Scenario: Phage Wars Identification of a Bacteriophage 80α
... the cell resistant to infection by other, unrelated bacteriophages. This is mechanistically different than the immunity to superinfection by related phages discussed above, and may target phage adsorption, replication, or other functions. The ability of a prophage to block infection by an unrelated ...
... the cell resistant to infection by other, unrelated bacteriophages. This is mechanistically different than the immunity to superinfection by related phages discussed above, and may target phage adsorption, replication, or other functions. The ability of a prophage to block infection by an unrelated ...
Biology Midterm Review Guide: 2007-08
... 1. What is the difference between a prokaryote and eukaryote cell – prokaryotic lacks a nucleus and most other organelles - eukaryotic cell has a membrane bound nucleus and organelles 2. Why is the phospholipid bilayer important- regulates the transport of substances across it, hydrophilic heads and ...
... 1. What is the difference between a prokaryote and eukaryote cell – prokaryotic lacks a nucleus and most other organelles - eukaryotic cell has a membrane bound nucleus and organelles 2. Why is the phospholipid bilayer important- regulates the transport of substances across it, hydrophilic heads and ...
c-fos Protein Can Induce Cellular Transformation: A Novel
... show that even though the c-fos protein is completely different from the v-fos protein at its C terminus, it is capable of transforming cultured fibroblasts. However, activation of the transforming potential of the c-fos gene requires two manipulations-a transcriptional enhancer sequence must be lin ...
... show that even though the c-fos protein is completely different from the v-fos protein at its C terminus, it is capable of transforming cultured fibroblasts. However, activation of the transforming potential of the c-fos gene requires two manipulations-a transcriptional enhancer sequence must be lin ...
Document
... • Cross-shaped configuration at meiosis I • Crossing-over results in gene imbalance, semisterility ...
... • Cross-shaped configuration at meiosis I • Crossing-over results in gene imbalance, semisterility ...
Slide
... Two type of families have dramatically different dynamics of molecular evolution: E-families diverge slowly, but persist for a long periods of time, thus diverging further than the paralogs in N-families N-families undergoes a more dynamic evolution: many duplicate get fixated, many other become pse ...
... Two type of families have dramatically different dynamics of molecular evolution: E-families diverge slowly, but persist for a long periods of time, thus diverging further than the paralogs in N-families N-families undergoes a more dynamic evolution: many duplicate get fixated, many other become pse ...
The liquid drop nature of nucleoli
... is coupled transcription and translation in prokaryotes whereby translation of an mRNA begins while it is still in the process of being transcribed.13 The resulting physical connection might coordinate the relative positions of gene, RNA polymerase, mRNA, and even the destination of the folded prote ...
... is coupled transcription and translation in prokaryotes whereby translation of an mRNA begins while it is still in the process of being transcribed.13 The resulting physical connection might coordinate the relative positions of gene, RNA polymerase, mRNA, and even the destination of the folded prote ...
sequence analysis of the 5` coi gene region from dama
... appearance of the Consortium for the Barcoding of Life (CBOL), which proposed as a standard for species identification, a 648bp mtDNA sequence, from the 5’ end of the cytochrome oxidase gene (Hebert et al., 2003, Stoeckle, 2003). For those groups where the COI gene proved unable to distinguish betwe ...
... appearance of the Consortium for the Barcoding of Life (CBOL), which proposed as a standard for species identification, a 648bp mtDNA sequence, from the 5’ end of the cytochrome oxidase gene (Hebert et al., 2003, Stoeckle, 2003). For those groups where the COI gene proved unable to distinguish betwe ...
BRED: Bacteriophage Recombineering with
... a. For deletions or small insertions, you will order an ~100 nt oligo with 50 nt of homology upsteam and downstream of the target region. You will also need two 75 nt ‘Extender Primers’, which add 50 bp of homology to either end of the 100mer and will be used to generate the dsDNA substrate. b. For ...
... a. For deletions or small insertions, you will order an ~100 nt oligo with 50 nt of homology upsteam and downstream of the target region. You will also need two 75 nt ‘Extender Primers’, which add 50 bp of homology to either end of the 100mer and will be used to generate the dsDNA substrate. b. For ...
