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02.08-text.pdf
02.08-text.pdf

... • In those instances in which the IVP (1) is known to have a unique solution (i.e., the conditions of Theorem 2.8.1 are met), one can start with a simple function φ0 that in no way solves (1), and generate a sequence of functions (called Picard iterates) φ1 , φ2 , φ3 , . . . iteratively by ...
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... Suppose, in general, that we have two functions, f(x) and g(x). Then y = f(g(x)) is a function of a function. In our case, the function f is the outer function i.e. ()10 and the function g is the inner function i.e (2x – 5) In order to differentiate a function of a function, y = f(g(x)), we need to ...
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... 1) What is a function from X to Y? Answer: Let X and Y be sets. A function f from X to Y is a subset of the Cartesian product X  Y having the property that for each x  X , there is exactly one y  Y with ( x, y )  f . 2) Given a set of points in the plane, how can we tell whether it is a function ...
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... Theorem 3.5 – Let f be a function that is continuous on the closed interval [a, b] and differentiable on the open interval (a, b). 1. If f '  x   0 for all x in (a, b), then f is increasing on [a, b]. 2. If f '  x   0 for all x in (a, b), then f is decreasing on [a, b]. 3. If f '  x   0 for ...
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