Addition Rule for disjoint events
... Rule 4. Two events A and B are disjoint if they have no outcomes in common and so can never occur simultaneously. If A and B are disjoint, P(A or B) = P(A) + P(B) This is the addition rule for disjoint events. Venn diagram- A helpful way to remind ourselves of the complement and disjoint events. Sho ...
... Rule 4. Two events A and B are disjoint if they have no outcomes in common and so can never occur simultaneously. If A and B are disjoint, P(A or B) = P(A) + P(B) This is the addition rule for disjoint events. Venn diagram- A helpful way to remind ourselves of the complement and disjoint events. Sho ...
Ch5 - ASU
... (not E) - the event that E does not occur (complement of E) (A & B) - the event that both A and B occur. (A or B) - the event that either A or B or both occur. Mutually Exclusive Events Two or more events are said to be mutually exclusive if at most one of them can occur when the experiment is perfo ...
... (not E) - the event that E does not occur (complement of E) (A & B) - the event that both A and B occur. (A or B) - the event that either A or B or both occur. Mutually Exclusive Events Two or more events are said to be mutually exclusive if at most one of them can occur when the experiment is perfo ...
Discrete_Probability.. - SIUE Computer Science
... about Big-O or Theta, it is often possible to make simplifying assumptions. ...
... about Big-O or Theta, it is often possible to make simplifying assumptions. ...
K.K. Gan Physics 416 Problem Set 2 Due Thursday, October 28, 2004
... a) If an evil country launches 20 missiles what is the probability that the missile defense system will destroy all of the incoming missiles? b) How many missiles have to be launched to have a 50% chance of at least one missile making it through the defense system? Note: this problem can be done usi ...
... a) If an evil country launches 20 missiles what is the probability that the missile defense system will destroy all of the incoming missiles? b) How many missiles have to be launched to have a 50% chance of at least one missile making it through the defense system? Note: this problem can be done usi ...
probability of an event
... device called a tree diagram is useful for determining the sample space. Example Flip a Penny, Nickel, and a Dime Event - Any subset of the sample space ...
... device called a tree diagram is useful for determining the sample space. Example Flip a Penny, Nickel, and a Dime Event - Any subset of the sample space ...
Section 6.3 geometric distribution
... problems because you are waiting until the first event of something happens. These problems also differ from binomial distribution problems because the number of ______________ is not fixed. The number of trials for each situation is the number of times it takes until the first occurrence of the eve ...
... problems because you are waiting until the first event of something happens. These problems also differ from binomial distribution problems because the number of ______________ is not fixed. The number of trials for each situation is the number of times it takes until the first occurrence of the eve ...
Harvard University
... (C) If the total roll is 4 then keep rolling the dice until the total is again 4 (in which case you win) or the total is 7 (in which case you lose). By restricting the sample space S to rolls of 4 or 7, calculate the probability that you will win after rolling a 4 for the first time. Solution. ...
... (C) If the total roll is 4 then keep rolling the dice until the total is again 4 (in which case you win) or the total is 7 (in which case you lose). By restricting the sample space S to rolls of 4 or 7, calculate the probability that you will win after rolling a 4 for the first time. Solution. ...
AP Statistics
... two of them to attend a conference in Chicago. To avoid unfairness, the choice will be made by drawing two names from a hat. (This is a sample size of 2.) (a) Write down all possible choices of two of the five names. For convenience, you can simply use the first letter of their names. ...
... two of them to attend a conference in Chicago. To avoid unfairness, the choice will be made by drawing two names from a hat. (This is a sample size of 2.) (a) Write down all possible choices of two of the five names. For convenience, you can simply use the first letter of their names. ...
1. Additive law of probability
... Example: From a pack of 52 cards, one card is drawn at random. Find the probability that the card is “Heart” or “Ace”. Four suits are : Spades, Diamonds, Clubs and Hearts. Each suit has 13 cards: Ace,2,3,4,5,6,7,8,9,10,Jack, Queen and King. There are four of each type, like 4 Aces,4 Jacks, 4 Queens, ...
... Example: From a pack of 52 cards, one card is drawn at random. Find the probability that the card is “Heart” or “Ace”. Four suits are : Spades, Diamonds, Clubs and Hearts. Each suit has 13 cards: Ace,2,3,4,5,6,7,8,9,10,Jack, Queen and King. There are four of each type, like 4 Aces,4 Jacks, 4 Queens, ...
Chapter 6: Probability (word document)
... For the experiment of rolling two dice, let E1 = “The sum of the numbers is greater than 9” and E3 = “The numbers on the two dice are equal”. Determine the sets E1 ∪ E3, E1 ∩ E3, and (E1 ∪ E3)'. ...
... For the experiment of rolling two dice, let E1 = “The sum of the numbers is greater than 9” and E3 = “The numbers on the two dice are equal”. Determine the sets E1 ∪ E3, E1 ∩ E3, and (E1 ∪ E3)'. ...
P(A B)
... • State the addition rule for disjoint events • State the general addition rule for union of two events • Given any two events A and B, compute P(A B) • Given two events, compute their joint probability • Use the general multiplication rule to define P(B | A) ...
... • State the addition rule for disjoint events • State the general addition rule for union of two events • Given any two events A and B, compute P(A B) • Given two events, compute their joint probability • Use the general multiplication rule to define P(B | A) ...
