9y = 9
3(x + 2y) = 4y - 5
ANSWERS
1. y = -x – 2
2. y = -4x + 8
3. y = 7x + 9
4. y = 3x + 6
5. y = -2x + 5
6. y = x + 9
7. y = 4x + 8
8. y = -3x - 6
9. y = -7x - 9
10. y = -3x + 5
2
11. y   x  2
5
1
12. y   x  3
3
13. y = -2x - 3
14. y 
17. y 
3
x 2
2
PRACTICE TEST
9
x 3
8
15. y 
1
x -1
2
5
13
16. y   x 3
3
y 
2
x -1
3
1A
1
2
18. y   x 3
3
1C y = 5x + 12
Reference Glencoe Textbook: Page 167 and 215 (ex: 2)
1B
3
5
y  x 2
2