DYNAMICS AND RELATIVITY (PART II)
... A non-conservative force is a force where the work done by a force moving an object from point A to point B depends on the path taken. This is sometimes called a dissipative force. A good example of a non-conservative force is friction. The frictional force always opposes the motion so ...
... A non-conservative force is a force where the work done by a force moving an object from point A to point B depends on the path taken. This is sometimes called a dissipative force. A good example of a non-conservative force is friction. The frictional force always opposes the motion so ...
Coulomb`s Law - hrsbstaff.ednet.ns.ca
... Fe12 x = 0 N Fe12 y = 3.4 x10 −3 N Fe 23 x = 5.4 x10 −3 N cos 233 Fe 23 x = −3.2 x10 −3 N Fe 23 y = 5.4 x10 −3 N sin 233 Fe 23 y = −4.3 x10 −3 N ...
... Fe12 x = 0 N Fe12 y = 3.4 x10 −3 N Fe 23 x = 5.4 x10 −3 N cos 233 Fe 23 x = −3.2 x10 −3 N Fe 23 y = 5.4 x10 −3 N sin 233 Fe 23 y = −4.3 x10 −3 N ...
Exam 1 Solutions
... +5Q, respectively. What is the charge on the inner surface of the outermost shell? The electric field must be zero inside an isolated conductor. So a spherical Gaussian surface within each conductive shell must have zero flux since E=0, which implies that by Gauss’ Law the enclosed charge must be ze ...
... +5Q, respectively. What is the charge on the inner surface of the outermost shell? The electric field must be zero inside an isolated conductor. So a spherical Gaussian surface within each conductive shell must have zero flux since E=0, which implies that by Gauss’ Law the enclosed charge must be ze ...
Lesson 7 (1) Definition of Electric Potential Consider the electric field
... If the test charges moves from the point A to B along a path, the work done can be calculated by dividing the path into small displacements and adding the work done along the displacements. In the limit when these displacements go to zero, we find the work done along the path from A to B in the form ...
... If the test charges moves from the point A to B along a path, the work done can be calculated by dividing the path into small displacements and adding the work done along the displacements. In the limit when these displacements go to zero, we find the work done along the path from A to B in the form ...
19-2 The Magnetic Force on a Charged Object
... The right-hand rule for determining the direction of the magnetic force on a moving charge First, make sure you use your right hand! Also, refer to Figure 19.7. • Point the fingers on your right hand in the direction of the charge’s velocity. • While keeping your fingers aligned with the velocity, r ...
... The right-hand rule for determining the direction of the magnetic force on a moving charge First, make sure you use your right hand! Also, refer to Figure 19.7. • Point the fingers on your right hand in the direction of the charge’s velocity. • While keeping your fingers aligned with the velocity, r ...
13 particle accelerators
... the actual number of events observed is a random distribution with that probability. √ If a cross-section predicts N events over a given time-period, the error on that number is N (this means √ that there is √ a 68% probability that the number of events observed will lie in the region N − N to N = N ...
... the actual number of events observed is a random distribution with that probability. √ If a cross-section predicts N events over a given time-period, the error on that number is N (this means √ that there is √ a 68% probability that the number of events observed will lie in the region N − N to N = N ...
Exam I
... Please read the problems carefully and answer them in the space provided. Write on the back of the page, if necessary. Show all your work. Partial credit will be given. Problem 1 (multiple choice, no partial credit, 20 pts): i) Two point charges of unknown magnitude and sign are a distance d apart. ...
... Please read the problems carefully and answer them in the space provided. Write on the back of the page, if necessary. Show all your work. Partial credit will be given. Problem 1 (multiple choice, no partial credit, 20 pts): i) Two point charges of unknown magnitude and sign are a distance d apart. ...
Calculations
... 26. A circuit is shown on the right, made up of 3 resistors (20ohm, 30 ohm, and 50ohm.) The current is tested at 2A. a) Calculate the total resistance b) Calculate the voltage needed to power the circuit. 27. A television converts 12,000 joules of electrical energy into light and sound every minute. ...
... 26. A circuit is shown on the right, made up of 3 resistors (20ohm, 30 ohm, and 50ohm.) The current is tested at 2A. a) Calculate the total resistance b) Calculate the voltage needed to power the circuit. 27. A television converts 12,000 joules of electrical energy into light and sound every minute. ...
