
Topological Vector Spaces.
... The reason is that A + U is the union of the translates a + U , with a running over A, and each translate a + U is an open set. If A and B are subsets of a vector space V then we shall write A − B to mean the set of all a − b, with a running over a and b running over B. The set difference of A and B ...
... The reason is that A + U is the union of the translates a + U , with a running over A, and each translate a + U is an open set. If A and B are subsets of a vector space V then we shall write A − B to mean the set of all a − b, with a running over a and b running over B. The set difference of A and B ...
3. The Sheaf of Regular Functions
... After having defined affine varieties, our next goal must be to say what kind of maps between them we want to consider as morphisms, i. e. as “nice maps preserving the structure of the variety”. In this chapter we will look at the easiest case of this: the so-called regular functions, i. e. maps to ...
... After having defined affine varieties, our next goal must be to say what kind of maps between them we want to consider as morphisms, i. e. as “nice maps preserving the structure of the variety”. In this chapter we will look at the easiest case of this: the so-called regular functions, i. e. maps to ...
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... Let (X, T ) be a topological space. A subset B of T is a basis for T if every member of T is a union of members of B. Equivalently, B is a basis if and only if whenever U is open and x ∈ U then there is an open set V ∈ B such that x ∈ V ⊆ U . The topology generated by a basis B consists of exactly t ...
... Let (X, T ) be a topological space. A subset B of T is a basis for T if every member of T is a union of members of B. Equivalently, B is a basis if and only if whenever U is open and x ∈ U then there is an open set V ∈ B such that x ∈ V ⊆ U . The topology generated by a basis B consists of exactly t ...