The Origin of the Jingwei Gene and the Complex Modular Structure
... Jingwei (jgw) is the first gene found to be of sufficiently recent origin in Drosophila to offer insights into the origin of a gene. While its chimerical gene structure was partially resolved as including a retrosequence of alcohol dehydrogenase (Adh), the structure of its non-Adh parental gene, the ...
... Jingwei (jgw) is the first gene found to be of sufficiently recent origin in Drosophila to offer insights into the origin of a gene. While its chimerical gene structure was partially resolved as including a retrosequence of alcohol dehydrogenase (Adh), the structure of its non-Adh parental gene, the ...
Cloning of PCR products into TOPO TA vectors
... amino acids to the α-subunit LacZ protein sequence, these extra amino acids surprisingly do not change it sufficiently to inactivate it. Neither the segment of LacZ encoded by the plasmid (the α-subunit) nor that encoded by E. coli is active alone. The polypeptides encoded by each region must associ ...
... amino acids to the α-subunit LacZ protein sequence, these extra amino acids surprisingly do not change it sufficiently to inactivate it. Neither the segment of LacZ encoded by the plasmid (the α-subunit) nor that encoded by E. coli is active alone. The polypeptides encoded by each region must associ ...
Document
... – usually results in increased association between the histone and the DNA and a decrease in transcription in that area – histone methylation is considered an epigenetic modification • alteration of gene expression by mechanisms outside of DNA structure • performed by a family of enzymes called hist ...
... – usually results in increased association between the histone and the DNA and a decrease in transcription in that area – histone methylation is considered an epigenetic modification • alteration of gene expression by mechanisms outside of DNA structure • performed by a family of enzymes called hist ...
RNA synthesis/Transcription I Biochemistry 302
... No independent 3′→5′ exonuclease activity but may have kinetic proofreading capabilities Two binding sites for ribonucleotides – Initiation site binds only purine rNTPs (GTP or ATP) with Kd = 100 µM…most mRNAs start with purine on 5′ end. – Elongation site binds any of 4 rNTPs with Kd = 10 µM. ...
... No independent 3′→5′ exonuclease activity but may have kinetic proofreading capabilities Two binding sites for ribonucleotides – Initiation site binds only purine rNTPs (GTP or ATP) with Kd = 100 µM…most mRNAs start with purine on 5′ end. – Elongation site binds any of 4 rNTPs with Kd = 10 µM. ...
Summary of lesson
... Cell respiration includes Glycolysis, the Krebs Cycle (sometimes called the “Citric Acid Cycle”) and the Electron Transport System (ETS). These pathways convert energy-rich sugar molecules into molecules that represent smaller units of energy. In this lesson, you’ll learn about the pathways of cellu ...
... Cell respiration includes Glycolysis, the Krebs Cycle (sometimes called the “Citric Acid Cycle”) and the Electron Transport System (ETS). These pathways convert energy-rich sugar molecules into molecules that represent smaller units of energy. In this lesson, you’ll learn about the pathways of cellu ...
Use the following information for the NEXT 3 QUESTIONS:
... population of these unusual dogs. Bunny and Cueball’s first litter has 6 yellowish-white pups and 2 pure white pups. You correctly predict that ___________. a) both dogs are homozygous for the pure white allele b) Cueball is homozygous for the pure white allele and Bunny is heterozygous c) both dogs ...
... population of these unusual dogs. Bunny and Cueball’s first litter has 6 yellowish-white pups and 2 pure white pups. You correctly predict that ___________. a) both dogs are homozygous for the pure white allele b) Cueball is homozygous for the pure white allele and Bunny is heterozygous c) both dogs ...
Newly found, `thrifty` genetic variant influences
... Samoans have a newly identified and significant genetic variant that contributes to obesity risk; a variant that had remained undiscovered until researchers focused on the islands' populations. In cell models in the lab, this "thrifty" variant promoted more efficient storage of more fat. ...
... Samoans have a newly identified and significant genetic variant that contributes to obesity risk; a variant that had remained undiscovered until researchers focused on the islands' populations. In cell models in the lab, this "thrifty" variant promoted more efficient storage of more fat. ...
2002-D-66-en-4
... understanding of biological principles and the learning of basic biological facts. b) The above balance should enable an average biology student who works well to easily obtain a 6 or a higher mark with extra effort. c) Each question should have a section to test basic knowledge and a section to tes ...
