Phy107Fall06Lect08
... • Speed at bottom of ramp should be related to change in potential energy. • On flat section, use timer and distance traveled to determine speed. ...
... • Speed at bottom of ramp should be related to change in potential energy. • On flat section, use timer and distance traveled to determine speed. ...
4.1 The Concepts of Force and Mass
... Rain comes down with a velocity of -15 m/s and hits the roof of a car. The mass of rain per second that strikes the roof of the car is 0.060 kg/s. Assuming that rain comes to rest upon striking the car, find the average force exerted by the rain on the roof. ...
... Rain comes down with a velocity of -15 m/s and hits the roof of a car. The mass of rain per second that strikes the roof of the car is 0.060 kg/s. Assuming that rain comes to rest upon striking the car, find the average force exerted by the rain on the roof. ...
Knight25CT
... An electron is fired into the region of the three charges from the lower right as shown. What is the direction of the acceleration of the electron when it is at point x? ...
... An electron is fired into the region of the three charges from the lower right as shown. What is the direction of the acceleration of the electron when it is at point x? ...
Document
... In each of the four cases shown below, a particle of charge +q is placed a distance d from a particle of charge +4q. The particles are then released simultaneously. The masses of the particles are indicated in the diagram. Rank the magnitude of the acceleration of the RIGHT HAND particle just after ...
... In each of the four cases shown below, a particle of charge +q is placed a distance d from a particle of charge +4q. The particles are then released simultaneously. The masses of the particles are indicated in the diagram. Rank the magnitude of the acceleration of the RIGHT HAND particle just after ...
3.Momentum
... Total Momentum of a System of Objects • A “System” is an object or a collection of objects. • The Total Momentum of a system equals the vector sum of the momenta of all the objects in the system: • PTotal System = P1 + P2 (for a system of two objects) • Also called the “Net Momentum”: PNET • EXAMPL ...
... Total Momentum of a System of Objects • A “System” is an object or a collection of objects. • The Total Momentum of a system equals the vector sum of the momenta of all the objects in the system: • PTotal System = P1 + P2 (for a system of two objects) • Also called the “Net Momentum”: PNET • EXAMPL ...
File
... This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permit ...
... This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permit ...
PhysicsNotes QRECT Video Version With MetaNumber Feb 19 2013.pdf
... 3.2 Projectile motion in two dimensions using vectors r(t) = (x(t) , y(t) ) and v(t) = (vx(t) , vy(t)) ............ 11 3.3 Graphical view of motion in a river or with an air current using vectors graphically ........................... 11 3.4 More complex projectile problems ........................ ...
... 3.2 Projectile motion in two dimensions using vectors r(t) = (x(t) , y(t) ) and v(t) = (vx(t) , vy(t)) ............ 11 3.3 Graphical view of motion in a river or with an air current using vectors graphically ........................... 11 3.4 More complex projectile problems ........................ ...
The Laws of Motion (Dynamics
... 1. State Newton’s First Law of Motion as: “If there is no net resultant force acting on an object, then if it is at rest, it will remain at rest and if it is moving with constant velocity, it will continue to do so” 2. State Newton’s Second Law of Motion as: “The net resultant force acting on an obj ...
... 1. State Newton’s First Law of Motion as: “If there is no net resultant force acting on an object, then if it is at rest, it will remain at rest and if it is moving with constant velocity, it will continue to do so” 2. State Newton’s Second Law of Motion as: “The net resultant force acting on an obj ...
Semester 1 Final Jeopardy Review
... A softball is tossed horizontally from a treehouse 4 meters tall, and the ball lands 20 meters from the treehouse. How fast was the ball thrown? dx = vxt and dy = (1/2)at2 t = √(2 dy/a) where dy = 4 m t = √[2(4 m)/(10 m/s2] = 0.894 sec v = dx / t = 20m / 0.894 sec v = 22.4 m/s ...
... A softball is tossed horizontally from a treehouse 4 meters tall, and the ball lands 20 meters from the treehouse. How fast was the ball thrown? dx = vxt and dy = (1/2)at2 t = √(2 dy/a) where dy = 4 m t = √[2(4 m)/(10 m/s2] = 0.894 sec v = dx / t = 20m / 0.894 sec v = 22.4 m/s ...
KEY - AP Physics– Electrostatics – FR 1 #1 (1975
... b. Resolving the tension into components we have T cos = W and T sin = F where W = mg and F = kq2/r2 and r = 2l sin giving F = kq2/(4l2 sin2) Dividing the two expressions we get tan = F/mg = kq2/(4l2 sin2 mg) solving yields q2 = 4mgl2 (sin2)(tan )/k ...
... b. Resolving the tension into components we have T cos = W and T sin = F where W = mg and F = kq2/r2 and r = 2l sin giving F = kq2/(4l2 sin2) Dividing the two expressions we get tan = F/mg = kq2/(4l2 sin2 mg) solving yields q2 = 4mgl2 (sin2)(tan )/k ...
