ch08_LecturePPT
... rotational velocity of 5 rev/s about a vertical axis. The rotational inertia of the wheel is 2 kg·m2 about its center and the rotational inertia of the student and wheel and platform about the rotational axis of the platform is 6 kg·m2. What is the initial angular momentum of the system? a) ...
... rotational velocity of 5 rev/s about a vertical axis. The rotational inertia of the wheel is 2 kg·m2 about its center and the rotational inertia of the student and wheel and platform about the rotational axis of the platform is 6 kg·m2. What is the initial angular momentum of the system? a) ...
Oscillations
... Questions 29-30. A block on a horizontal frictionless plane is attached to a spring, as shown above. The block oscillates along the x-axis with simple harmonic motion of amplitude A. 29. Which of the following statements about the block is correct? (A) At x = 0, its velocity is zero. (B) At x = 0, i ...
... Questions 29-30. A block on a horizontal frictionless plane is attached to a spring, as shown above. The block oscillates along the x-axis with simple harmonic motion of amplitude A. 29. Which of the following statements about the block is correct? (A) At x = 0, its velocity is zero. (B) At x = 0, i ...
Basic Equations
... In this version of the continuity equation it is assumed that the particle number is conserved, i.e. no particles are generated or annihilated, or integrating ρ over the total volume where particles might be, always gives the same number. This is the continuity assumption. This is a perfectly good a ...
... In this version of the continuity equation it is assumed that the particle number is conserved, i.e. no particles are generated or annihilated, or integrating ρ over the total volume where particles might be, always gives the same number. This is the continuity assumption. This is a perfectly good a ...
The Milky Way
... for objects at rest to stay at rest and objects in motion to stay in uniform motion in a straight line. How do we measure inertia? MASS ...
... for objects at rest to stay at rest and objects in motion to stay in uniform motion in a straight line. How do we measure inertia? MASS ...
Coriolis Force
... Conservation of absolute angular momentum. Consider a parcel of air or water with constant mass, m, moving with constant speed, v, in a circular orbit. According to Newton’s second law, the parcel must conserve absolute angular momentum (i.e., angular momentum in the absolute frame of reference). Th ...
... Conservation of absolute angular momentum. Consider a parcel of air or water with constant mass, m, moving with constant speed, v, in a circular orbit. According to Newton’s second law, the parcel must conserve absolute angular momentum (i.e., angular momentum in the absolute frame of reference). Th ...
Electric Potential - University of Waterloo
... (a)- Find the potential difference by moving a positive test charge q0 from i to f along the path (i-f) shown in figure (a). (b)- Find the potential difference by moving a positive test charge q0 from i to f along the path i-c-f shown in figure (b). ...
... (a)- Find the potential difference by moving a positive test charge q0 from i to f along the path (i-f) shown in figure (a). (b)- Find the potential difference by moving a positive test charge q0 from i to f along the path i-c-f shown in figure (b). ...
1 CHAPTER 9 MAGNETIC POTENTIAL 9.1 Introduction We are
... Can we express the magnetic field B in a similar manner as the gradient of some potential function ψ, so that, for example, B = −grad ψ = −= =ψ ? Before answering this, we note that there are some differences between E and B . Unlike E, the magnetic field B is sourceless; there are no sources or sin ...
... Can we express the magnetic field B in a similar manner as the gradient of some potential function ψ, so that, for example, B = −grad ψ = −= =ψ ? Before answering this, we note that there are some differences between E and B . Unlike E, the magnetic field B is sourceless; there are no sources or sin ...
PHYS 1443 – Section 501 Lecture #1
... We will first learn about mechanics of fluid at rest, fluid statics. In what way do you think fluid exerts stress on the object submerged in it? Fluid cannot exert shearing or tensile stress. Thus, the only force the fluid exerts on an object immersed in it is the forces perpendicular to the surface ...
... We will first learn about mechanics of fluid at rest, fluid statics. In what way do you think fluid exerts stress on the object submerged in it? Fluid cannot exert shearing or tensile stress. Thus, the only force the fluid exerts on an object immersed in it is the forces perpendicular to the surface ...
PowerPoint Presentation - Chapter 15 Thermodynamics
... rotational velocity of 5 rev/s about a vertical axis. The rotational inertia of the wheel is 2 kg·m2 about its center and the rotational inertia of the student and wheel and platform about the rotational axis of the platform is 6 kg·m2. What is the initial angular momentum of the system? a) ...
... rotational velocity of 5 rev/s about a vertical axis. The rotational inertia of the wheel is 2 kg·m2 about its center and the rotational inertia of the student and wheel and platform about the rotational axis of the platform is 6 kg·m2. What is the initial angular momentum of the system? a) ...
Ch17 Oscillations
... 11.6 cm from equilibrium and released. Take time t=0 when the block is released, the horizontal surface is frictionless. (a) What is the total energy? (b) What is the maximum speed of the block? (c) What is the maximum acceleration? (d) What is the position, velocity, and acceleration at t=0.215s? ...
... 11.6 cm from equilibrium and released. Take time t=0 when the block is released, the horizontal surface is frictionless. (a) What is the total energy? (b) What is the maximum speed of the block? (c) What is the maximum acceleration? (d) What is the position, velocity, and acceleration at t=0.215s? ...
Exam No. 1 Solutions
... by inspection. Second, because P is on the line bisecting the 2 positive charges (located at (a, 0) and (0, -a)), the portions of the field perpendicular to that bisecting line will cancel, leaving a field pointing along that line, or at 45° above the –x-axis. Alternative approach –The direction is ...
... by inspection. Second, because P is on the line bisecting the 2 positive charges (located at (a, 0) and (0, -a)), the portions of the field perpendicular to that bisecting line will cancel, leaving a field pointing along that line, or at 45° above the –x-axis. Alternative approach –The direction is ...
3 - USNA
... In a hydrostatic fluid, the only surface force acting in the medium is pressure. The resultant stress field and stress tensor are isotropic since the force acts equally in all directions. Quantitatively, the requirement of isotropy means that the components of the tensor do not change when the coord ...
... In a hydrostatic fluid, the only surface force acting in the medium is pressure. The resultant stress field and stress tensor are isotropic since the force acts equally in all directions. Quantitatively, the requirement of isotropy means that the components of the tensor do not change when the coord ...
1. In which of the following situations would an object be accelerated?
... In which of the following situations would an object be accelerated? I. It moves in a straight line at constant speed. II. It moves with uniform circular motion. III. It travels as a projectile in a gravitational field with negligible air resistance. (A) I only (B) III only (C) I and II only (D) II ...
... In which of the following situations would an object be accelerated? I. It moves in a straight line at constant speed. II. It moves with uniform circular motion. III. It travels as a projectile in a gravitational field with negligible air resistance. (A) I only (B) III only (C) I and II only (D) II ...