... understanding of biological principles and the learning of basic biological facts. b) The above balance should enable an average biology student who works well to easily obtain a 6 or a higher mark with extra effort. c) Each question should have a section to test basic knowledge and a section to tes ...
![Exam 3 ANSWER KEY Page 1 [10] 1. The proBA genes are required](http://s1.studyres.com/store/data/022831268_1-65a27ab890c110d79900531dcea4fd6a-300x300.png)
Exam 3 ANSWER KEY Page 1 [10] 1. The proBA genes are required
... chromosomal DNA at the insertion site. Both IS elements and transposons usually have indirect repeats at the ends of their sequence. The major difference is thus: • An IS element only encodes the gene products needed for transposition. • A Tn encoded the gene products needed for transposition and ad ...
... chromosomal DNA at the insertion site. Both IS elements and transposons usually have indirect repeats at the ends of their sequence. The major difference is thus: • An IS element only encodes the gene products needed for transposition. • A Tn encoded the gene products needed for transposition and ad ...
PCR Lecture - Woods Hole Oceanographic Institution
... Repeat unit 2-3 bp; nuclear; can get dozens of loci relatively easily; method of choice for parentage recombination; state characters; start-up time is great; issues of homoplasy in geographical studies; mutation must be taken into account in gene flow models ...
... Repeat unit 2-3 bp; nuclear; can get dozens of loci relatively easily; method of choice for parentage recombination; state characters; start-up time is great; issues of homoplasy in geographical studies; mutation must be taken into account in gene flow models ...
microRNA: microRNA
... To identify a possible molecular effect of the C->T substitution, vectors containing either the wild-type allele of the miR-15a–miR-16-1 cluster or the mutated allele were prepared. The 293 cells, were transfected with the vectors. ...
... To identify a possible molecular effect of the C->T substitution, vectors containing either the wild-type allele of the miR-15a–miR-16-1 cluster or the mutated allele were prepared. The 293 cells, were transfected with the vectors. ...
BIOL2165 - UWI St. Augustine - The University of the West Indies
... inversions and translocations can have profound effects on plants and animals including several genetic diseases of humans. All the multiple gene families that are responsible for things like immunity, expression of haemoglobin, and body architecture are a result of duplications. Furthermore most of ...
... inversions and translocations can have profound effects on plants and animals including several genetic diseases of humans. All the multiple gene families that are responsible for things like immunity, expression of haemoglobin, and body architecture are a result of duplications. Furthermore most of ...
presentation source (powerpoint)
... First we took the RNA from two mice, a healthy one and a diseased one. We then proceeded to use the RNA to make cDNA, an exact copy of the RNA except that it is in DNA form. Afterwards we embarked on the journey of cleaning the cDNA and inserting it into bacteria. ...
... First we took the RNA from two mice, a healthy one and a diseased one. We then proceeded to use the RNA to make cDNA, an exact copy of the RNA except that it is in DNA form. Afterwards we embarked on the journey of cleaning the cDNA and inserting it into bacteria. ...
Key concepts for Essay #1
... DNA ligase seals Okazaki fragments together DNA polymerase proof-reads the new strands ...
... DNA ligase seals Okazaki fragments together DNA polymerase proof-reads the new strands ...
Identification of Genes Overexpressed in Tumors
... phocytes (Lane 3) were hybridized with 32P-labeled probes for selected cDNA clones from the subtracted library. The autoradiographs were obtained after expo sure with an intensifying screen at —80°C for 3 days with probes B9 and E9 and 2 days with probe E4. The probe used is indicated above each ...
... phocytes (Lane 3) were hybridized with 32P-labeled probes for selected cDNA clones from the subtracted library. The autoradiographs were obtained after expo sure with an intensifying screen at —80°C for 3 days with probes B9 and E9 and 2 days with probe E4. The probe used is indicated above each ...
Genetics
... 26. In garden peas, a single gene controls stem length. The recessive allele (t) produces short stems when homozygous. The dominant allele (T) produces long stems. A short stemmed plant is crossed with a heterozygous long stemmed plant. Which of the following represents the expected phenotypes of th ...
... 26. In garden peas, a single gene controls stem length. The recessive allele (t) produces short stems when homozygous. The dominant allele (T) produces long stems. A short stemmed plant is crossed with a heterozygous long stemmed plant. Which of the following represents the expected phenotypes of th ...
